sub-array

问题 C program that finds starting and ending indexes of subarray to remove to make given array have equal sums of left and right side. If its impossible print -1. I need it to work for any array, this is just for testing. Heres a code that finds equilibrium. #include <stdio.h> int equilibrium(int arr[], int n) { int i, j; int leftsum, rightsum; /* Check for indexes one by one until an equilibrium index is found */ for (i = 0; i < n; ++i) { /* get left sum */ leftsum = 0; for (j = 0; j < i; j++)

问题 I want to modify the values of a sub-array in Python but it does not work the way I would like to. Here is an example, first let us consider the numpy arrays : A = np.reshape(np.arange(25),(5,5)) and B = np.ones((2,3)) If we check the values of A we get : >>> A array([[ 0, 1, 2, 3, 4], [ 5, 6, 7, 8, 9], [10, 11, 12, 13, 14], [15, 16, 17, 18, 19], [20, 21, 22, 23, 24]]) I want to replace in A the values of the sub-array A[:,[1,3,4]][[1,3],:] by the values of B. So what I am doing is the

问题 I have an array of numbers and I need to sort only part of it by left and right barriers. Can you please help me how to implement it correctly? const sortBetween = (arr, left, right) => { ... } given: [9,3,5,7,4,9,4,1] , left = 2, right = 5 expected: [9,3,4,5,7,9,4,1] [9,3, 5,7,4,9 ,4,1] -> [9,3, 4,5,7,9 ,4,1] Thanks for the help. 回答1: This is an approach by using sort directly, but shaping the access with a Proxy for length and the indices. type original array length ------- ----------------

问题 I have the following array with sub arrays [0] through [9]. I want to test the array and see if there is One sub array or more than one. Why? Because sometimes I get one record back from some tables and I have to be able to tell whether I can save it as is or should I use a foreach to save it. I'm building an if-then statement to determine if one record then do x or if there is two or more then do y and use the foreach method. I have yet to be able to isolate the sub array and count them

问题 In python lists can be sliced like this x[4:-1] to get from the fourth to the last element. In R something similar can be accomplished for vectors with x[4:length(x)] and for multidimensional arrays with something like x[,,,,4:dim(x)[5],,,] . Is this more elegant syntax for array slicing for a particular dimension from an element in the middle to the last element? Thanks 回答1: You could use the drop elements syntax: > (1:10)[-(1:4)] [1] 5 6 7 8 9 10 回答2: In case you are interested in slicing

问题 This question already has answers here : Find unique rows in numpy.array (20 answers) Closed 3 years ago . I have 3D numpy array and I want only unique 2D-sub-arrays. Input: [[[ 1 2] [ 3 4]] [[ 5 6] [ 7 8]] [[ 9 10] [11 12]] [[ 5 6] [ 7 8]]] Output: [[[ 1 2] [ 3 4]] [[ 5 6] [ 7 8]] [[ 9 10] [11 12]]] I tried convert sub-arrays to string (tostring() method) and then use np.unique, but after transform to numpy array, it deleted last bytes of \x00, so I can't transform it back with np.fromstring

问题 I have this multidimensional array: Array ( [0] => Array ( [0] => 2012-02-26 07:15:00 ) [1] => Array ( [0] => 2012-02-26 17:45:00 [1] => 2012-02-26 18:55:00 ) [2] => Array ( [0] => 2012-02-26 18:55:00 [1] => 2012-02-26 17:45:00 ) [3] => Array ( [0] => 2012-02-26 18:57:00 [1] => 2012-02-26 17:45:00 [2] => 2012-02-26 18:55:00 ) When I count subarrays I get this 1,2,2,3. How could I receive it in 3,2,2,1? I need to get for example last 3 subarrays with the highest subarray count (DESC, it means

问题 I've found different versions of heap sort for python, but I can't seem to find the one that matches my needs. Iterative Heap Sort is the closest I found, but I can't quite figure out how to change it to work with a sub-list (index start, index end) and remain in place. If I get it right then I'll post my answer here. If anyone has an implementation in even C or Java that will be great. 回答1: I managed to do what I want. This code works on objects and sorts by a specific attribute. def

问题 Given two arrays as parameters (x and y) and find the starting index where the first occurrence of y in x. I am wondering what the simplest or the fastest implementation would be. Example: when x = {1,2,4,2,3,4,5,6} y = {2,3} result starting index should be 3 Update: Since my code is wrong I removed it from the question. 回答1: Here is a simple (yet fairly efficient) implementation that finds all occurances of the array, not just the first one: static class ArrayExtensions { public static

问题 I am using the following array structure to create a tableView with sections struct words { var sectionName : String! var coptic : [String]! var english : [String]! } var array = [words]() var filtered = [words]() array = [words(sectionName: "", coptic: [""], English: [""])] I want to utilize a searchcontroller using similar code to this func updateSearchResults(for searchController: UISearchController) { // If we haven't typed anything into the search bar then do not filter the results if