unzip

从动手到放弃之我不要自己编译ffmpeg了 【踩坑+草稿篇】

这一生的挚爱 提交于 2020-01-25 12:17:16
原本我在想要不要放出这篇文章来的,因为这篇文章不成熟,都是在编译ffmpeg---即使有前人放出来的源代码,但还是出现种种问题了----历经的各种坑,各种bug,但是其实一想,这些问题不会只有我一个人遇到的,放出来起码能让其他人做出参考。 在编译ffmpeg这期间,其实很耗时间,主要是不熟c++、cmake、makefile这些,还有几篇文章也是草稿类型,也是同时期涂鸦的: 都是废稿,不过可以说明一下ffmpeg不是拿一个源代码包编译就可以的: [运维] ubuntu等linux下编译配置ffmpeg以供c++调用[草稿] [运维] ubuntu等linux下编译配置ffmpeg以供c++调用 下面是正文: 前前言 我也不想有这个前前言的,然而,人工手动编译ffmpeg的难度已经超过我的想象了,即使有前人的智慧,但是我还是各种地雷,这个只是用来做踩坑用的一篇小笔记,如果正式要编译的话,那么直接看正式篇吧,这篇踩坑篇用来做什么?用来记录还有告诉其他人,你遇到的坑已经有人填过了。 前言 因为要涉足音视频的开发,所以,需要编译一下ffmpeg为静态库然后用c++调用。 然后,这种编译我重复了多次还是没办法成功---光是依赖都一大堆,而且要逐个编译--整个人都崩溃了,不过,好在看到了其他兄弟的编译脚本,尚算有一丝希望。 可以参考这个兄弟的: https://github.com

Windows command line compression/extraction tool?

一世执手 提交于 2020-01-24 20:40:35
问题 I need to write a batch file to unzip files to their current folder from a given root folder. Folder 0 |----- Folder 1 | |----- File1.zip | |----- File2.zip | |----- File3.zip | |----- Folder 2 | |----- File4.zip | |----- Folder 3 |----- File5.zip |----- FileN.zip So, I wish that my batch file is launched like so: ocd.bat /d="Folder 0" Then, make it iterate from within the batch file through all of the subfolders to unzip the files exactly where the .zip files are located. So here's my

Unzip password protected file in SSIS using Ionic.Zip dll

血红的双手。 提交于 2020-01-21 21:49:02
问题 I got requirement to unzip a file which contains password protected text files in zip file.which have to be done in SSIS package.. I have googled and download a dll called Ionic.Zip to used in script task. i have used the below code using c# in script task.. using Ionic.Zip; public void Main() { Dts.TaskResult = (int)ScriptResults.Success; start obj= new start(); obj.decrypt(); } public class start { public void decrypt() { string sfilepath ="E:\\shekar\\CIF_Files\\USAGE.zip"; ZipFile

Uzip folders recursively -android

对着背影说爱祢 提交于 2020-01-21 05:44:05
问题 I have tried to unzip a zipped file (This file contains many sub-folders and files). I am not able to create sub-folders while unzipping the file. Each time I am getting an error saying: No such file or directory. I have searched a lot about this like: Android - Unzip a folder? http://www.roseindia.net/tutorial/java/corejava/zip/ZipIsDirectory.html Unzip a zipped file on sd card in Android application How to unzip files recursively in Java? But, nothing helped me. Following is what I have

CentOS安装FastDFS超详细教程

試著忘記壹切 提交于 2020-01-19 13:59:27
请你用绝对的理智和清醒的头脑去压制你心里的爱和难过 首先下载所需要的安装文件, 点击下载 。 一、上传 将下载文件上传到linux下的 /home/fdfs 目录: 二、安装依赖 1、安装GCC依赖 GCC用来对C语言代码进行编译运行,使用yum命令安装: yum -y install gcc 2、安装unzip工具 unzip工具可以帮我们对压缩包进行解压 : yum install -y unzip zip 3、安装libevent yum -y install libevent 4、安装Nginx所需依赖 yum -y install pcre pcre-devel zlib zlib-devel openssl openssl-devel 5、安装libfastcommon-master 这个没有yum包,只能通过编译安装: ---解压刚刚上传的 libfastcommon-master.zip unzip libfastcommon-master.zip ---进入解压完成的目录: cd libfastcommon-master ---编译并且安装: ./make.sh && ./make.sh install 到这里为止,所有依赖都已经安装完毕,接下来我们安装FastDFS 三、 安装FastDFS 1、编译安装 ---解压 tar -xvf FastDFS_v5.08

