std-bitset

sending bitset with MPI

自作多情 提交于 2019-12-25 12:06:18
问题 What is an efficient way to send/receive bits from bitset class without conversion. Is it possible to use MPI_BYTE? If so, what to define as container for the array that is going to hold the bits? If this is not possible, which conversion is more efficient, conversion to ulong or to strings? 回答1: Convert it to array of "bool" and send by MPI_BYTE, this method works on cluster. 来源: https://stackoverflow.com/questions/43263598/sending-bitset-with-mpi

Bitset as the return value of a function

风流意气都作罢 提交于 2019-12-23 23:55:21
问题 I'd like to have an interface whose function returns a bitset: class IMyInterface { public: virtual std::bitset<100> GetBits() = 0; }; The problem is that I don't want to force the size of the bitset . So I think I have to use boost::dynamic_bitset instead: class IMyInterface { public: virtual boost::dynamic_bitset<> GetBits() = 0; }; I have heard that boost::dynamic_bitset is slower than std::bitset though. Is there any other way to avoid using dynamic_bitset and have an interface that

Structure padding with union members of std::bitset

给你一囗甜甜゛ 提交于 2019-12-13 23:56:36
问题 After I had solved my issue to this question I went on to expand this version of my code to incorporate the unions of the data fields from my previous template versions with this version and I have this so far: main.cpp #include <iostream> #include <type_traits> #include "Register.h" int main() { using namespace vpc; std::cout << std::boolalpha; std::cout << "std::bitset<64> is trivially copyable " << std::is_trivially_copyable<std::bitset<64>>::value << '\n' << "QWord is trivially copyable "

Overload the shift operators of std::bitset

亡梦爱人 提交于 2019-12-11 03:37:48
问题 I'd like to use the shift operators as doing a bit rotation instead of their actual bit shift. This is my expected behavior: std::bitset<8> b8("1010"); // b8 = 00001010 b8 <<= 5; // b8 = 01000001 So I try and overloaded the <<= operator, referencing the bitset definition, as followed: #include <iostream> #include <bitset> using namespace std; template <size_t size> bitset<size>& bitset<size>::operator<< (size_t pos) noexcept { // an error at here } I've got an error at keyword operator : Out

Are enums the canonical way to implement bit flags?

放肆的年华 提交于 2019-12-05 15:30:25
问题 Currently I'm using enums to represent a state in a little game experiment. I declare them like so: namespace State { enum Value { MoveUp = 1 << 0, // 00001 == 1 MoveDown = 1 << 1, // 00010 == 2 MoveLeft = 1 << 2, // 00100 == 4 MoveRight = 1 << 3, // 01000 == 8 Still = 1 << 4, // 10000 == 16 Jump = 1 << 5 }; } So that I can use them this way: State::Value state = State::Value(0); state = State::Value(state | State::MoveUp); if (mState & State::MoveUp) movement.y -= mPlayerSpeed; But I'm

C++ How can I assign an input value to a std::bitset argument?

≯℡__Kan透↙ 提交于 2019-12-01 20:02:51
问题 I want to make a simple program that will take number of bits from the input and as an output show binary numbers, written on given bits (example: I type 3: it shows 000, 001, 010, 011, 100, 101, 110, 111) . The only problem I get is in the second for -loop, when I try to assign variable in bitset< bits > , but it wants constant number. If you could help me find the solution I would be really greatful. Here's the code: #include <iostream> #include <bitset> #include <cmath> using namespace std

C++ How can I assign an input value to a std::bitset argument?

╄→尐↘猪︶ㄣ 提交于 2019-12-01 19:54:08
I want to make a simple program that will take number of bits from the input and as an output show binary numbers, written on given bits (example: I type 3: it shows 000, 001, 010, 011, 100, 101, 110, 111) . The only problem I get is in the second for -loop, when I try to assign variable in bitset< bits > , but it wants constant number. If you could help me find the solution I would be really greatful. Here's the code: #include <iostream> #include <bitset> #include <cmath> using namespace std; int main() { int maximum_value = 0,x_temp=10; //cin >> x_temp; int const bits = x_temp; for (int i =

XOR bitset when 2D bitset is stored as 1D

老子叫甜甜 提交于 2019-12-01 13:13:55
To answer How to store binary data when you only care about speed? , I am trying to write some to do comparisons, so I want to use std::bitset . However, for fair comparison, I would like a 1D std::bitset to emulate a 2D. So instead of having: bitset<3> b1(string("010")); bitset<3> b2(string("111")); I would like to use: bitset<2 * 3> b1(string("010111")); to optimize data locality. However, now I am having problem with How should I store and compute Hamming distance between binary codes? , as seen in my minimal example: #include <vector> #include <iostream> #include <random> #include <cmath>

XOR bitset when 2D bitset is stored as 1D

隐身守侯 提交于 2019-12-01 11:10:43
问题 To answer How to store binary data when you only care about speed?, I am trying to write some to do comparisons, so I want to use std::bitset . However, for fair comparison, I would like a 1D std::bitset to emulate a 2D. So instead of having: bitset<3> b1(string("010")); bitset<3> b2(string("111")); I would like to use: bitset<2 * 3> b1(string("010111")); to optimize data locality. However, now I am having problem with How should I store and compute Hamming distance between binary codes?, as