xml

XPath query with xmlstarlet

由 荒凉一梦 提交于 2021-02-19 03:42:34
问题 I have XML similar to this one: <orders> <orderCompleteRequestType> <Head> <Aufnr>11111</Aufnr> </Head> <Register> <Id>180</Id> <value1>11</value1> <value2>22</value2> </Register> <Register> <Id>181</Id> <value1>3</value1> <value2>43</value2> </Register> <Register> <Id>160</Id> <value1>5</value1> <value2>25</value2> </Register> </orderCompleteRequestType> <orderCompleteRequestType> <Head> <Aufnr>22222</Aufnr> </Head> <Register> <Id>280</Id> <value1>1</value1> <value2>12</value2> </Register>

Spring config xml isn't valid after adding spring-data-jpa schema references

由 て烟熏妆下的殇ゞ 提交于 2021-02-19 03:34:09
问题 I have the following Exception while starting the spring context: java.lang.Exception: java.lang.IllegalStateException: ContainerBase.addChild: start: org.apache.catalina.LifecycleException: org.apache.catalina.LifecycleException: org.xml.sax.SAXParseException; systemId: http://www.springframework.org/schema/data/jpa/; lineNumber: 1; columnNumber: 55; White spaces are required between publicId and systemId. Before I added the spring-data-jpa to the spring config.xml everything worked fine.

Reference String Resource in custom XML Resource

由 馋奶兔 提交于 2021-02-19 02:24:28
问题 In the assets folder of my Android App Project I am storing custom XML files which describe actions in my game. Since they are a little more complex, they can not be directly written as Android Resources. Update: I am storing my custom (complex) XML files in the res/xml folder now. Simple Example: <dialog> <npc>1</npc> <text>Hello! How are you?</text> </dialog> What I want is to use the convenient advantages of Android String resources for language localisation. In the example above, I want

Can I update an XML node value using a variable in VBA

由 核能气质少年 提交于 2021-02-19 02:00:08
问题 I am a complete newcomer to learning about XML but OK with VBA in Excel 2010. In Excel VBA I have created a simple CustomXMLPart with 5 nodes under a single root, akin to the example below: < <RefTest> <sRef1>SomeText</sRef1> 'text <sRef2>XYZ234</sRef2> 'text <sRef3>ABC123</sRef3> 'text <dRef4>25/02/1953</dRef4> 'date or text? <iRef5>0</iRef5> 'numeric or text? </RefTest> > This works OK and I can read the values back-in using VBA. My problem is that the node values (at the moment) are

Should I be using XSD 1.1 to build an open standard?

由 独自空忆成欢 提交于 2021-02-19 00:55:09
问题 We have been asked to put together a set of schemas for an open XML standard. XSD 1.0 would cope with most of the rules, but it would be a bit messy in places (especially to allow for extensibility) it would also rely on implementers reading free text descriptions of some rules in the form of annotations. Pretty much all of the rules could be implemented using XSD 1.1, however we are not sure if this would limit implementers unduly. So my question, is XSD 1.1 mature enough to be used in the

Mapping XML to classes in c#

由 僤鯓⒐⒋嵵緔 提交于 2021-02-18 23:30:51
问题 I'm looking to map multiple XML attributes in nested elements into a single POCO class using the XmlSerializer object. XML <products grand-total="100"> <one price="50" /> <two price="20" /> <tree price="30" /> </products> POCO public class Product { public int GrandTotal { get; set; } public int OnePrice { get; set; } public int TwoPrice { get; set; } public int ThreePrice { get; set; } } C# var doc = XDocument.Load("XmlDoc.xml"); var serializer = new XmlSerializer(typeof(Product)); var

It's possible define bean stereotypes via XML?

由 允我心安 提交于 2021-02-18 18:51:57
问题 It's possible, via XML, define a bean stereotype? Something as: <bean ... stereotype="org.springframework.stereotype.Service"> </bean> or, <bean...> <stereotype class="mypackage.myStereotype" /> </bean> ? 回答1: Probably the easiest solution would be to use arbitrary spring bean metadata as follows: <bean id="fooService" class="org.example.FooServiceImpl"> <meta key="stereotype" value="mypackage.myStereotype" /> </bean> The definition of the meta element in spring-beans.xsd is: <xsd:complexType

How to configure persistence.xml provider tag

由 萝らか妹 提交于 2021-02-18 18:14:41
问题 Hey I'm learning this stuff, I don't really understand all of it and I have a problem, I don't know what to write in provider tag in persistence.xml Here are my persistence.xml and pom.xml files: pom.xml <?xml version="1.0" encoding="UTF-8"?> <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>com

How to configure persistence.xml provider tag

由 北城余情 提交于 2021-02-18 18:14:09
问题 Hey I'm learning this stuff, I don't really understand all of it and I have a problem, I don't know what to write in provider tag in persistence.xml Here are my persistence.xml and pom.xml files: pom.xml <?xml version="1.0" encoding="UTF-8"?> <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>com

XSLT with overlapping elements?

由 不打扰是莪最后的温柔 提交于 2021-02-18 17:13:26
问题 So the title of this post may be a little misleading, but it's the best I can come up with. I'm working on a project that uses TEI for encoding texts. One of the requirements of my current work is to write XSL transformations to render the XML-encoded texts as HTML. For the most part, no problem. I'm kind of stuck on this issue, though: <l>There is <delSpan spanTo="A1"/>deleted text spanning</l> <l>multiple lines here.<anchor xml:id="A1"/> More text...</l> Or, in other instances: <delSpan
订阅 xml