strlen

strcpy, strdup, strcat, strncpy, strndup

本小妞迷上赌 提交于 2020-01-10 12:32:26
http://hi.baidu.com/liuhuman/item/c862c932b272d020b3c0c532 char* strcpy (char* dst, const char* src); //如果dst的长度 小于或者等于 strlen(src)时, src多余的字符串仍然被复制,将覆盖原先存储于数组后面的内存空间的值。 char* strdup(const char* src); //这个函数包含了malloc和strcpy, 不用担心在strcpy中dst的长度问题 char* strcat(char* dst, cosnt char* src); // 需要保证dst的大小足至少是strlen(dst) + strlen(src) + 1,否则数组溢出。 char* strncpy(char* dst, const char* src, size_t len); // 它总是正好向dst写入len个字符。 如果strlen(src) 小于 len , dst数组就用额外的'\0'填充到len个长度。 如果strlen(src) 大于或者等于 len, 那么只有len个字符被复制到dst中。注意: 它的结果将不会以'\0'结束 char* strndup(const char* src, size_t len); //复制len个字符串,它比strcpy好在:

Strlen returns unreasonable number

耗尽温柔 提交于 2020-01-10 05:46:11
问题 If I write: char lili [3]; cout<<strlen(lili)<<endl; then what is printed is : 11 but if I write: char lili [3]; lili [3]='\0'; cout<<strlen(lili)<<endl; then I get 3. I don't understand why it returns 11 on the first part? Isn't strlen supposed to return 3, since I allocated 3 chars for lili ? 回答1: It is because strlen works with "C-style" null terminated strings. If you give it a plain pointer or uninitialised buffer as you did in your first example, it will keep marching through memory

php加密解密函数大全

坚强是说给别人听的谎言 提交于 2020-01-09 21:54:33
第一种: <?php function encryptDecrypt($key, $string, $decrypt){ if($decrypt){ $decrypted = rtrim(mcrypt_decrypt(MCRYPT_RIJNDAEL_256, md5($key), base64_decode($string), MCRYPT_MODE_CBC, md5(md5($key))), "12"); return $decrypted; }else{ $encrypted = base64_encode(mcrypt_encrypt(MCRYPT_RIJNDAEL_256, md5($key), $string, MCRYPT_MODE_CBC, md5(md5($key)))); return $encrypted; } } //加密:"z0JAx4qMwcF+db5TNbp/xwdUM84snRsXvvpXuaCa4Bk=" echo encryptDecrypt('password', 'Helloweba欢迎您',0); //解密:"Helloweba欢迎您" echo encryptDecrypt('password', 'z0JAx4qMwcF+db5TNbp/xwdUM84snRsXvvpXuaCa4Bk=',1); ?> 第二种 <?php //加密函数

林大OJ习题 2020年1月7日

三世轮回 提交于 2020-01-08 02:16:01
合并字符串 (也可以直接使用函数 strcat()) # include <stdio.h> # include <stdlib.h> # include <string.h> int main ( ) { char a [ 100 ] , b [ 100 ] ; int n , m , i , j ; while ( scanf ( "%s %s" , a , b ) != EOF ) { getchar ( ) ; n = strlen ( a ) ; m = strlen ( b ) ; for ( i = 0 ; i < m ; i ++ ) { if ( b [ i ] != '\0' ) { a [ n ] = b [ i ] ; n ++ ; } else { break ; } } a [ n ] = '\0' ; for ( j = 0 ; j < n ; j ++ ) { printf ( "%c" , a [ j ] ) ; } printf ( "\n" ) ; } return 0 ; } 来源: CSDN 作者: neuer_yao 链接: https://blog.csdn.net/neuer_yao/article/details/103882184

