syntax-error

问题 This question already has answers here : The literal xyz of type int is out of range (5 answers) Closed 5 years ago . I was trying to do some Project Euler question which involves pandigital numbers with special divisibility requirements of the first 5 prime numbers, and thought that this would be the starting point (see, 1023456789 is the first number being looked at, and 9876543210 is the last one). import java.util.*; public class pandigital_special { public static void main (String args[]

问题 I have a table cell that shows if there's more than 10 records. Part of my pagination. <td ng-show="totalRecords>10" colspan="5"> <ul uib-pagination style="margin:0;" total-items="totalRecords" ng-model="currentPage" ng-change="pageChanged()"></ul> </td> Pretty straightforward. But here's the crazy - it throws the following error in Chrome: Uncaught Error: Syntax error, unrecognized expression: td[ng-show='totalRecords @ browserLink:37 bc.error @ browserLink:37 bh @ browserLink:37 bp @

问题 I've just downloaded python 3.3.2 and pygame-1.9.2a0.win32-py3.3.msi . I have decided to try a few tutorials on youtube and see if they work. I have tried thenewboston's 'Game Development Tutorial - 2 - Basic Pygame Program' to see if it works. It is supposed to produce a black background and a ball that is the mouse (or so i think). It comes up with a syntax error when i try to run it, if i delete it it just produces a black pygame window. Here is the code: bgg="bg.jpg" ball="ball.png"

问题 DROP PROCEDURE `ModificarUsuario`// CREATE DEFINER=`root`@`localhost` PROCEDURE `ModificarUsuario`( IN `Aid` INT, IN `Aced` VARCHAR(100), IN `Anombre` VARCHAR(100), IN `Acargo` VARCHAR(100), IN `Acedula` VARCHAR(100), IN `Ausuario` VARCHAR(100), IN `Apass` VARCHAR(100), OUT `res` VARCHAR(10) ) BEGIN SELECT COUNT(usuario) INTO res FROM `usuario` WHERE `cedula`=Aced and `id`<>Aid; IF res =0 THEN UPDATE `usuario` SET cedula=Aced, nombre=Anombre, cargo=Acargo, usuario=Ausuario, contrasena=Apass

问题 I am writing code to generate a random 3 letter strings using the letters a, b, and c. I am getting the error message "Syntax error on token ";", { expected after this token" after the line where i create the random variable (Random rand = new Random();). I do not know why I am getting this error when it looks fine to me. I am also getting the error message: Syntax error, insert "}" to complete ClassBody, after the last bracket in the program. I am almost postive all my closing brackets match

问题 First off, I'm confused on how to run PHP in the command-line. I've been reading several articles on the web and they all say that you need a CLI (Command Line Interface). Basically, I have PHP files, and I want to call something like this: php -l somefile.php But I'm wanting to check a string , not a file! How can this be done? Can using STDIN , STDOUT , or STDERR help with this at all? If so, how? Can someone provide an example here? Also, where do I place that above code? I don't have

问题 The following lines of JavaScript try { function _free() {} var _free = 1; } finally { } result in the following error: Uncaught SyntaxError: Identifier '_free' has already been declared However, the following two blocks of JavaScript code don't: Without the try block scope: function _free() {} var _free = 1; Within a function scope: function a() { function _free() {} var _free = 1; } But why? (Testing environment: Chromium 61.0.3126.0) 回答1: Because block-scoped function declarations are a

问题 I've a little headache with this console error, ONLY on Safari (working on MacBook actually). I have this function: function exists(element){ var exists = document.querySelector(element); return exists; } invoked inside another function: function includeHoverStylesheet(){ var path = $("body").attr("data-hover"); if (!("ontouchstart" in document.documentElement || exists("link[href='" + path + "'"))) { var link = document.createElement("link"); link.rel = "stylesheet", link.href = path,

问题 I keep getting syntax error if i use instructions like li or la. If i try a code without these instructions it works fine, but i need to use them. I tried different versions and i keep getting the same error (I have allowed pseudo instructions). I need to use it for a university project but i can't check if the code i wrote is ok since i can't run the code. Am i missing something? I don't know how to make it work properly, i'm new to assembly and pcspim, so i may be overlooking something

问题 I Don't know what actually I should do and if there is something wrong somebody please correct it and give it thanks in advance <?php $db_host = 'localhost'; $db_user = 'root'; $db_pass = ''; $db_name = 'cms'; $conn = mysqli_connect($db_host,$db_user,$db_pass) or die(mysql_error()); mysqli_select_db($db_name,$conn); ?> 回答1: Use this: $con = mysqli_connect($hostname,$user,$password,$database); You don't need: mysqli_select_db Your code will be: $db_host = 'localhost'; $db_user = 'root'; $db