string

问题 I am trying to use reflection to set a pointer. elasticbeanstalk.CreateEnvironmentInput has a field SolutionStackName which is of type *string . I am getting the following error when I try to set any value: panic: reflect: call of reflect.Value.SetPointer on ptr Value Here is my code: ... newEnvCnf := new(elasticbeanstalk.CreateEnvironmentInput) checkConfig2(newEnvCnf, "SolutionStackName", "teststring") ... func checkConfig2(cnf interface{}, key string, value string) bool { log.Infof("key %v,

问题 If I do args.svc_name, I was expecting equivalent to args.option1, because the svc_name's value is option1. But i got error for "'Namespace' object has no attribute 'svc_name's'" parser = argparse.ArgumentParser(prog=None,description="test") parser.add_argument("--option1", nargs="?",help="option") args = parser.parse_args() svc_name = "option1" print (args.svc_name) Can someone help me out? 回答1: The ArgumentParser class exposes the keys as direct attributes rather than a mapping, so to get

问题 Quick little question... I need to count the length of a string, but WITHOUT the spaces inside of it. E.g. for a string like "I am Bob", string.Length would return 8 (6 letters + 2 spaces). I need a method, or something, to give me the length (or number of) just the letters (6 in the case of "I am Bob") I have tried the following s.Replace (" ", ""); s.Replace (" ", null); s.Replace (" ", string.empty); to try and get "IamBob", which I did, but it didn't solve my problem because it still

问题 Quick little question... I need to count the length of a string, but WITHOUT the spaces inside of it. E.g. for a string like "I am Bob", string.Length would return 8 (6 letters + 2 spaces). I need a method, or something, to give me the length (or number of) just the letters (6 in the case of "I am Bob") I have tried the following s.Replace (" ", ""); s.Replace (" ", null); s.Replace (" ", string.empty); to try and get "IamBob", which I did, but it didn't solve my problem because it still

问题 Quick little question... I need to count the length of a string, but WITHOUT the spaces inside of it. E.g. for a string like "I am Bob", string.Length would return 8 (6 letters + 2 spaces). I need a method, or something, to give me the length (or number of) just the letters (6 in the case of "I am Bob") I have tried the following s.Replace (" ", ""); s.Replace (" ", null); s.Replace (" ", string.empty); to try and get "IamBob", which I did, but it didn't solve my problem because it still

问题 When i run the following program it prints only equals says they are equal However From equalsIgnoreCase docs in java 8 we have : Two characters c1 and c2 are considered the same ignoring case if at least one of the following is true: • Applying the method java.lang.Character.toUpperCase(char) to each character produces the same result public class Test { public static void main(String[] args) { String string1 = "abc\u00DF"; String string2 = string1.toUpperCase(); if (string1.equalsIgnoreCase

问题 When i run the following program it prints only equals says they are equal However From equalsIgnoreCase docs in java 8 we have : Two characters c1 and c2 are considered the same ignoring case if at least one of the following is true: • Applying the method java.lang.Character.toUpperCase(char) to each character produces the same result public class Test { public static void main(String[] args) { String string1 = "abc\u00DF"; String string2 = string1.toUpperCase(); if (string1.equalsIgnoreCase

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 5 days ago . Improve this question Recreating java.lang.String is not hard. See attached code. I'm really writing this to show how easy it is. If anybody wants to figure out how to get the native isBigEndian() and add it in the solutions, that'd be great. Other String methods would be great too. Just put this

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 5 days ago . Improve this question Recreating java.lang.String is not hard. See attached code. I'm really writing this to show how easy it is. If anybody wants to figure out how to get the native isBigEndian() and add it in the solutions, that'd be great. Other String methods would be great too. Just put this

问题 This question already has answers here : Finding the variable name passed to a function (17 answers) Closed last month . Considering this code: string variable = "hello"; myMethod(variable) //usage 1 myMethod("hello") //usage 2 Can I detect the difference between the these method usage above? 回答1: Requiring debug info generated (anything but none, in debug as well as in release build mode), having the source code and to deploy it, and using Finding the variable name passed to a function