Count consecutive occurence of specific, identical characters in a string - PHP

元气小坏坏 提交于 2020-01-07 03:09:08
问题 I am trying to calculate a few 'streaks', specifically the highest number of wins and losses in a row, but also most occurences of games without a win, games without a loss. I have a string that looks like this; 'WWWDDWWWLLWLLLL' For this I need to be able to return: Longest consecutive run of W charector (i will then replicate for L) Longest consecutive run without W charector (i will then replicate for L) I have found and adapted the following which will go through my array and tell me the

一些常用函数:memset、memcpy、strlen、strcpy

风格不统一 提交于 2020-01-06 14:48:39
memset一般用作初始化函数。作用是将某一块内存中的内容全部设置为某一值。 格式:起始指针、设定的初始值、长度 memset ( buffer , 0 , sizeof ( int ) * 10 ) ; //在buffer处初始化10个0 memcpy用于从源内存地址的起始位置开始拷贝若干个字节到目标内存地址。 格式:返回指针,源指针、长度 memcpy ( dst , src , strlen ( src ) + 1 ) ; strlen是计算字符串长度的函数,从内存任意位置开始到’\0’为止的字符数量,一般比sizeof得到的少1。 格式:字符串指针 strlen ( str ) ; strcpy是字符串拷贝函数,把含有’\0’结束符的字符串复制到另一个地址空间。 格式:返回指针,源指针 strcpy ( dst , src ) ; 来源: CSDN 作者: 海洋之心。 链接: https://blog.csdn.net/weixin_42979679/article/details/103846996

sizeof()和strlen()的区别

主宰稳场 提交于 2020-01-05 13:50:43
1、#include<iostream> 运算符 sizeof 功能:计算可见字符串包括 '\0’的s的长度 sizeof是C/C++中的一个操作符(operator),简单的说其作用就是返回一个对象或者类型所占的内存字节数 2、strlen是一个函数 #include <string.h> int strlen(char *s) 功能:计算可见字符串s的长度 说明:返回s的长度,不包括结束符NULL int strlen(const char *str) {   int len = 0; assert(str != NULL); while(*str++) { len++; } return len; } 由函数原型可以知道: strlen所作的仅仅是一个计数器的工作,它从内存的某个位置(可以是字符串开头,中间某个位置,甚至是某个不确定的内存区域)开始扫描,直到碰到第一个字符串结束符'\0'为止,然后返回计数器值。 来源: https://www.cnblogs.com/briskzou/p/12152197.html

php与java通用AES加密解密算法

让人想犯罪 __ 提交于 2020-01-04 03:41:32
AES指高级加密标准(Advanced Encryption Standard),是当前最流行的一种密码算法,在web应用开发,特别是对外提供接口时经常会用到,下面是我整理的一套php与java通用的AES加密解密算法。 php版代码如下: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 <?php

Why use “strlen30()” instead of “strlen()”?

时光毁灭记忆、已成空白 提交于 2020-01-03 08:53:11
问题 I've read and wondered about the source code of sqlite static int strlen30(const char *z){ const char *z2 = z; while( *z2 ){ z2++; } return 0x3fffffff & (int)(z2 - z); } Why use strlen30() instead of strlen() (in string.h)?? 回答1: The commit message that went in with this change states: [793aaebd8024896c] part of check-in [c872d55493] Never use strlen(). Use our own internal sqlite3Strlen30() which is guaranteed to never overflow an integer. Additional explicit casts to avoid nuisance warning

Why use “strlen30()” instead of “strlen()”?

大兔子大兔子 提交于 2020-01-03 08:52:22
问题 I've read and wondered about the source code of sqlite static int strlen30(const char *z){ const char *z2 = z; while( *z2 ){ z2++; } return 0x3fffffff & (int)(z2 - z); } Why use strlen30() instead of strlen() (in string.h)?? 回答1: The commit message that went in with this change states: [793aaebd8024896c] part of check-in [c872d55493] Never use strlen(). Use our own internal sqlite3Strlen30() which is guaranteed to never overflow an integer. Additional explicit casts to avoid nuisance warning