Unzip all files and directories from a subfolder

半城伤御伤魂 提交于 2020-01-16 18:46:07
问题 My first post here. I need to create a Python script that can extract the sub-folder content of a .zip file into a specified directory and I can't find a way to do this. More exactly I'm upgrading daily the Blender_2.8 build from here: https://builder.blender.org/download/blender-2.80-741641f4c3b8-win64.zip The problem is that every day the name of the folder inside the .zip file it is changing. I need to extract only the sub-folder content without the root folder. I do have a somehow working

trouble unzipping file under Windows

为君一笑 提交于 2020-01-16 04:33:09
问题 I have the following code: download.file( "http://www.wikipathways.org//wpi/batchDownload.php?species=Homo%20sapiens&fileType=txt", destfile="human.zip") files <- unzip( "human.zip", list=T) It works on Linux, but throws the following error on Windows: Error in unzip("human.zip", list = T) : error -103 with zipfile in unzGetCurrentFileInfo Do you happen to know what's the problem? 回答1: In ?download.file , we read that: If mode is not supplied and url ends in one of .gz, .bz2, .xz, .tgz, .zip,

tar,unzip命令用法

徘徊边缘 提交于 2020-01-15 03:06:01
tar命令可以为文件和目录创建档案。平时经常使用。但对于命令参数却不一定很了解。 语法:tar [主选项+辅选项] 文件或目录 使用该命令时,主选项是必须要有的,而辅选项则是可以选的。 主选项: c 创建新的档案文件,如果想备份一个目录或文件,必须选择这个选项。 r 把要存档的文件追加到档案文件的末尾。例如用户已经做好备份文件,又发现一个目录或文件忘记备份时,使用该选项。 t 列出档案文件的内容,查看已备份了那些文件。 u 更新文件。用新增的文件取代备份文件,如果在备份文件中找不到更新的文件,则把它追加到备份文件的最后。 x 从档案文件中释放文件。 辅助选项: b 该选项是为磁带机而设的。 f 使用档案文件或设备,通常此选项是必选的。 k 保存已经存在的文件。当我们把某个文件进行还原时,在还原的过程中,遇到相同的文件,不会进行覆盖。 m 在还原文件时,把所有文件的修改时间设定为现在。 M 创建多卷的档案文件,以便在几个磁盘中存放。 v 详细报告tar处理的文件信息。 w 每一步都要求确认。 z 用gzip来压缩/解压文件。加上该选项后,可以将档案文件进行压缩。 示例: tar 解包:tar xvf FileName.tar 打包:tar cvf FileName.tar DirName (注:tar是打包,不是压缩!) -------------------------------

Java - How to move a file into a zip file?

守給你的承諾、 提交于 2020-01-13 18:05:38
问题 That's it. I have a text file, and I need to move it to a (existing) Zip File in a given directory. File file = new File("C:\\afolder\\test.txt"); File dir = new File(directoryToGo+"existingzipfile.zip"); boolean success = file.renameTo(new File(dir, file.getName())); But it does not work. Is there a way to move a file into a existing Zip File? Thank you. 回答1: Hmm you could use something like: public static void addFilesToExistingZip(File zipFile, File[] files) throws IOException { // get a

R download and unzip file to store in data frame

末鹿安然 提交于 2020-01-13 03:10:15
问题 I have a similar question to the one posted in here but the solution suggested doesn't work for me. I want to simply download a zipped file from github, unzip it and store the data on a data frame (it is a Coursera project but the main purpose is to create a Markdown doc and not to download/unzip the file...so I am not asking how to do my homework). My code is the following: activity_url <- "https://github.com/rdpeng/RepData_PeerAssessment1/blob/master/activity.zip" temp <- tempfile()