unpack

git unpack error on push to gerrit

╄→гoц情女王★ 提交于 2019-11-28 03:18:51
On push of a new branch to a gerrit server we encounter the following error: de@roma:~/git-hate/www$ git push origin landingpage Counting objects: 149, done. Delta compression using up to 2 threads. Compressing objects: 100% (73/73), done. Writing objects: 100% (111/111), 2.77 MiB, done. Total 111 (delta 68), reused 80 (delta 38) remote: Resolving deltas: 100% (68/68) error: unpack failed: error Missing tree 30c4809ade0b4b0c81cb7f882450774862b82361 fatal: Unpack error, check server log To ssh://user@git-server/repository ! [remote rejected] landingpage -> landingpage (n/a (unpacker error))

lambda arguments unpack error

无人久伴 提交于 2019-11-27 23:12:54
In Python 2 this code is OK: f = lambda (m, k): m + k m = [1,2,3,4] k = [5,6,7,8] print(map(f, zip(m, k))) but in Python 3 the following error occurred: f = lambda (m, k): m + k ^ SyntaxError: invalid syntax If I remove parentheses in lambda expression then another error occurred: TypeError: <lambda>() missing 1 required positional argument: 'k' Also approach with tuple as single lambda argument works in Python 3, but it's not clear (hard for reading): f = lambda args: args[0] + args[1] How can I unpack values in the right way in Python 3? The removal of tuple unpacking is discussed in PEP

Python-like unpacking in JavaScript

心已入冬 提交于 2019-11-27 21:07:52
I have the following string output_string = "[10, 10, [1,2,3,4,5], [10,20,30,40,50]]" Then I JSON.parse it my_args = JSON.parse(output_string) How do I unpack it in a Python-like way so that every element in my_args becomes an argument to a JavaScript function? some_javascript_function(*my_args) // should be equivalent to: some_javascript_function(my_args[0],my_args[1],my_args[2],my_args[3]) // or: some_javascript_function(10, 10, [1,2,3,4,5], [10,20,30,40,50]) Is there a core JavaScript idiom that does that? Once you 've collected the function arguments in an array, you can use the apply()

How do I unpack various form of integers in a byte buffer in Golang?

萝らか妹 提交于 2019-11-27 13:57:08
问题 I need to extract various fields in a byte buffer. I came up with this solution: func (fs *FileSystem) readSB() { // fs.f is a *os.File buf := make([]byte, 1024) fs.f.ReadAt(buf, 1024) // Offset: type var p *bytes.Buffer // 0: uint32 p = bytes.NewBuffer(buf[0:]) binary.Read(p, binary.LittleEndian, &fs.sb.inodeCount) // 4: uint32 p = bytes.NewBuffer(buf[4:]) binary.Read(p, binary.LittleEndian, &fs.sb.blockCount) // 20: uint32 p = bytes.NewBuffer(buf[20:]) binary.Read(p, binary.LittleEndian,

pack / unpack functions for node.js [closed]

泪湿孤枕 提交于 2019-11-27 07:36:47
Are there any modules that provide pack / unpack functionality for nodejs similar to python's struct module? I haven't found any specifically for node, and I'd assume that javascript implementations would be significantly slower. Thanks. https://github.com/pgriess/node-jspack appears to be a straight-up port of Python's struct API for packing binary data, but it's implemented in JS. It doesn't appear to be packaged for npm yet. https://github.com/substack/node-binary provides unpacking, also implemented in JS, and you can install it with npm install binary if you have npm installed. https:/

Python: reading 12-bit binary files

左心房为你撑大大i 提交于 2019-11-27 06:31:58
问题 I am trying to read 12-bit binary files containing images (a video) using Python 3. To read a similar file but encoded in 16 bits, the following works very well: import numpy as np images = np.memmap(filename_video, dtype=np.uint16, mode='r', shape=(nb_frames, height, width)) where filename_video is the file and nb_frames, height, and width characteristics of the video that can be read from another file. By 'working very well' I mean fast: reading a 640x256 video that has 140 frames takes

How to unpack all objects of a git repository?

六眼飞鱼酱① 提交于 2019-11-27 04:02:51
How can I unpack all objects of a pack file? I've just cloned a remote repository, so my local repository currently doesn't contain any loose object, only a .pack and a .idx files. I've tried running git unpack-objects < .git/objects/pack/pack-.pack , but nothing happens. I'm doing something wrong? Is there any other command to do that? You need to move the pack objects outside the .git/objects/pack directory before using the command. However, the pack files need to be inside the repository. For example, create a directory name SAMPLE in your project's root. Then, move the pack files to SAMPLE

How to unpack the contents of a JavaScript file?

流过昼夜 提交于 2019-11-27 02:15:59
问题 You know how those packed js files look like, right? eval(function(p,a,c,k,e,d){ ... } ('obfuscated-string'.split('|'),0,{})) It just so happens to be that i have to tweak some large legacy code that looks like that and I want to find a way to turn this into a more readable version. If that's not possible, can i at least get rid of the eval? 回答1: You can with online unpackers: try one of these, find one that suits you: Dean Edwards Unpacker JSUnpack 回答2: JS Beautifier will both reformat and

Python-like unpacking in JavaScript

筅森魡賤 提交于 2019-11-26 23:01:57
问题 I have the following string output_string = "[10, 10, [1,2,3,4,5], [10,20,30,40,50]]" Then I JSON.parse it my_args = JSON.parse(output_string) How do I unpack it in a Python-like way so that every element in my_args becomes an argument to a JavaScript function? some_javascript_function(*my_args) // should be equivalent to: some_javascript_function(my_args[0],my_args[1],my_args[2],my_args[3]) // or: some_javascript_function(10, 10, [1,2,3,4,5], [10,20,30,40,50]) Is there a core JavaScript

lambda arguments unpack error

限于喜欢 提交于 2019-11-26 20:59:33
问题 In Python 2 this code is OK: f = lambda (m, k): m + k m = [1,2,3,4] k = [5,6,7,8] print(map(f, zip(m, k))) but in Python 3 the following error occurred: f = lambda (m, k): m + k ^ SyntaxError: invalid syntax If I remove parentheses in lambda expression then another error occurred: TypeError: <lambda>() missing 1 required positional argument: 'k' Also approach with tuple as single lambda argument works in Python 3, but it's not clear (hard for reading): f = lambda args: args[0] + args[1] How