weekend

问题 For a simple time series: import pandas as pd df = pd.DataFrame({'dt':['2020-01-01', '2020-01-02', '2020-01-04', '2020-01-05', '2020-01-06'], 'foo':[1,2, 4,5,6]}) df['dt'] = pd.to_datetime(df.dt) df['dt_label']= df['dt'].dt.strftime('%Y-%m-%d %a') df = df.set_index('dt') #display(df) df['foo'].plot() x =plt.xticks(ticks=df.reset_index().dt.values, labels=df.dt_label, rotation=90, horizontalalignment='right') How can I highlight the x-axis labels for weekends? edit Pandas Plots: Separate color

问题 We are using quartz for scheduling the batch jobs. We are trying to apply weekend or holiday strategy for the job triggers. Looking at the quartz implementation, it was easy to implement weekend strategy using calendar(s), however for holiday implementation. If holiday(s) are defined well in advance before the job creation, it would be easy to handle along with weekend(s) in custom calendars. But, if holidays can be created dynamically, and the strategy to be applied at runtime, I thought it

问题 I want to calculate the number of weekdays days in a give month and year. Weekdays means monday to friday. How do i do it ? 回答1: Some basic code: $month = 12; $weekdays = array(); $d = 1; do { $mk = mktime(0, 0, 0, $month, $d, date("Y")); @$weekdays[date("w", $mk)]++; $d++; } while (date("m", $mk) == $month); print_r($weekdays); Remove the @ if your PHP error warning doesn't show notices. 回答2: You don't need to count every day in the month. You already know the first 28 days contain 20

问题 My data looks like this for one column: Date AED.USD 03/01/2005 3.6726 04/01/2005 3.6726 05/01/2005 3.6725 06/01/2005 3.6726 07/01/2005 3.6725 08/01/2005 NA 09/01/2005 NA 10/01/2005 3.6726 11/01/2005 3.6725 12/01/2005 3.6726 13/01/2005 3.6725 14/01/2005 3.6726 15/01/2005 NA 16/01/2005 NA 17/01/2005 3.6725 18/01/2005 3.6726 19/01/2005 3.6725 20/01/2005 3.6725 21/01/2005 3.6725 I want to remove the dates with the weekends, I have tried using x <- seq(as.Date("2005-01-03"),as.Date("2016-11-30")

问题 How can I find the difference between two dates in DB2 (excluding weekends)? Are there any functions that will do this in DB2? Or do I need to write a query myself? 回答1: There is AFAIK no such function. It is however easy to write a query that calculates this: with cal(d) as ( values date('2015-01-01') -- start_date union all select d + 1 day from cal where d < '2015-01-15' -- end_date ) select count(case when dayofweek(d) between 2 and 6 then 1 end) from cal; If you do a lot of these kind of

问题 Using NetSuite, I am trying to automate the creation of monthly tasks. These tasks will fall on the last day of the month, a day before, and 1,2,3,4,5 days after the last day of the month. But, the tasks can't be due on a weekend, only business days. So if the day falls on a sat or sun the dates have to move up. How can I use my custom record to calculate the next months task dates skipping weekends? Here is a screenshot of the record - see that 10/4 and 10/5 fall on saturday and sunday, how

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 5 years ago . I am just wondering if there is a simple way or framework to to get all weekends within date range in C#? Is it possible to do with LINQ as well? Any clue? Thank you! 回答1: If you make a way to enumerate all days, you can use linq to filter to weekends: IEnumerable<DateTime>

问题 I am trying to add hours to a date but want the new date to exclude weekends and only be between 9.00 to 17.00. example: first scenario: if my date is 23/02/2012 16:00:00. if I add 4 hours to that my new date should be 24/02/2012 12:00:00 (which will be within working hours) second scenario: if my date is 24/02/2012 09:00:00 (which is a friday) if I add 24 hours then the new date should be 27/02/2012 09:00:00 (which would be monday next week at 9am) so far I got this but am stuck as this will

问题 I'm trying to get the dates within a given month. My plan is to Get the start and the end dates of a given month,. Get all the dates that fall within that range. Iterate through them and eliminate dates that fall within a weekend using the isDateInWeekend method. The remaining dates are the weekdays. So I created two NSDate extension methods to get the start and the end dates of the month. extension NSDate { var startOfMonth: NSDate { let calendar = NSCalendar.currentCalendar() let components

问题 I am using this code to calculate the difference between two dates ignoring weekends: SELECT To_date(SYSDATE) - To_date('01.07.2014', 'DD.MM.YYYY') - 2 * ( TRUNC(Next_day(To_date(SYSDATE) - 1, 'FRI')) - TRUNC( Next_day(To_date('01.07.2014' , 'DD.MM.YYYY') - 1, 'FRI')) ) / 7 AS DAYS_BETWEEN FROM dual I have another table called table1 in which the column "date" exists (its type is "DATE") in which all dates where a holiday is are written down. Example table 1: DATES 12.06.2011 19.06.2014 09.05