Why is the ELF execution entry point virtual address of the form 0x80xxxxx and not zero 0x0?
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问题 When executed, program will start running from virtual address 0x80482c0. This address doesn\'t point to our main() procedure, but to a procedure named _start which is created by the linker. My Google research so far just led me to some (vague) historical speculations like this: There is folklore that 0x08048000 once was STACK_TOP (that is, the stack grew downwards from near 0x08048000 towards 0) on a port of *NIX to i386 that was promulgated by a group from Santa Cruz, California. This was