unix-timestamp

问题 I want to convert a date string to unix timestamp from a date string e.g. 14-02-2018 Can someone help? 回答1: Since JDK 8 you can do: val l = LocalDate.parse("14-02-2018", DateTimeFormatter.ofPattern("dd-MM-yyyy")) val unix = l.atStartOfDay(ZoneId.systemDefault()).toInstant().epochSecond Note that the example uses your system's default timezone. 回答2: use this to convert the date string to UNIX timestamp val date = SimpleDateFormat("dd-MM-yyyy").parse("14-02-2018") println(date.time) 来源： https:/

问题 I want to convert a date string to unix timestamp from a date string e.g. 14-02-2018 Can someone help? 回答1: Since JDK 8 you can do: val l = LocalDate.parse("14-02-2018", DateTimeFormatter.ofPattern("dd-MM-yyyy")) val unix = l.atStartOfDay(ZoneId.systemDefault()).toInstant().epochSecond Note that the example uses your system's default timezone. 回答2: use this to convert the date string to UNIX timestamp val date = SimpleDateFormat("dd-MM-yyyy").parse("14-02-2018") println(date.time) 来源： https:/

问题 I am writing a script and which requires to calculate the difference between the two timestamps . I have done some search but didn't get a clue so far. For Example say: time1 = 20160314 10:16:27 time2 = 20160313 15:17:28 From the above I need to get result like below: difference is: " 1 day 5 hours 1 minute 1 second " Please help me in resolving this. 回答1: datediff() { t1=$(date -d "$1" +%s) t2=$(date -d "$2" +%s) diff=$(( $t1 - $t2 )) echo "Duration: $(( $diff / 86400 )) days $(($diff / 3600

问题 I have datetime string "2019-11-02T20:18:00Z" . How can I convert it into timestamp in Hive HQL? 回答1: If you want preserve milliseconds then remove Z , replace T with space and convert to timestamp: select timestamp(regexp_replace("2019-11-02T20:18:00Z", '^(.+?)T(.+?)Z$','$1 $2')); Result: 2019-11-02 20:18:00 Also it works with milliseconds: select timestamp(regexp_replace("2019-11-02T20:18:00.123Z", '^(.+?)T(.+?)Z$','$1 $2')); Result: 2019-11-02 20:18:00.123 Using from_unixtime(unix

问题 I logging my temperature every 1-3 seconds with unix timestamp, I wish like get row of data return by average every 1 minute period and last for 24 hour. my logger table look like this: unixtime temp 1350899052 25.37 1350899054 25.44 1350899057 25.44 1350899059 25.44 1350899062 25.44 1350899064 25.44 1350899069 25.44 1350899071 25.44 and i wish like it return as unixtime temp 1350899052 25.37 -- average value of 1 minute range both unixtime and temp 1350899054 25.44 1350899057 25.44 please

问题 How can I convert unix epoch with milliseconds to timestamp with milliseconds In Hive? Neither cast() nor from_unixtime() function is working to get the timestamp with milliseconds. I tried .SSS but the function just increases the year and doesn't take it as a part of millisecond. scala> spark.sql("select from_unixtime(1598632101000, 'yyyy-MM-dd hh:mm:ss.SSS')").show(false) +-----------------------------------------------------+ |from_unixtime(1598632101000, yyyy-MM-dd hh:mm:ss.SSS)| +-------

问题 I have a text file with many rows of data - the first piece of data in each row is a unix timestamp such as 1436472000 . I am using numpy.loadtxt and in the parameters for converters I want to specify for it to convert the timestamp into whatever numpy understands as a date time. I know this needs to go after the 0: in the curly brackets, but I can't work out how to convert it. I know a converter can be used from matplotlib.dates.strpdate2num for normal dates, but I this won't work for unix

问题 I have a date in utc second and its time zone offset in sec. I would like to convert it to date string in format yyyy-mm-dd using java8 ZoneOffset class. Below is the time in seconds and offset long time = 1574962442, long offset = 3600 Now i want to obtain date in below format using java-8 DateTime API ? String date = 2019-11-28 // in yyyy-MM-dd 回答1: You can use Instant from java-8 DateTime API to obtains an OffsetDateTime of Instant from epoch seconds with offset seconds OffsetDateTime

问题 How Can I get the date time in unix time as byte array which should fill 4 bytes space in Java? Something like that: byte[] productionDate = new byte[] { (byte) 0xC8, (byte) 0x34, (byte) 0x94, 0x54 }; 回答1: First: Unix time is a number of seconds since 01-01-1970 00:00:00 UTC. Java's System.currentTimeMillis() returns milliseconds since 01-01-1970 00:00:00 UTC. So you will have to divide by 1000 to get Unix time: int unixTime = (int)(System.currentTimeMillis() / 1000); Then you'll have to get

问题 I'm trying to read the date fields of Firefox places.sqlite datedase using ADO.NET and PowerShell. Obviously these fields are in Unix time. I'm looking for a conversion to .Net datetime or string Edit: I want to bind the datarow to a WPF GridView. I need either a way to do the conversion within the SQL query or some way while binding the datarows to the grid. 回答1: Something like this should put you on the right path: [TimeZone]::CurrentTimeZone.ToLocalTime(([datetime]'1/1/1970').AddSeconds(