xml-deserialization

How to deserialize Nullable<bool>? [duplicate]

由 跟風遠走 提交于 2020-05-28 02:23:50
问题 This question already has answers here : Deserializing empty xml attribute value into nullable int property using XmlSerializer (4 answers) Closed 2 years ago . I am trying to deserialize a Nullable<bool> from my XML file. My expectation was that a XMLAttribute which was not found in my XMLElement is null and if it's found it will be true or false . Same for serialization. My variable will be written if it's not null. Anyways, everytime I'm trying to deserialize my XML an

How to deserialize xml with jaxb using builder class

由 痴心易碎 提交于 2020-04-30 09:17:21
问题 I want to deserialize xml with Jaxb and using builder class Below is my xml input <Test> <Head>Hey</Head> <Message code="MNP">[Hey How are yu] <care>test2</care> <care>test1</care> </Message> </Test> This Xml has mixed content. Below is classes which I used to deserialize: @XmlRootElement(name = "Test") public class Test { private final String header; private final List<Message> message; private Test(final Builder builder) { this.header = builder.header.orElse(null); this.message = builder

How to deserialize xml with jaxb using builder class

由 时光怂恿深爱的人放手 提交于 2020-04-30 09:17:06
问题 I want to deserialize xml with Jaxb and using builder class Below is my xml input <Test> <Head>Hey</Head> <Message code="MNP">[Hey How are yu] <care>test2</care> <care>test1</care> </Message> </Test> This Xml has mixed content. Below is classes which I used to deserialize: @XmlRootElement(name = "Test") public class Test { private final String header; private final List<Message> message; private Test(final Builder builder) { this.header = builder.header.orElse(null); this.message = builder

Android SimpleXML Deserialisation

由 ﹥＞﹥吖頭↗ 提交于 2020-04-18 06:32:31
问题 I am trying to create node & edge objects from this graphml. I had some great advice that told me to use several packages, on further research, with it being an android implementation I went for simplexml. http://simple.sourceforge.net/download/stream/doc/tutorial/tutorial.php#nested I am starting with the nodes. I have created my node class: @Root(name="node") public class DeserialisedNode implements Serializable { public DeserialisedNode() { super(); } @Attribute(name = "id") private int iD

VB.Net Xml Deserialization into a Class

由 我是研究僧i 提交于 2020-03-02 10:16:11
问题 I have a bit of an issue trying to deserialize some XML into a class that I have created. The error I get is: There is an error in XML document (1, 2). at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle, XmlDeserializationEvents events) at System.Xml.Serialization.XmlSerializer.Deserialize(TextReader textReader) at CommonLayer.InvuManager.FindDocuments(String policy, String year) in C:\GIT\novus\CommonLayer\InvuManager.vb:line 194 at Novus

VB.Net Xml Deserialization into a Class

由 荒凉一梦 提交于 2020-03-02 10:15:10
问题 I have a bit of an issue trying to deserialize some XML into a class that I have created. The error I get is: There is an error in XML document (1, 2). at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle, XmlDeserializationEvents events) at System.Xml.Serialization.XmlSerializer.Deserialize(TextReader textReader) at CommonLayer.InvuManager.FindDocuments(String policy, String year) in C:\GIT\novus\CommonLayer\InvuManager.vb:line 194 at Novus

how to read xml attribute using C# classes using deserialization

由 血红的双手。 提交于 2020-02-22 05:13:49
问题 Below is My XML File : <Visibilities> <Visibilities AppName="Test2"> <Visibility DisplayName="Full Name"> <FullName> <FirstName PropertyName="FullName.FirstName" DisplayName="First Name" ListOrder="3"></FirstName> <MiddleName PropertyName="FullName.MiddleName" DisplayName="Middle Name" ListOrder="2"></MiddleName> <LastName PropertyName="FullName.LastName" DisplayName="Last Name" ListOrder="1"></LastName> </FullName> </Visibility> </Visibilities> </Visibilities> Below are my classes #region

how to read xml attribute using C# classes using deserialization

由 泄露秘密 提交于 2020-02-22 05:13:47
问题 Below is My XML File : <Visibilities> <Visibilities AppName="Test2"> <Visibility DisplayName="Full Name"> <FullName> <FirstName PropertyName="FullName.FirstName" DisplayName="First Name" ListOrder="3"></FirstName> <MiddleName PropertyName="FullName.MiddleName" DisplayName="Middle Name" ListOrder="2"></MiddleName> <LastName PropertyName="FullName.LastName" DisplayName="Last Name" ListOrder="1"></LastName> </FullName> </Visibility> </Visibilities> </Visibilities> Below are my classes #region

how to read xml attribute using C# classes using deserialization

由 独自空忆成欢 提交于 2020-02-22 05:13:40
问题 Below is My XML File : <Visibilities> <Visibilities AppName="Test2"> <Visibility DisplayName="Full Name"> <FullName> <FirstName PropertyName="FullName.FirstName" DisplayName="First Name" ListOrder="3"></FirstName> <MiddleName PropertyName="FullName.MiddleName" DisplayName="Middle Name" ListOrder="2"></MiddleName> <LastName PropertyName="FullName.LastName" DisplayName="Last Name" ListOrder="1"></LastName> </FullName> </Visibility> </Visibilities> </Visibilities> Below are my classes #region

how to read xml attribute using C# classes using deserialization

由 ℡╲_俬逩灬. 提交于 2020-02-22 05:13:31
问题 Below is My XML File : <Visibilities> <Visibilities AppName="Test2"> <Visibility DisplayName="Full Name"> <FullName> <FirstName PropertyName="FullName.FirstName" DisplayName="First Name" ListOrder="3"></FirstName> <MiddleName PropertyName="FullName.MiddleName" DisplayName="Middle Name" ListOrder="2"></MiddleName> <LastName PropertyName="FullName.LastName" DisplayName="Last Name" ListOrder="1"></LastName> </FullName> </Visibility> </Visibilities> </Visibilities> Below are my classes #region
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