urldecode

How to decode “\\u0026” in a URL?

核能气质少年 提交于 2019-12-05 05:05:44
I want decode URL A to B : A) http:\/\/example.com\/xyz?params=id%2Cexpire\u0026abc=123 B) http://example.com/xyz?params=id,expire&abc=123 This is a sample URL and I look for a general solution not A.Replace("\/", "/")... Currently I use HttpUtility.UrlDecode(A, Encoding.UTF8) and other Encodings but cannot generate URL B ! You only need this function System.Text.RegularExpressions.Regex.Unescape(str); This is a basic example I was able to come up with: static void Sample() { var str = @"http:\/\/example.com\/xyz?params=id%2Cexpire\u0026abc=123"; str = str.Replace("\\/", "/"); str =

Jquery reading several array parameters from url

点点圈 提交于 2019-12-04 23:08:48
I have the following URL: http://mydomain/Forwards?searchValue[]=Nike+Webstore&searchValue[]=Bodyman&category_filter[]=Animals+%26+Pet+Supplies&category_filter[]=Fashion&country_filter[]=Aland+Islands&country_filter[]=American+Samoa This url contains alot of paramters that are sent as an array: Now i wish to get each individual array and its value out in the above example the result should be something like this: searchValue = array( [0] = 'Nike Webstore' [1] = 'Bodyman' ); category_filter = array( [0] = 'Animals & Pet Supplies' [1] = 'Fashion' ); country_filter = array( [0] = 'Aland Islands'

swift removingPercentEncoding not work with a gb2312 string

天大地大妈咪最大 提交于 2019-12-04 21:06:19
The server returns a gb2312 string that has been processed by the urlencode function: %D7%CF%BD%FB%B3%C7%C4%A7%D6%E4_%CE%DE%CF%DE%D0%A1%CB%B5%CD%F8_www.55x.cn.rar How to decode it back to gb2312 string: 紫禁城魔咒_无限小说网_www.55x.cn.rar Percent encoding on other encodings than UTF-8 is not considered to be a recommended way in recent www world, so you may need to implement such conversion by yourself. It may be something like this: extension String.Encoding { static let gb_18030_2000 = String.Encoding(rawValue: CFStringConvertEncodingToNSStringEncoding(CFStringEncoding(CFStringEncodings.GB_18030_2000

java how to decode get url parameter received throw BeanParam

守給你的承諾、 提交于 2019-12-04 00:00:42
问题 I receive a GET response to this web service @GET @Path("/nnnnnn") public Response pfpfpfpf(@BeanParam NNNNNN n) The class NNNNN has: @QueryParam("parameter") private String parameter; And for that parameter there is a get and set. I send a request on a get with a query parameter and it is being bind automatically to my option NNNNN, everything is great. but, now i am sending Japanese strings in the query url. I encode the paramter by UTF-8 before sending, and I have to decode them using UTF

How to “URL decode” a string in Emacs Lisp?

只谈情不闲聊 提交于 2019-12-03 22:21:44
I've got a string like "foo%20bar" and I want "foo bar" out of it. I know there's got to be a built-in function to decode a URL-encoded string (query string) in Emacs Lisp, but for the life of me I can't find it today, either in my lisp/ folder or with google. Anybody remember what it's called? org-link-unescape does the job for very simple cases ... w3m-url-decode-string is better, but it isn't built in and the version I have locally isn't working with Emacs 23. url-unhex-string In my case I needed to do this interactively. The previous answers gave me the right functions to call, then it was

Does VBA have any built in URL decoding?

流过昼夜 提交于 2019-12-03 18:05:50
问题 I just need to decode a URL, for example, replace %2E with . I can hack out a method if one isn't build in, but my assumption is that there must be a URL decoding tool already existing. 回答1: No. But here's one: URL Encoder and Decoder for VB Or something along the lines of (possibly not complete): Public Function URLDecode(ByVal strEncodedURL As String) As String Dim str As String str = strEncodedURL If Len(str) > 0 Then str = Replace(str, "&amp", " & ") str = Replace(str, "&#03", Chr(39))

How to decode a (doubly) 'url-encoded' string in python

折月煮酒 提交于 2019-12-03 11:00:42
问题 Tried decoding a url-encoded string in the following way some_string = 'FireShot3%2B%25282%2529.png' import urllib res = urllib.unquote(some_string).decode() res u'FireShot3+%282%29.png' Original string is FireShot3 (2).png . Any help would be appreciated. Answer: urllib.unquote_plus(urllib.unquote_plus(some_string)) due to double encoding. 回答1: Your input is encoded double . Using Python 3: urllib.parse.unquote(urllib.parse.unquote(some_string)) Output: 'FireShot3+(2).png' now you have the +

Unicode URL decoding

北战南征 提交于 2019-12-03 09:55:34
问题 The usual method of URL-encoding a unicode character is to split it into 2 %HH codes. ( \u4161 => %41%61 ) But, how is unicode distinguished when decoding? How do you know that %41%61 is \u4161 vs. \x41\x61 ("Aa")? Are 8-bit characters, that require encoding, preceded by %00 ? Or, is the point that unicode characters are supposed to be lost/split? 回答1: According to Wikipedia: Current standard The generic URI syntax mandates that new URI schemes that provide for the representation of character

URL decode in iOS

本小妞迷上赌 提交于 2019-12-03 06:23:30
问题 I am using Swift 1.2 to develop my iPhone application and I am communicating with a http web service. The response I am getting is in query string format (key-value pairs) and URL encoded in .Net . I can get the response, but looking the proper way to decode using Swift. Sample response is as follows status=1&message=The+transaction+for+GBP+12.50+was+successful Tried following way to decode and get the server response // This provides encoded response String var responseString = NSString(data

How to know if a URL is decoded/encoded?

好久不见. 提交于 2019-12-03 05:52:24
I am using Javascript method decodeURIComponent to decode an encoded URL. Now I am having an issue, that sometimes the URL is get encoded twice during redirection between servers, sometimes it is encoded only once. I want to check that if the URL is still encoded after calling the method decodeURIComponent . How can I do that? Any pointer would be very helpful to me. Update - 1 If I recursively call a method and check that if the given URL still contains "%", if it contains "%" then decode it and call the method again; and if not return it to the caller, will that work? Update - 2 For my case