strict

问题 This is brand new install - I have not put any transitions on the Alert component To replicate the code it is simple import React from "react"; import { Alert } from "reactstrap"; export const Index = () => { return ( <div> <Alert color='primary'>This is a primary alert — check it out!</Alert> </div> ); }; Error Msg: Please update the following components: Transition How does one go about updating Transition or eliminating it all together? 回答1: I have this same warning, and I fixed it

问题 This is brand new install - I have not put any transitions on the Alert component To replicate the code it is simple import React from "react"; import { Alert } from "reactstrap"; export const Index = () => { return ( <div> <Alert color='primary'>This is a primary alert — check it out!</Alert> </div> ); }; Error Msg: Please update the following components: Transition How does one go about updating Transition or eliminating it all together? 回答1: I have this same warning, and I fixed it

问题 This is brand new install - I have not put any transitions on the Alert component To replicate the code it is simple import React from "react"; import { Alert } from "reactstrap"; export const Index = () => { return ( <div> <Alert color='primary'>This is a primary alert — check it out!</Alert> </div> ); }; Error Msg: Please update the following components: Transition How does one go about updating Transition or eliminating it all together? 回答1: I have this same warning, and I fixed it

问题 As I understand it, --strictFunctionTypes compiler option in Typescript prevents a very common use case of polymorphism from working: type Handler = (request: Request) => Response const myHandler: Handler = (request: Request & { extraArg: boolean }) => { return !!request.extraArg } Generally, I assume that all compiler options in the strict family have some great benefits, but in this case, all I see is that it prevents a very logical behavior from working. So what are the cases where this

问题 As I understand it, --strictFunctionTypes compiler option in Typescript prevents a very common use case of polymorphism from working: type Handler = (request: Request) => Response const myHandler: Handler = (request: Request & { extraArg: boolean }) => { return !!request.extraArg } Generally, I assume that all compiler options in the strict family have some great benefits, but in this case, all I see is that it prevents a very logical behavior from working. So what are the cases where this

问题 As I understand it, --strictFunctionTypes compiler option in Typescript prevents a very common use case of polymorphism from working: type Handler = (request: Request) => Response const myHandler: Handler = (request: Request & { extraArg: boolean }) => { return !!request.extraArg } Generally, I assume that all compiler options in the strict family have some great benefits, but in this case, all I see is that it prevents a very logical behavior from working. So what are the cases where this

问题 Is there any recommend guidelines when to use strictness in Haskell ? For example, I was looking on the tagsoup library. They have one of their data structure defined like this: data Tag str = TagOpen str [Attribute str] | TagClose str | TagText str | TagComment str | TagWarning str | TagPosition !Row !Column type Row = Int type Column = Int So on what factor exactly do they decide that TagPosition should be strict ? Are there any recommend guidelines for this ? 回答1: For simple, unstructured

问题 Suppose you have a routine like the following to wire up click event handlers getElements(".board>div").forEach(function(elem){ elem.addEventListener("click", handleClick); }); And then in the handler, you need to work with the sender (i.e. this) function handleClick(){ if(this.innerText.toLowerCase() !== "x"){ ... How do you use this in this scenario without a jshint violation/warning? 回答1: Your use of this is valid. To suppress the this errors in your event handler add /*jshint validthis:

问题 Where can I get a summary of differences between ActionScript 3.0 strict and standard mode? In other words, what are the things I can do in standard mode but not in strict mode? 回答1: Damn, I was trying to remember all night long where I've seen theses differences and I suddenly had a total recall in the shower this morning :p http://books.google.fr/books?id=gUHX2fcLKxYC&pg=PA135&lpg=PA135&dq=essential+actionscript+3.0+compiler+standard+strict&source=bl&ots=cuTT2kfUE-&sig

问题 I have the following Haskell type definition: import Data.Sequence(Seq, length) import Data.ByteString.UTF8(ByteString) type StringSeq = Seq ByteString I have expressions of type StringSeq for which I would like to force strict evaluation with deepseq . So I need to define instances of NFData . I did the following: import Control.DeepSeq(NFData, deepseq) instance NFData ByteString instance NFData a => NFData (Seq a) where rnf s = rnf (length s) So I compute the length of a sequence to force