word-boundary

问题 I'm using regex word boundary \b, and I'm trying to match foo in the following $sentence but the result is not what I need, the underscore is killing me, I want underscore to be word boundary just like hyphen or space: $sentence = "foo_foo_foo foo-foo_foo"; X X X YES X X Expected: $sentence = "foo_foo_foo foo-foo_foo"; YES YES YES YES YES YES My code: preg_match("/\bfoo\b/i", $sentence); 回答1: You would have to create DIY boundaries. (?:\b|_\K)foo(?=\b|_) 回答2: Does this do what you want?: preg

问题 I want to replace string which is a square bracket with another number. I am using regex replace method. Sample input: This is [test] version. Required output (replacing "[test]" with 1.0): This is 1.0 version. Right now regex is not replacing the special character. Below is the code which I have tried: string input= "This is [test] version of application."; string stringtoFind = string.Format(@"\b{0}\b", "[test]"); Console.WriteLine(Regex.Replace(input, stringtoFind, "1.0")); There may be

问题 I want to replace string which is a square bracket with another number. I am using regex replace method. Sample input: This is [test] version. Required output (replacing "[test]" with 1.0): This is 1.0 version. Right now regex is not replacing the special character. Below is the code which I have tried: string input= "This is [test] version of application."; string stringtoFind = string.Format(@"\b{0}\b", "[test]"); Console.WriteLine(Regex.Replace(input, stringtoFind, "1.0")); There may be

问题 I am working on a solution to split long lines of Khmer (the Cambodian language) into individual words (in UTF-8). Khmer does not use spaces between words. There are a few solutions out there, but they are far from adequate (here and here), and those projects have fallen by the wayside. Here is a sample line of Khmer that needs to be split (they can be longer than this): ចូរសរសើរដល់ទ្រង់ដែលទ្រង់បានប្រទានការទាំងអស់នោះមកដល់រូបអ្នកដោយព្រោះអង្គព្រះយេស៊ូវ

问题 Regex: \b< low="" number="" low="">\b Example string: <b22>Aquí se muestran algunos síntomas < low="" number="" low=""> tienen el siguiente aspecto.</b22> I'm not sure why the word boundary between síntomas and < is not being found. Same problem exists on the other side between > and tienen Suggestions on how I might more properly match this boundary? When I give it the following input, the Regex matches as expected: Aquí se muestran algunos síntomas< low="" number="" low="">tienen el

问题 Following this question and answer, I still have a bit trouble in the result I get, For instance, REGEXP '>[^<]*lau[[:>:]]' will match ' lau ' only but not ' laurence ' which is correct. REGEXP '>[^<]*men[[:>:]]' will match ' empowerment ' and ' women ' which are not what I am after. REGEXP '( |>|$)home( |<|$)' will match ' home ' only but not ' home! ' which it should . How can match these correctly? For instance, Home - match HOME - match welcome home! - match home is far! - match hometown

问题 I'm trying to implement word boundaries in my emoticons feature for a chat. But for some reason I can't seem to get the word boundaries to work. I am new to regex. So when I do: var reg = /\b\Hi\b/gi; var str = 'HiHiHi Hi HiHiHi Hi'; alert(str.replace(reg, '')); This happens: Jsfiddle It actually works fine, and does remove those 2 Hi's that are standing alone. But when I change the reg to an escaped smiley and then change the string: var reg = /\b\:\)\b/gi; var str = 'HiHi:) :) HiHiHi :)';

问题 I have a regular expression using word boundaries that works exceedingly well... ~\b('.$value.')\b~i ...save for the fact that it matches text inside HTML tags (i.e. title="This is blue!" ). It's a problem because I'm doing text substitution on anything the regex matches, then making tooltips appear using those title tags. So, as you can imagine, it's substituting text inside the title and breaking the HTML of the tooltip. For example, what should be: <span class="blue" title="This is blue!"

问题 Hi I have the following code which is meant to find the word "is" but not when it is within another string so the word "this" should not return a match so I use \b. But the following code does not find a match and I cant figure out why? public static void main(String[] args) { String a = "This island is beautiful."; Pattern p = Pattern.compile("\bis\b"); Matcher m = p.matcher(a); while(m.find()){ System.out.println(a.substring(m.start(), m.end())); } } 回答1: Double escape it: Pattern p =

问题 I'm getting unexpected results with this code: 'foo'.match(new RegExp('\bfoo\b')); // Returns null Why is this returning null while this one returns "foo"? 'foo'.match(new RegExp('foo')); // Returns "foo" Doesn't a word boundary marker match the beginning and end as well? EDIT: I need the regular expression itself to be a string because I am injecting variables into it. 回答1: Escape the backslashes 'foo'.match(new RegExp('\\bfoo\\b')); 回答2: Don't wrap it in quotes... instead, do this:- 'foo'