synchronizing

问题 display a1b2c3...z26 by creating 2 process and each process run seperatley with a random sleep of 1 to 5 is there any way to show off the process 1 has to wait for process 2 respectively p1 will generate abcdef... with sleep $[ ( $RANDOM % 5 ) + 1 ]s p2 will generate 12345..with sleep $[ ( $RANDOM % 5 ) + 1 ]s 回答1: Process 1 ./abc.sh > cd /home/sanjaisambu/Sanjai/a1b2/ for j in {a..z} do > while [ -f './syncfile' ] > do > echo 'process 1 waiting' > sleep 1 > done > touch ./syncfile > echo -n

问题 display a1b2c3...z26 by creating 2 process and each process run seperatley with a random sleep of 1 to 5 is there any way to show off the process 1 has to wait for process 2 respectively p1 will generate abcdef... with sleep $[ ( $RANDOM % 5 ) + 1 ]s p2 will generate 12345..with sleep $[ ( $RANDOM % 5 ) + 1 ]s 回答1: Process 1 ./abc.sh > cd /home/sanjaisambu/Sanjai/a1b2/ for j in {a..z} do > while [ -f './syncfile' ] > do > echo 'process 1 waiting' > sleep 1 > done > touch ./syncfile > echo -n

问题 I have a question about CUDA synchronizing. Particularly, I need some clarification about synchronizing in if statements. I mean, if I put a __syncthreads() under the scope of an if statement hit by a fraction of the threads inside the block, what happens? I thought that some threads will remain "forever" waiting for the other threads that won't hit the synchronizing point. So, I wrote and executed some sample code to inspect: __global__ void kernel(float* vett, int n) { int index = blockIdx

问题 I am trying to synchronize two threads - the "Main" thread, and a runnable. I get the IllegalMonitorStateException, but I do not completelty understand what "you do not have the lock of the object" means. Here is my code: public class ThreadsTest { private static ThreadsTest instance; public volatile boolean flag = false; public void doStuff() { System.out.println("first"); this.flag = true; } public Runnable mDrawer = new Runnable() { public void run() { synchronized (ThreadsTest.getInstance