strftime | 易学教程

How do you set a strftime with javascript?

阅读更多关于 How do you set a strftime with javascript?

问题 I need to custom format dates. In ruby, I would use strftime, or string formatted time, to accomplish this. now = Time.new now.strftime '%a, %d of %b' #=> "Sat, 27 of Jun" Does javascript use strftime or some equivalent? How can I get a similar effect in javascript? 回答1: UPDATE Arguments of toLocaleString method can also configure the format of the dates. This is supported in modern browser versions, you can see more information here. let date = new Date(Date.UTC(2015, 5, 27, 12, 0, 0)) ,

How do I pass Shell parameters to Perl script?

阅读更多关于 How do I pass Shell parameters to Perl script?

问题 I am trying to find dates with in a certain format, I have done it before with perl( strftime ), but that time I mentioned a static time, this time i need a variable $CURRENT_DAY here. Below is the issue, when equate the CURRENT_DAY by using DAYHOUR=86400 and an integer, the variable is giving the right time, but once I put $CURRENT_DAY variable in the statement, the date would not decrease. $ DAYHOUR=86400 $ DAY=1 $ CURRENT_DAY=`echo $(($DAYHOUR*$DAY))` $ DD=`perl -e 'use POSIX; print

How to create a video from frames named using timestamp with ffmpeg

阅读更多关于 How to create a video from frames named using timestamp with ffmpeg

问题 I have a folder filled with frames that have the timestamp in the name in the folowing format im_%H_%M_%S_%MS.png im_08_05_09_007324.png im_08_05_09_532857.png im_08_05_10_059340.png im_08_05_10_575862.png im_08_05_11_118361.png im_08_05_11_596814.png im_08_05_12_148340.png im_08_05_12_665838.png I try to use -pattern_type glob in windows but it does not work. ffmpeg.exe -framerate 10 -pattern_type glob -i im_*.png -c:v libx264 -r 30 -vf "scale=trunc(iw/2)*2:trunc(ih/2)*2" -pix_fmt yuv420p

strptime defaulting to 1900

阅读更多关于 strptime defaulting to 1900

问题 from datetime import datetime datetime.strptime('%b%d %I:%M%p', 'AUG21 3:26PM') results with 1900-08-21 15:26:00 how can I write in pythonic way so that when there's no year, take the current year as default (2013)? I checked and strftime function doesn't have option to change the default.. maybe another time libraries can do? thx 回答1: Parse the date as you are already doing, and then date= date.replace(2013) This is one of simplest solution with the modules you are using. Thinking better

How do I add together all numbers from the same week into a list?

阅读更多关于 How do I add together all numbers from the same week into a list?

来源： https://stackoverflow.com/questions/64312442/how-do-i-add-together-all-numbers-from-the-same-week-into-a-list

How do I add together all numbers from the same week into a list?

阅读更多关于 How do I add together all numbers from the same week into a list?

来源： https://stackoverflow.com/questions/64312442/how-do-i-add-together-all-numbers-from-the-same-week-into-a-list

Making a list of months and years from DatetimeIndex in Pandas

阅读更多关于 Making a list of months and years from DatetimeIndex in Pandas

问题 I have a dataframe of information. I set the index to be the received date and time. Now I want a list I set the df index doing this: df.index = pd.to_datetime(df.index, format='%m/%d/%Y %H:%M') which gives me this: print df.index <class 'pandas.tseries.index.DatetimeIndex'> [2014-07-28 09:42:08, ..., 2015-07-28 09:06:12] Length: 15177, Freq: None, Timezone: None I want a list of the month and years in order to use them to plot, like so: ["Jan 2015", "Feb 2015", "Mar 2015", "Apr 2015", "May

Python的datetime模块分析

阅读更多关于 Python的datetime模块分析

datetime模块用于是date和time模块的合集，datetime有两个常量，MAXYEAR和MINYEAR，分别是9999和1. datetime模块定义了5个类，分别是 1.datetime.date：表示日期的类 2.datetime.datetime：表示日期时间的类 3.datetime.time：表示时间的类 4.datetime.timedelta：表示时间间隔，即两个时间点的间隔 5.datetime.tzinfo：时区的相关信息一、首先看一下datetime.date类： date类有三个参数,datetime.date(year,month,day)，返回year-month-day 方法： 1.datetime.date.ctime(),返回格式如 Sun Apr 16 00:00:00 2017 2.datetime.date.fromtimestamp(timestamp),根据给定的时间戮，返回一个date对象；datetime.date.today()作用相同 3.datetime.date.isocalendar():返回格式如(year，month，day)的元组,(2017, 15, 6) 4.datetime.date.isoformat()：返回格式如YYYY-MM-DD 5.datetime.date.isoweekday()

python time模块和datetime模块

阅读更多关于 python time模块和datetime模块

python time模块和datetime模块一、time模块 time模块中时间表现的格式主要有三种：　　a、timestamp时间戳，时间戳表示的是从1970年1月1日00:00:00开始按秒计算的偏移量　　b、struct_time时间元组，共有九个元素组。　　c、format time 格式化时间，已格式化的结构使时间更具可读性。包括自定义格式和固定格式。 1、时间格式转换图： 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 #! /usr/bin/env python # -*- coding:utf-8 -*- # __author__ = "TKQ" import time # 生成timestamp time.time() # 1477471508.05 #struct_time to timestamp time.mktime(time.localtime()) #生成struct_time # timestamp to struct_time 本地时间 time.localtime() time.localtime(time.time()) # time.struct_time(tm_year

实验三 Linux系统用户管理及VIM配置

阅读更多关于实验三 Linux系统用户管理及VIM配置

实验三 Linux系统用户管理及VIM配置项目内容这个作业属于哪个课程班级课程主页这个作业的要求在哪里作业要求学号-姓名 17041422-王骁阳作业学习目标 (1)学习Linux系统用户管理(2)学习vim使用及配置实验内容 Linux用户管理简答：Linux系统为什么应避免使用root用户登录？答：1.对用户进行限制 2.root权限可能会无意造成危害操作 1）如何在与用户有关的三个文件中查看当前用户的信 cat /etc/passwd | grep xiaoyang #查看用户xiaoyang的用户信息请简要描述这三个文件？ /etc/passwd 这个文件存放着所有用户账号的信息 /etc/group 这个文件是用户组的配置文件 /etc/shadow 这个文件存放着密码数据 2）用id命令查看当前用户相关信息请简要描述输出结果？ uid=0(root)#用户id gid=0(root)#组id groups=0(root) #组名称 3）创建两个账号，一个账号为test,另外一个账号以大写E开头加上你自己学号尾数4位，两个账号分别设置密码及管理员权限，账号设置完成后，切换账号简单查看信息后，删除test账号，保留另一账号，以备后续操作。 a)创建账号 b) 设置密码 c)设置权限请简要描述用户组的概念？管理员组：root 普通用户组系统组