triplet

Triplet loss on text embeddings with keras

由 ≡放荡痞女 提交于 2019-12-11 16:08:28
问题 I'd start saying i'm quite new to Keras and machine learning in general. I'm trying to build an "experimental" model consisting of two parts: An "encoder" which takes a string (containing a long series of attributes, i'm using the DBLP-ACM dataset), builds an embedding of the words of this string (word2vec), and encodes them in a vector (bidirectional LSTM). A trainable model which takes 3 vectors in input (result of model 1) and uses the triplet loss as loss function (i already defined it,

How to print all increasing-index triplets in an array?

由 a 夏天 提交于 2019-12-08 05:27:51
问题 Given an array ar of length n , how can I print all triplets (ar[i], ar[j], ar[k]) in better than O(n^3) time where 0<=i<j<=k<n ? Example Input: ar[]={5,6,7} Output: 5 6 6 5 6 7 6 7 7 回答1: You can't. Suppose that the array has n elements. Included in the output is each combination of values from the first third of the array, second third, and third third. That right there is n^3/27 = O(n^3) output. You cannot produce O(n^3) output with less than O(n^3) work. 来源： https://stackoverflow.com

is it possible to find all the triplets in the given array for the O (n) time?

由 久未见 提交于 2019-12-04 05:16:38
问题 Given an array of numbers find all such triplets that satisfy the given condition. Condition: a[i] < a[j] < a[k] where I < j < k . it is possible to solve this problem in O (n) time? This is not home work !!! 回答1: The size of the output (worst case) is a lower bound on the complexity. Since there are possibly O(n^3) such triplets, the complexity cannot be O(n). For example if the array is sorted from lowest to highest, you will have n choose 3 such triplets which is order of n^3. If the

STL-pair-like triplet class - do I roll my own?

由 点点圈 提交于 2019-11-30 17:03:09
I want to use a triplet class, as similar as possible to std::pair. STL doesn't seem to have one. I don't want to use something too heavy, like Boost. Is there some useful FOSS non-restrictive-license triplet class I could lift from somewhere? Should I roll my own? Should I do something else entirely? Edit: About std::tuple ... Is there really no benefit to a triplet-specific class? I mean, with tuple, I can't do template<typename T1, typename T2, typename T3> std::tuple<T1, T2, T3> triple; now can I? Won't I have to typedef individual-type-combination triples? Joseph Mansfield No, don't roll

STL-pair-like triplet class - do I roll my own?

由 三世轮回 提交于 2019-11-30 00:15:00
问题 I want to use a triplet class, as similar as possible to std::pair. STL doesn't seem to have one. I don't want to use something too heavy, like Boost. Is there some useful FOSS non-restrictive-license triplet class I could lift from somewhere? Should I roll my own? Should I do something else entirely? Edit: About std::tuple ... Is there really no benefit to a triplet-specific class? I mean, with tuple, I can't do template<typename T1, typename T2, typename T3> std::tuple<T1, T2, T3> triple;
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