string-split

Splitting string using boost spirit

半世苍凉 提交于 2019-12-04 18:44:55
Is it a good idea? For a reason I thought it should be faster than boost's tokenizer or split. however most of the time I'm stuck in the boost::spirit::compile template <typename Iterator> struct ValueList : bsq::grammar<Iterator, std::vector<std::string>()> { ValueList(const std::string& sep, bool isCaseSensitive) : ValueList::base_type(query) { if(isCaseSensitive) { query = value >> *(sep >> value); value = *(bsq::char_ - sep); } else { auto separator = bsq::no_case[sep]; query = value >> *(separator >> value); value = *(bsq::char_ - separator); } } bsq::rule<Iterator, std::vector<std:

Split string using regular expression in Go

╄→гoц情女王★ 提交于 2019-12-04 02:59:35
问题 I'm really new to Go, and have been enjoying it so far. I'm trying to find a good way to split a string using a regular expression instead of a string. Thanks http://nsf.github.com/go/strings.html?f:Split! 回答1: If you just want to split on certain characters, you can use strings.FieldsFunc , otherwise I'd go with regexp.FindAllString . 回答2: I made a regex-split function based on the behavior of regex split function in java, c#, php.... It returns only an array of strings, without the index

T-SQL Split string into many-to-one relationship?

独自空忆成欢 提交于 2019-12-03 20:55:24
I have the following SQL script: DECLARE @temp table ( ID int IDENTITY(1, 1), data nvarchar(100) ) INSERT INTO @temp (data) VALUES ('a,b,c') INSERT INTO @temp (data) VALUES ('d,e,f') SELECT * FROM @temp AS T INNER JOIN (SELECT * FROM dbo.__StringSplit(T.data, ',', T.ID)) AS S ON T.ID = S.RefID And on after clicking !Execute, I got these: Line 17 The multi-part identifier "T.data" could not be bound. I have also tried the non-join version and got the same error: SELECT T.ID, S.Item AS dataItem FROM @temp AS T, dbo.__StringSplit(T.data, ',', T.ID) AS S WHERE T.ID = S.RefID ... What I expected

Markdown: how to show a preview (such as the first N words)

ぃ、小莉子 提交于 2019-12-02 21:29:38
问题 I am using Rails 4 and Kramdown, but I believe that this question extends to any (web-) programming language with Markdown support. I am making a blogging website. On the overview page, I want to show the start of each of the articles. As an article can be very long, I only want to show the first part. A bare-bones idea would be to just truncate the article after N characters. A slightly better idea would be to truncate the article after N words. Of course, when dealing with a document that

Regular Expression to Split String based on space and matching quotes in java

别来无恙 提交于 2019-12-02 14:33:16
问题 I have a String which i need to split based on the space and the exact matching quotes. If the string = "It is fun \"to write\" regular\"expression" After the Split i want the result to be : It is fun "to write" regular "expression The regular expression from which i came to some thing close to do this was : STRING_SPLIT_REGEXP = "[^\\s\"']+|\"([^\"]*)\"|'([^']*)'" Thanks in advance for answers. 回答1: It seems that you just used regex from this answer, but as you could see it doesn't use split

Separate values in a column of a dataframe and melt

江枫思渺然 提交于 2019-12-02 13:36:50
问题 I have a data frame where I want to separate values in the Client.ID column and melt, so each row contains one Client.ID and and the corresponding Account.Name and owner. > head(df) Account.Owner Account.Name Client.ID 1 Deb Berman Albertsons LLC 3184, 3186, 3185, 2578 2 Deb Berman All Recipes 909, 4937 3 Liz Madsen American Express 1230,1236 4 Deb Berman Bed Bath & Beyond 1180, 1556 5 Deb Berman Birchbox 101, 1704, 5149, 5150, 5148 6 Jeff Murphy Brown Shoe Company 5402, 6159, 6160 At the end

JavaScript string split by Regex results sub-strings include empty slices

五迷三道 提交于 2019-12-02 11:38:35
I've the following string splitting JavaScript code: var formula = "(field1 + field2) * (field5 % field2) / field3"; console.log(formula.split(/[+(-)% *\/]/)); And the result is out of expectation: ["", "field1", "", "", "field2", "", "", "", "", "field5", "", "", "field2", "", "", "", "field3"] What the desired result would be: ["field1", "field2", "field5", "field2", "field3"] I'm using Google Chrome 11 official release as the testing browser, please kindly advise what I'm doing wrong. Thank you! William Instead of splitting on /[+(-)% *\/]/ split on more than one: /[+(-)% *\/]+/ . You still

need to get desired data from string using batch

时光怂恿深爱的人放手 提交于 2019-12-02 08:58:31
问题 i need to extract only URL and app id in the given string and saved in variables url:{ "url":"ad.ifwcash.com/www/delivery/afr.php?zoneid=127&cb=2015738640", "app":61} final result like variable_1 : ad.ifwcash.com/www/delivery/afr.php?zoneid=127&cb=2015738640 variable_2 : 61 回答1: Here's another hybrid solution using JScript. (Still save it with a .bat extension.) @if (@CodeSection == @Batch) @then @echo off setlocal set "JSONfile=test.json" for /f "delims=" %%I in ('cscript /nologo /e:JScript

Markdown: how to show a preview (such as the first N words)

会有一股神秘感。 提交于 2019-12-02 08:39:36
I am using Rails 4 and Kramdown, but I believe that this question extends to any (web-) programming language with Markdown support. I am making a blogging website. On the overview page, I want to show the start of each of the articles. As an article can be very long, I only want to show the first part. A bare-bones idea would be to just truncate the article after N characters. A slightly better idea would be to truncate the article after N words. Of course, when dealing with a document that contains additional markup, such as markdown, this can and will break stuff, so another solution is

Empty check with string split

感情迁移 提交于 2019-12-02 08:29:13
vector<string> SplitString (string aString,char *sep) { vector<string> vec; char * cstr,*val,*p; string str = aString; cstr = new char [str.size()+1]; strcpy (cstr, str.c_str()); p=strtok (cstr,sep); while(p!=NULL) { vec.push_back(p); p=strtok(NULL,sep); }delete[] cstr;return vec; } This is my code to string split. I sent the below string to split with separator '&' "f0=fname0&l0=lname0&f1=fname1&l1=lname1&f2=fname2&l2=lname2&f3=&l3=". I got result in the vector as below. f0=fname0 l0=lname0 f1=fname1 l1=lname1 f2=fname2 l2=lname2 f3= l3= Now I again the sent the resulted strings with