sql-order-by

问题 I have tables/records like this: Table: COMMENTS --------------------------------------------- COMMENT_ID | CONTENT | CREATE_DATE --------------------------------------------- 1 | Content 1 | 2016-09-01 2 | Content 2 | 2016-09-02 3 | Content 3 | 2016-09-03 4 | Reply to Content 2 | 2016-09-04 5 | Reply to Content 1 | 2016-09-05 6 | Reply to Content 2 | 2016-09-03 Table: REPLY_COMMENTS --------------------------------- COMMENT_ID | REPLY_TO_COMMENT_ID --------------------------------- 4 | 2 5 |

问题 I have a question about ordering a SQL table. And I can't find a solution on stack or google. My table "Score" seems as follows: Name Total Tries Game1 Game2 Game3 ------------------------------------------ Sam 65 61 10 31 24 Tom 55 11 30 Jim 65 58 9 34 22 Dan 62 52 10 30 22 Note: "Total" column is COUNT(Game1 + Game2 + Game3). As you can see the Total record of Tom is empty, because Tom didn't play Game2. I want to order my table as follows (highest-lowest priority): Empty cells (at the

问题 Upgrade advisor says "Non-integer constants are not allowed in the ORDER BY clause in 90 or later compatibility mode". But, when I try the below statement in SQL Server 2008 , it works just fine. So, my questions is - What exactly is a non-integer constant? select POS_NO ,EMP_NO ,ORG_NAME ,EMP_LAST_NAME + ', ' + EMP_FIRST_NAME AS "Name" FROM dbo.MyEmpTable ORDER BY "Name" 回答1: Here is what the MSDN have to say about character constant that are in a sense the non-integer constant Character

问题 Here's a neat one for you (MySQL, obviously): # Setting things up DROP DATABASE IF EXISTS index_test_gutza; CREATE DATABASE index_test_gutza; USE index_test_gutza; CREATE TABLE customer_order ( id MEDIUMINT UNSIGNED NOT NULL AUTO_INCREMENT, invoice MEDIUMINT UNSIGNED NOT NULL DEFAULT 0, PRIMARY KEY(id) ); INSERT INTO customer_order (id, invoice) VALUES (1, 1), (2, 2), (3, 3), (4, 4), (5, 5); CREATE TABLE customer_invoice ( id MEDIUMINT UNSIGNED NOT NULL AUTO_INCREMENT, invoice_no MEDIUMINT

问题 I have a view that is joining two tables and ordering by the first table. Except that the order isn't correct. It misses an occasional record, and then at the end, most of those records exist in order, and then at that end, the rest of the records exist in order. So it has records such as 1 (most of the records in order) 2 4 5 6 7 8 10 11 13 15 3 (the first set of missing records) 12 9 (the rest of the missing records) 14 My view is below. Do I need to do the order by before I do the join?

问题 This question already has answers here : Closed 9 years ago . Possible Duplicate: Ordering by the order of values in a SQL IN() clause With a query such as: SELECT * FROM images WHERE id IN (12,9,15,3,1) is it possible to order the results by the contents of the IN clause? The result I'm looking for would be something like: [0] => Array ( [id] => 12 [file_name] => foo ) [1] => Array ( [id] => 9 [file_name] => bar ) [2] => Array ( [id] => 15 [file_name] => baz ) ... 回答1: The IN clause defines

问题 This question already has answers here : Closed 9 years ago . Possible Duplicate: Ordering by the order of values in a SQL IN() clause With a query such as: SELECT * FROM images WHERE id IN (12,9,15,3,1) is it possible to order the results by the contents of the IN clause? The result I'm looking for would be something like: [0] => Array ( [id] => 12 [file_name] => foo ) [1] => Array ( [id] => 9 [file_name] => bar ) [2] => Array ( [id] => 15 [file_name] => baz ) ... 回答1: The IN clause defines

问题 Sorting Alphanumeric field in SQL CE (Compact Edition) version 3.5 TreeNumber is a nvarchar field with a mix of numbers and strings for the values. I want to sort these records so that the records that contain alpha characters are at the top and the rest are sorted in numeric order. I want something similar to the following query which works in SQL Server: SELECT * FROM Tree ORDER BY (CASE WHEN TreeNumber LIKE '%[a-z]%' THEN 0 ELSE TreeNumber END), TreeNumber The above query doesn't seem to

问题 I looked online, but I could only find two queries combined with the same order by . First query: SELECT Name , Priority FROM Music WHERE `Priority` > 0 AND `date` > '2014-10-27 20:04:25' ORDER BY `Priority` DESC Second query: SELECT Name , Priority FROM Music WHERE `Priority` = 0 AND `date` > '2014-10-27 20:04:25' ORDER BY `date` I need to combine the first and the second query into one, where the first query is executed and then the second query is executed giving me a complete list. 回答1:

问题 I am pulling a column in an existing script into my template files, and everything is working great. The only problem is, that this script has a column called order , and every row then has a number in that column to show which should be at the top etc. If I set my query to " ORDER BY name " for example, everything works fine, but when I use " ORDER BY order ", then I get a SQL error. Can I not have a column called order ? I can't change column name, because it's part of the script. Is there