topmost

问题 What I'm trying to do is simple: make my WinForm on top of another, but not topmost. Like, when I click on a window, my winform will be on top of it, but when I click on something else, like a browser, my form will not be on top of it. Like a TopMost WinForm, but only for a specific process. (Im making a overlay for a game, so I need it to be topmost ONLY on the game.) Pictures to help (Everything inside the RED border is my form): And then when I change to another window (In this case,

问题 What I'm trying to do is simple: make my WinForm on top of another, but not topmost. Like, when I click on a window, my winform will be on top of it, but when I click on something else, like a browser, my form will not be on top of it. Like a TopMost WinForm, but only for a specific process. (Im making a overlay for a game, so I need it to be topmost ONLY on the game.) Pictures to help (Everything inside the RED border is my form): And then when I change to another window (In this case,

问题 How do you put a Windows Form Application on top off everything on your screen? Just setting the topmost-property isn't enough when you're running fullscreen games. If anyone has a solution for good old Forms i'll also be happy I've seen many posts on this forum that say it's impossible but i know it's not couse i've seen alot of apps (fraps, teamspeak overlay, xfire, etc) that does this. 回答1: If you want to use a graphics library to display something always on screen, you may want to start

问题 I will first explain why I need it, because I anticipate that the first response will be "Why do you need it?". I want to detect when the mouse cursor is on an edge of the screen and I don't want to use hooks. Hence, I created one pixel wide TOPMOST invisible window. I am using C++ on Win XP, so when the window is created (CreateWindowEx(WS_EX_TOPMOST | WS_EX_TRANSPARENT ...) everything works fine. Unfortunately, if a user moves another topmost window, for example the taskbar over my window,

问题 I already know tkinter.Tk().attributes("-topmost", True) which makes the window stay on top all the time. But is there some way to make the window stay at the bottom all the time? I mean something like tkinter.Tk().attributes("-bottommost", True) or something like that. 回答1: No, there is no method in tkinter that forces the window to be below all other windows on the desktop. 回答2: There is not strictly a way to make a Tk window always underneath others. If your aim is to have a Tk application

问题 Is there a way I can set a ShowDialog() to not be topmost? I've looked at all the related SO questions, and none quite matched my situation. What I do is open a new WinForm from a datagridview button column. This new form pulls information from a few SQLite tables and allows the user to add information to the row the button was clicked. I open the WinForm using the code below. I use the ShowDialog() method so I can tell if the user saves the information in the form or cancels it. Pay_Bill

问题 I would like to display a status window in my C# Windows Forms application that informs the user when the application is waiting to acquire a lock. This is an application-defined thing, however, the window should be visible and always remain on top of all other windows of my application, even when the user clicks on another window (like for example the larger main window behind it). It must not be modal (so ShowDialog() cannot be used) because the app needs to keep trying in the background

问题 Basically, how do I tell if my program is layered above all the other ones? 回答1: A fairly simple way is to P/Invoke GetForegroundWindow() and compare the HWND returned to the application's form.Handle property. using System; using System.Runtime.InteropServices; namespace MyNamespace { class GFW { [DllImport("user32.dll")] private static extern IntPtr GetForegroundWindow(); public bool IsActive(IntPtr handle) { IntPtr activeHandle = GetForegroundWindow(); return (activeHandle == handle); } }

问题 Basically, how do I tell if my program is layered above all the other ones? 回答1: A fairly simple way is to P/Invoke GetForegroundWindow() and compare the HWND returned to the application's form.Handle property. using System; using System.Runtime.InteropServices; namespace MyNamespace { class GFW { [DllImport("user32.dll")] private static extern IntPtr GetForegroundWindow(); public bool IsActive(IntPtr handle) { IntPtr activeHandle = GetForegroundWindow(); return (activeHandle == handle); } }

问题 I have a vector and I'm able to return highest and lowest value, but how to return 5 topmost values? Is there a simple one-line solution for this? 回答1: > a <- c(1:100) > tail(sort(a),5) [1] 96 97 98 99 100 回答2: x[order(x)[1:5]] 回答3: Yes, head( X, 5) where X is your sorted vector. 回答4: tail(sort.int(x, partial=length(x) - 4), 5) Using sort.int with partial has the advantage of being (potentially) faster by (potentially) not doing a full sort. But in reality, my implementation appears a little