static-binding | 易学教程

What are static and dynamic binding in C (strictly C,not C++)?

阅读更多关于 What are static and dynamic binding in C (strictly C,not C++)?

问题 I had initial apprehensions about posting this question lest it be a duplicate.But even after googling with many keywords,I couldn't find any link on StackOverflow that explains static and dynamic binding for C.There are questions and answers for C++ though,but all involve classes and stuff that are clearly not for C.And the links outside StackExchange were quite dubious. I need to know the rigorous definition and contrast between these two bindings,exclusively in the context of C.I would

What are static and dynamic binding in C (strictly C,not C++)?

阅读更多关于 What are static and dynamic binding in C (strictly C,not C++)?

Why static binding works differently for class and function?

阅读更多关于 Why static binding works differently for class and function?

问题 In python (tested on 2.7.6) all variables are statically bound to a scope at compile time. This process is well described in http://www.python.org/dev/peps/pep-0227/ and http://docs.python.org/2.7/reference/executionmodel.html It is explicitly stated that "If a name binding operation occurs anywhere within a code block, all uses of the name within the block are treated as references to the current block." A function is a code block so the following code with fail because x is assigned after

Shallow & Deep Binding - What would this program print?

阅读更多关于 Shallow & Deep Binding - What would this program print?

问题 I'm not sure how to do this... function f1() { var x = 10; function f2(fx) { var x; x = 6; fx(); }; function f3() { print x; }; f2(f3); }; For each of the following two binding methods, what would the program print? A) Shallow Binding B) Deep Binding Thanks for the help! 回答1: Deep/shallow binding makes sense only when a procedure can be passed as an argument to a function. Deep binding binds the environment at the time a procedure is passed as an argument. Shallow binding binds the

Static Vs. Dynamic Binding in Java

阅读更多关于 Static Vs. Dynamic Binding in Java

问题 I'm currently doing an assignment for one of my classes, and in it, I have to give examples, using Java syntax, of static and dynamic binding . I understand the basic concept, that static binding happens at compile time and dynamic binding happens at runtime, but I can't figure out how they actually work specifically. I found an example of static binding online that gives this example: public static void callEat(Animal animal) { System.out.println("Animal is eating"); } public static void

Avoid static binding in operations which use hierarchy arguments

阅读更多关于 Avoid static binding in operations which use hierarchy arguments

问题 I have found an issue about static binding. My real class are very extended, so I will use several toy class to express my problem. We suppose that we have the following hierarchy. public class Element{} public class Element1 extends Element{} public class Element2 extends Element{} I have a Stock class which use the different Element specialization defined by Element hierarchy. public class Stock{ public void operation(Element1 e1){ System.out.println("Operation - " + e1.getClass().getName()

Why static binding works differently for class and function?

阅读更多关于 Why static binding works differently for class and function?

In python (tested on 2.7.6) all variables are statically bound to a scope at compile time. This process is well described in http://www.python.org/dev/peps/pep-0227/ and http://docs.python.org/2.7/reference/executionmodel.html It is explicitly stated that "If a name binding operation occurs anywhere within a code block, all uses of the name within the block are treated as references to the current block." A function is a code block so the following code with fail because x is assigned after its use (so at compile time it is defined local because it is assigned somewhere in the function, but at

Static Binding and Dynamic Binding

阅读更多关于 Static Binding and Dynamic Binding

I am really confused about dynamic binding and static binding. I have read that determining the type of an object at compile time is called static binding and determining it at runtime is called dynamic binding. What happens in the code below: Static binding or dynamic binding? What kind of polymorphism does this show? class Animal { void eat() { System.out.println("Animal is eating"); } } class Dog extends Animal { void eat() { System.out.println("Dog is eating"); } } public static void main(String args[]) { Animal a=new Animal(); a.eat(); } Your example is dynamic binding , because at run

Static Vs. Dynamic Binding in Java

阅读更多关于 Static Vs. Dynamic Binding in Java

I'm currently doing an assignment for one of my classes, and in it, I have to give examples, using Java syntax, of static and dynamic binding . I understand the basic concept, that static binding happens at compile time and dynamic binding happens at runtime, but I can't figure out how they actually work specifically. I found an example of static binding online that gives this example: public static void callEat(Animal animal) { System.out.println("Animal is eating"); } public static void callEat(Dog dog) { System.out.println("Dog is eating"); } public static void main(String args[]) { Animal

What is the difference between Early and Late Binding?

阅读更多关于 What is the difference between Early and Late Binding?

What is the difference between early and late binding? The short answer is that early (or static) binding refers to compile time binding and late (or dynamic) binding refers to runtime binding (for example when you use reflection). James A. Rosen In compiled languages, the difference is stark. Java: //early binding: public create_a_foo(*args) { return new Foo(args) } my_foo = create_a_foo(); //late binding: public create_something(Class klass, *args) { klass.new_instance(args) } my_foo = create_something(Foo); In the first example, the compiler can do all sorts of neat stuff at compile time.