visual-paradigm

Wrap conditional into a function or not represent it at all in a sequence diagram?

由 落爺英雄遲暮 提交于 2019-12-25 03:33:02
问题 I've this PHP controller class (belongs to Symfony2 bundle): class ReptoolController extends PageController { // ... private function _get($request, $action, $case) { $app_id = $this->getRequested('app_id'); if( ( $repappConfig = $this->getDoctrine()->getRepository('PDOneBundle:RepappConfig')->findOneBy(array("app_id"=>$app_id))) ) { $current_timestamp = new \DateTime(date('Y-m-d')); if($repappConfig->getExpireDate()) $expire_date = $repappConfig->getExpireDate()->getTimestamp(); else { $temp

Interface Class relationship in visual paradigm

由 梦想与她 提交于 2019-12-14 03:54:58
问题 I have been working on this for quite few time but could not find a way to denote the relationship between a class and an interface that is implemented by class in an UML diagram. Can someone help me in the above problem? My interface and class has following relationship interface foo { void a(); void b(); } class goo : foo { public override void a() { //Code goes here } } Can you please tell me what to use in visual paradigm to show there relationship? 回答1: It is shown like inheritance. This

What does the dot mean at the end of an association?

由 情到浓时终转凉″ 提交于 2019-12-10 15:33:26
问题 I reversed some Java code to get a uml class diagram using Visual Paradigm. The diagram shows some associations with little black circles on one end, which I never saw before. Image It's definitely not a composition and not a containment! Can anybody explain to me, what kind of association this is? Here's the related code: public class DataAdapter extends RecyclerView.Adapter<DataAdapter.ViewHolder> { public static final String TAG = DataAdapter.class.getSimpleName(); private static Context

UML generalization and realization

由 冷暖自知 提交于 2019-12-01 18:09:55
问题 I am pretty new to UML, so I have some questions about Generalization and Realization. I am modeling the behavior of an electronic microcontroller and I need to generate C++ code from the UML description. As far as I know, a class realizes an interface, that means it may provide the implementation of an interface. A generalization relationship may exist between two classes. In that case the derived class inherits all the members of the base class and gains access to public and protected

UML generalization and realization

由 限于喜欢 提交于 2019-12-01 17:44:54
I am pretty new to UML, so I have some questions about Generalization and Realization. I am modeling the behavior of an electronic microcontroller and I need to generate C++ code from the UML description. As far as I know, a class realizes an interface, that means it may provide the implementation of an interface. A generalization relationship may exist between two classes. In that case the derived class inherits all the members of the base class and gains access to public and protected members. Here is my question (I am using Visual Paradigm as modeling tool). Let us assume we have a module

Setting the association end ownership in UML: What does it mean with respect to generated code in visual paradigm (or in other UML tools)?

由 扶醉桌前 提交于 2019-12-01 05:40:34
问题 What is the effect of setting the association end ownership from "association" to "classifier" on the code that gets generated? In other words, 0) I start with an empty diagram 1) I create class A and class B 2) I connect A and B with an association A-B 3) the association end at A is named as a 4) the association end at B is named as b 5) the association end ownership for a is set to class B (by default it is set to the association A-B itself) 6) I generate Java code for this diagram How and
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