strcpy | 易学教程

Char and strcpy in C

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问题 I came across a part of question in which, I am getting an output, but I need a explanation why it is true and does work? char arr[4]; strcpy(arr,"This is a link"); printf("%s",arr); When I compile and execute, I get the following output. Output: This is a link 回答1: The short answer why it worked (that time) is -- you got lucky. Writing beyond the end of an array is undefined behavior . Where undefined behavior is just that, undefined , it could just a easily cause a segmentation fault as it

C++ How to populate a static array of strings with new strings in different locations?

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问题 Say I got this char* MapIds[5000] = { "Northeast Asia","Hanyang","Pusan","Pyongyang","Shanghai","Beijing","Hong Kong", /*...5000 values etc../* }; I tried strcpy(MapIds[0], "gfggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg"); But it crashes How Do I keep changing them around without messing up the strings in other elements. I dont want to use std::string or vector those cause crazy slow compile times. 回答1: Because you try to copy into a

Modifying a String (char array) [closed]

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问题 Closed. This question needs debugging details. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 11 months ago . Improve this question I am trying to modify a string in C language char signal_cat[8]; if (k == 1) { strcpy_s(signal_cat, "HPHA",6); //why cant I change char array (string) values??? } else if (k == 2) { strcpy_s(signal_cat, "Normal",6); } printf("Original signal category: %s \n", signal_cat); When

Modifying a String (char array) [closed]

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How to add null terminator to char pointer, when using strcpy

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来源： https://stackoverflow.com/questions/28676223/how-to-add-null-terminator-to-char-pointer-when-using-strcpy

How to add null terminator to char pointer, when using strcpy

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来源： https://stackoverflow.com/questions/28676223/how-to-add-null-terminator-to-char-pointer-when-using-strcpy

How to add null terminator to char pointer, when using strcpy

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来源： https://stackoverflow.com/questions/28676223/how-to-add-null-terminator-to-char-pointer-when-using-strcpy

What exactly is -fno-builtin doing here?

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问题 So I was reading Hacking the Art of Exploitation and in the book, they use the strcpy() function in their C code: 1 #include <stdio.h> 2 #include <string.h> 3 4 int main() { 5 char str_a[20]; 6 7 strcpy(str_a, "Hello, world!\n"); 8 printf(str_a); 9 } They then proceed to compile their source code and analyze it with gdb . He sets a breakpoint on line 6, the strcpy function, and line 8, but when setting a break on strcpy it reads the following: (gdb) break strcpy Function "strcpy" not defined.

C语言字符串

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目录一、字符串的概念二、占用内存的情况三、字符串的初始化四、字符串与指针五、字符串的结尾标志六、字符串的输出七、字符串越界八、字符串常用的库函数 1、获取字符串的长度（strlen） 2、字符串复制或赋值（strcpy） 3、字符串复制或赋值（strncpy） 4、字符串拼接（strcat） 5、字符串拼接（strncat） 6、字符串比较（strcmp、strncmp） 7、字符查找（strchr、strrchr） 8、字符串查找（strstr）九、应用经验 1、留有余地 2、变量初始化 3、位置（地址）偏移的用法 4、不要在子函数中对字符指针用sizeof 十、课后作业十一、版权声明在很多教程中，字符串不过是一个以0结束的字符数组，但是，在我看来，字符串虽然不是C语言基本数据类型，但它比任何数据类型都重要，因为字符串是最常用的数据。一、字符串的概念我们可以把字符串储存在char类型的数组中，如果char类型的数组末尾包含一个表示字符串末尾的空字符\0，则该数组中的内容就构成了一个字符串。因为字符串需要用\0结尾，所以在定义字符串的时候，字符数组的长度要预留多一个字节用来存放\0，\0就是数字0。这是约定。 char strname[21]; // 定义一个最多存放20个英文字符或十个中文的字符串字符串也可以存放中文和全角的标点符号

笔记strlen() ，sizeof(),strcpy(),strncpy(),strcat()

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strlen函数的意思是测试字符串的字符长度，不含字符串结束标志的。 int strlen( const char *str) { assert(str != NULL); int len; while((*str++) != '\0') { len++; } return len; } sizeof是运算符，它的结果是字符串在内存中的所占字节大小，它要把\0算进去的。 strcpy函数原型 ( strcpy(s1,s2); strcpy函数的意思是：把字符串s2中的内容copy到s1中，连字符串结束标志也一起copy ) char *strcpy(char *strDest, const char *strSrc)//strDest为目标,strSrc为源 { assert((strDest!=NULL) && (strSrc !=NULL)); //如果两个为空则不用复制,直接中止 char *address = strDest; //用address指向strDest开始地址 while( (*strDest++ = * strSrc++) != ‘\0’ ) //复制,直到源串结束; NULL ; //空操作 return address ; //返回strDest开始地址 } } strncpy函数：利用标准库函数strncpy()，可以