suds

问题 Im using python 2.7 and suds 0.4 in windows and linux and in both cases I get the same error when calling a method of a web service: Traceback (most recent call last): File "wsclient.py", line 23, in <module> client.service.Echo() File "build\bdist.win32\egg\suds\client.py", line 542, in __call__ File "build\bdist.win32\egg\suds\client.py", line 602, in invoke File "build\bdist.win32\egg\suds\client.py", line 643, in send File "build\bdist.win32\egg\suds\client.py", line 678, in succeeded

问题 I am trying to connect to Aramex shipping SOAP API using Python Suds using following code: import suds from suds.client import Client client = Client('file:///home/test/test_wsdl_aramex/shipments-tracking-api-wsdl.wsdl',cache=None) But after starting, I get the following exception: > raise Exception("portType '%s', not-found" % self.type) Exception: portType 'i0:Service_dd1_0', not-found The WSDL file source can be found here. 回答1: Error is here: <wsdl:binding type="i0:Service_1_0" name=

问题 Background I'm building a SOAP client with python 2.7.3 and using the suds 0.4.1 library provided by Canonical. The server is using basic authentication over HTTPS. Problem Can't pass authentication on the server, even to get at the WSDL. I get the following error: suds.transport.TransportError: HTTP Error 401: Unauthorized Attempts at resolution and code I have tried both of the authentication methods described in the suds documentation, but still get the error above at the client = Client

问题 I have the following simple python test script that uses Suds to call a SOAP web service (the service is written in ASP.net): from suds.client import Client url = 'http://someURL.asmx?WSDL' client = Client( url ) result = client.service.GetPackageDetails( "MyPackage" ) print result When I run this test script I am getting the following error (used code markup as it doesn't wrap): No handlers could be found for logger "suds.bindings.unmarshaller" Traceback (most recent call last): File

问题 I have the following simple python test script that uses Suds to call a SOAP web service (the service is written in ASP.net): from suds.client import Client url = 'http://someURL.asmx?WSDL' client = Client( url ) result = client.service.GetPackageDetails( "MyPackage" ) print result When I run this test script I am getting the following error (used code markup as it doesn't wrap): No handlers could be found for logger "suds.bindings.unmarshaller" Traceback (most recent call last): File

问题 I use python/suds to implement a client and I get wrong namespace prefixes in the sent SOAP header for a spefic type of parameters defined by element ref= in the wsdl. The .wsdl is referencing a data types .xsd file, see below. The issue is with the function GetRecordAttributes and its first argument of type gbt:recordReferences . File: browse2.wsdl <xsd:schema targetNamespace="http://www.grantadesign.com/10/10/Browse" xmlns="http://www.grantadesign.com/10/10/Browse" xmlns:gbt="http://www

问题 Trying to place SOAP calls to Cisco AXL interface using Python with SUDS. Have the following test code: from suds.client import Client from suds.sax.element import Element wsdl = 'file:///C://Cisco//axlsqltoolkit//schema//8.0//AXLAPI.wsdl' client = Client(wsdl,username='administrator',password='ABC123') regionName = Element('name').setText('Default') region = client.service.getRegion(regionName) Getting the following error: DEBUG:suds.client:sending to (https://192.168.1.10:8443/axl/) message

问题 how to check the version of suds installed in python, i look over in the net but i cannot find one. i try this one. in running python manage.py shell >>> import suds >>> suds but i got the python version on running it. <module 'suds' from '/usr/local/lib/python2.7/dist-packages/suds/__init__.pyc'> how can I check the suds version? i try also suds version but i got this error >>> import suds >>> suds version File "<console>", line 1 suds version ^ SyntaxError: invalid syntax 回答1: >>>> import

问题 I've read and tried the other solutions I've seen posted, but despite this I can't seem to get this to work. I have the following code: imp = Import('http://www.w3.org/2001/XMLSchema', location='http://www.w3.org/2001/XMLSchema.xsd') imp.filter.add(['http://microsoft.com/wsdl/types/','http://tempuri.org/', 'http://tempuri.org']) # the schema to import into. d = ImportDoctor(imp) client = Client(url='https://apitest.integrapay.com.au/PayLinkService.svc?singleWsdl', username='user', password=

问题 I'm trying to send a soap request using the suds python package as below: from suds.client import Client WSDL_URL = 'file:/home/Documents/soap/getttt.wsdl' client = Client(WSDL_URL, cache=None) result = client.service.GET_TTT(H_ID="01", TTT_ID="44825955", VERSION_DATE="2010-12-01", ACC="B9800B4930543BC4FB305124EDFF7846") print result It works fine with a simple wsdl with http uri, but I need to load this wsdl using the file protocol and this wsdl is much more complicated. It imports xsd files