unix-timestamp

问题 Is there a good way to parse milliseconds since epoch (ex. 1486252500000 13 digits) formatted time into a human readable format? 回答1: DateTime does have a named constructor for millisecond since epoch https://api.dartlang.org/stable/1.24.2/dart-core/DateTime/DateTime.fromMillisecondsSinceEpoch.html DateTime date = new DateTime.fromMillisecondsSinceEpoch(1486252500000) If you want to convert it to human readable string, you can use intl package with the DateFormat class import "package:intl

问题 How can I replace "details1" in "request_2" with correlated value "SynchToken" from "request_1". I am trying to replace with ${SynchToken} but it is not reflecting the correlated value. val Transaction_Name_1 = group("Transaction_Name_1") { exec(http("request_1") .get(session => "/abc/details1?_=" + System.currentTimeMillis()) .check(regex("""name="SYNCHRONIZER_TOKEN" value="(.*?)"""").saveAs("SynchToken"))) .pause(5) .exec(http("request_2") .get(session => "/abc/details1?_=" + System

问题 How can I replace "details1" in "request_2" with correlated value "SynchToken" from "request_1". I am trying to replace with ${SynchToken} but it is not reflecting the correlated value. val Transaction_Name_1 = group("Transaction_Name_1") { exec(http("request_1") .get(session => "/abc/details1?_=" + System.currentTimeMillis()) .check(regex("""name="SYNCHRONIZER_TOKEN" value="(.*?)"""").saveAs("SynchToken"))) .pause(5) .exec(http("request_2") .get(session => "/abc/details1?_=" + System

问题 I am attempting to get a matplotlib plotting function to be able to produce a graph with the x-axis set as a time axis. However, when I attempt to plot some values against UNIX times, I encounter the error ValueError: year is out of range . What is going wrong and how can it be addressed? import os import time import matplotlib.dates import matplotlib.pyplot import shijian def main(): data = [ [1484611200.0, 844.4333], [1484524800.0, 783.3373], [1484438400.0, 774.194 ], [1484352000.0, 769

问题 I am attempting to get a matplotlib plotting function to be able to produce a graph with the x-axis set as a time axis. However, when I attempt to plot some values against UNIX times, I encounter the error ValueError: year is out of range . What is going wrong and how can it be addressed? import os import time import matplotlib.dates import matplotlib.pyplot import shijian def main(): data = [ [1484611200.0, 844.4333], [1484524800.0, 783.3373], [1484438400.0, 774.194 ], [1484352000.0, 769

问题 I am working in with a database in which dates are stored as unix time (seconds since 1970). I have the following sql which works as expected: select CONVERT_TZ(FROM_UNIXTIME(creation_date), @@session.time_zone, "Europe/Berlin") from transaction; This is how I tried to do it in Jooq: dsl.select(DSL.date(TRANSACTION.CREATION_DATE) // This does not work .from(TRANSACTION) .fetch(); 回答1: You're using quite a few vendor specific functions there, which are not supported out of the box in jOOQ. As

问题 I am trying to figure out how to display a firestore timestamp in a react app. I have a firestore document with a field named createdAt. I am trying to include it in a list of output (extracting the relevant bits here so that you don't have to read through the entire list of fields). componentDidMount() { this.setState({ loading: true }); this.unsubscribe = this.props.firebase .users() .onSnapshot(snapshot => { let users = []; snapshot.forEach(doc => users.push({ ...doc.data(), uid: doc.id })

问题 I have start date as "2017-11-14 10:11:01 CET" and end date as "2017-11-15 01:15:59 CET". I want to create timestamps of 500 milliseconds each, between these start and end timestamps. E.g. I need a dataframe containing the following output timestamp 2017-11-14 10:11:01.000 2017-11-14 10:11:01.500 2017-11-14 10:11:02.000 2017-11-14 10:11:02.500 . . . 2017-11-15 01:15:59.000 Somehow, I managed to get the start and end date in milliseconds using the following code: start.date <- strptime("2017

问题 I have a requirement to convert the mentioned input string format and produce the desired output in timestamp as shown below. Input: 16AUG2001:23:46:32.876086 Desired Output: 2001-08-16 23:46:32.876086 Output which is coming by running the below code: 2001-08-17 00:01:08 Query: select '16AUG2001:23:46:32.876086' as row_ins_timestamp, from_unixtime(unix_timestamp('16AUG2001:23:46:32.876086', 'ddMMMyyyy:HH:mm:ss.SSSSSS')) as row_ins_timestamp from temp; Milliseconds part is not getting

问题 I have a Unix timestamp like this: $timestamp=1330581600 How do I get the beginning of the day and the end of the day for that timestamp? e.g. $beginOfDay = Start of Timestamp's Day $endOfDay = End of Timestamp's Day I tried this: $endOfDay = $timestamp + (60 * 60 * 23); But I don't think it'll work because the timestamp itself isn't the exact beginning of the day. 回答1: strtotime can be used to to quickly chop off the hour/minutes/seconds $beginOfDay = strtotime("today", $timestamp);