xquery-sql

I have an XML hierarchy like this in an XML type column of a table with 10,000 records- <Root> <Elem1> <Parent1> <Separator> <Child1/> </Separator> </Parent1> </Elem1> </Root> I have a query like this - DECLARE @Root VARCHAR(50) DECLARE @Entity VARCHAR(50) DECLARE @ParentNode VARCHAR(50) DECLARE @Separator VARCHAR(50) DECLARE @ChildNode VARCHAR(50) SET @Root = 'Root' SET @Entity = 'Elem1' SET @ParentNode = 'Parent1' SET @Separator = 'separator' SET @ChildNode = 'Child1' select Parent.P.value('.', 'varchar(max)') as MyValue, T.uniqueId, T.XMLCol from [XMLTable] as T cross apply (SELECT XMLTable

I am having a hard time trying to parse an XML that has some namespaces defined: <TravelItineraryReadRS xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" Version="2.2.0"> <TravelItinerary xmlns="http://webservices.sabre.com/sabreXML/2011/10"> <CustomerInfo> <PersonName WithInfant="false" NameNumber="01.01" RPH="1"> <GivenName>JEFF S</GivenName>" The XMl is stored in an XML type column named response, and I want to get the GivenName value, for which I use the below query: ;WITH XMLNAMESPACES (DEFAULT 'http://webservices.sabre.com/sabreXML/2011/10

I have a large XML note with many nodes. is there a way that I can select only a single node and all of its contents from the larger XML? i am using sql 2005 You should use the query() Method if you want to get a part of your XML. declare @XML xml set @XML = ' <root> <row1> <value>1</value> </row1> <row2> <value>2</value> </row2> </root> ' select @XML.query('/root/row2') Result: <row2> <value>2</value> </row2> If you want the value from a specific node you should use value() Method . select @XML.value('(/root/row2/value)[1]', 'int') Result: 2 Update: If you want to shred your XML to multiple

I have this variable: declare @xmlDoc XML it has the following xml stored in it: <?xml version="1.0" encoding="utf-8"?> <NewDataSet> <Table1> <Sharedparam>shared</Sharedparam> <Antoher>sahre</Antoher> <RandomParam2>Good stuff</RandomParam2> <MoreParam>and more</MoreParam> <ResultsParam>2</ResultsParam> </Table1> <Table1> <RandomParam2>do you</RandomParam2> <MoreParam>think</MoreParam> <ResultsParam>2</ResultsParam> </Table1> <Table1> <Sharedparam>Last</Sharedparam> <Antoher> Set </Antoher> <RandomParam2> of </RandomParam2> <MoreParam>values</MoreParam> <ResultsParam>are here</ResultsParam> <

How can get the XML with sorted attributes using XQuery in SQL? for example for this XML: <root><book b='' c='' a=''/></root> must return: <root><book a='' b='' c=''/></root> From Limitations of the xml Data Type . The order of attributes in an XML instance is not preserved. When you query the XML instance stored in the xml type column, the order of attributes in the resulting XML may be different from the original XML instance. So even if you could figure out a way of sorting the attributes, you can not trust that the XML data type in SQL Server will preserve the order you want. Attributes