user-input

问题 I am learning C++ using the book C++ Primer. In Section 1.4.3 , the following example code about reading the unknown number of inputs is given. #include <iostream> int main() { int sum = 0, value = 0; // read until end-of-file, calculating a running total of all values read while (std::cin >> value) sum += value; // equivalent to sum = sum + value std::cout << "Sum is: " << sum << std::endl; return 0; } According to the book, if we give an input of 3 4 5 6 , the output will be Sum is: 18 But

问题 I'm working on building out a set of common SASS mixins. Some of these mixins have 5-10 variables, all with default values. I'd like a way to check whether a user has input values - not the variable contents, but whether there has been an actual user input. For example, in the following mixin: @mixin backdrop($color: #000) { background-color: $color; } If a user, in their own code, calls: @include backdrop(#000); There should be no warning. Even though they have input the same value as the

问题 I have a program that is displaying a barchart of results. I want to wait until the user closes the bar chart to continue to the next line of code which is asking if they want to enter new information for the chart. Scene scene = BarGraph.getBarChart(); primaryStage.setScene(scene); primaryStage.setTitle("Bar Chart"); primaryStage.show(); repeat = JOptionPane.showConfirmDialog(null, "Would you like to enter another number?"); What is happening is the scene for the bar chart will open, but

问题 I have to use a provided script that takes user input while the script is running instead of parameters. I can't get around this. An example of script would be: #!/bin/bash echo "param one" read one doSomething echo "param two" read two doSomething echo "param three" read three doSomething echo "param four" read four doSomething echo "param five" read five doSomething I would like a way to be able to call this script and provide parameterized input, something like: ./scriptNameWrapper.ksh 1

问题 I'm working in Drupal, got CKEditor set up and have the tables plugin going on. The design I'm working with requires some visual elements that would be made A LOT easier if I had a div with a class wrapped around the tables in the output (because tables can't have padding on their sides in IE)... SO.. I'm can think of 2 ways to do it, but don't know and can't figure out how to do either: 1)Use CKEditor to wrap all table elemnts in a div with a class.. 2)Use Drupal input filter to wrap all

问题 I'm trying to create a simple temperature conversion program that allows the user to convert temperatures as many times as they want until they decide to end the program by entering the letter 'e'. Everything else in the code works except the part where the user enters the letter 'e'. If I take the last else statement out, the program just starts at the beginning of the loop again. If I leave the else statement in, when the user enters the letter 'e', the else statement thinks that it is

问题 I am trying to implement a simple yes/no script. A function runs, then the user is prompt to input whether or not to run it again. If the user inputs "y", then the procedure should repeat. If the user inputs "n", then the procedure should terminate. If neither, then the question should repeat. Here is my code: function func(i) { console.log(i); ask(i + 1); } function ask(i) { process.stdout.write("again (y/n)?"); process.stdin.on("data", function(data) { process.stdin.end(); if (data.toString

问题 Story so far..... I want to learn JQuery, and im also building an MVC ASP.NET Apps which requires a "search as you type" search function - perfect to learn JQuery as well! So far (with the help of stackoverflowers ) I have managed to get the AJAX/JSON bit. Now I want to evaluate each key press and validate it against the JSON Array which was created as an unordered list. What im trying to achieve is to only show the account numbers in the list that contain what is inputted. So, my reasoning

问题 I am solving this question. This is my code: import java.io.IOException; import java.util.Scanner; public class Main { public static void main(String[] args) throws IOException { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int k = sc.nextInt(); int[] t = new int[n]; int count = 0; for (int i = 0; i < n; i++) { t[i] = sc.nextInt(); if (t[i] % k == 0) { count++; } } System.out.println(count); } } But when I submit it, it get's timed out. Please help me optimize this to as much as

问题 This is a short excerpt from a bigger program, but the rest of the program is irrelevant since I think I was able to isolate the issue. I suspect that it has something to do with the way I'm using fgets. I've read that it's preferable to use fgets over scanf, but I can't seem to get it to work properly here. When I use the following code, the program doesn't give me a chance to enter the number (but simply skips to the while loop which checks if the number entered is in the correct range):