sorting

问题 I need to reorder a sorted list so the "middle" element is the highest number. The numbers leading up to the middle are incremental, the numbers past the middle are in decreasing order. I have the following working solution, but have a feeling that it can be done simpler: foo = range(7) bar = [n for i, n in enumerate(foo) if n % 2 == len(foo) % 2] bar += [n for n in reversed(foo) if n not in bar] bar [1, 3, 5, 6, 4, 2, 0] 回答1: how about: foo[len(foo)%2::2] + foo[::-2] In [1]: foo = range(7)

问题 I need to reorder a sorted list so the "middle" element is the highest number. The numbers leading up to the middle are incremental, the numbers past the middle are in decreasing order. I have the following working solution, but have a feeling that it can be done simpler: foo = range(7) bar = [n for i, n in enumerate(foo) if n % 2 == len(foo) % 2] bar += [n for n in reversed(foo) if n not in bar] bar [1, 3, 5, 6, 4, 2, 0] 回答1: how about: foo[len(foo)%2::2] + foo[::-2] In [1]: foo = range(7)

问题 I am trying to sort a class array that has 5 values inside of it. 3 strings and 2 ints . I would like to sort the array from highest to lowest on the int values but can't figure out how to do so. My though process is to send the array into the class and then pull out the correct int value and sort for each array location without changing the other values of that location. How can I pull out these values so that I can sort them accordingly? If I could then I would know how to finish my code.

问题 I am trying to sort a class array that has 5 values inside of it. 3 strings and 2 ints . I would like to sort the array from highest to lowest on the int values but can't figure out how to do so. My though process is to send the array into the class and then pull out the correct int value and sort for each array location without changing the other values of that location. How can I pull out these values so that I can sort them accordingly? If I could then I would know how to finish my code.

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 1 year ago . Improve this question I dont know is this is possible at all, I´m not even sure how to google it. Im using SQL Server 2014. Right now I have a SP that outputs a table with data including MovementID, Vehicle, VehicleType and Total of sales. But it groups all the vehicles ids and vehicles types with a

问题 I have an array of objects: object1-> name="Name1" key="key1" object2-> name="Name2" key="key2" object3-> name="Name3" key="key3" and an array of priority keys: $keys = ["key3", "key1"]; I need to sort the array of objects based on priority keys, so the result should be: object3: name="Name3" key="key3" object1-> name="Name1" key="key1" object2: name="Name2" key="key2" What is the best way to do it? 回答1: The idea is to add a priority as integer, and sort the array from the highest integer to

问题 The takeOrdered Method from pyspark.RDD gets the N elements from an RDD ordered in ascending order or as specified by the optional key function as described here pyspark.RDD.takeOrdered. The example shows the following code with one key: >>> sc.parallelize([10, 1, 2, 9, 3, 4, 5, 6, 7], 2).takeOrdered(6, key=lambda x: -x) [10, 9, 7, 6, 5, 4] Is it also possible to define more keys e.g. x,y,z for data that has 3 columns? The keys should be in different order such as x= asc, y= desc, z=asc. That

问题 The takeOrdered Method from pyspark.RDD gets the N elements from an RDD ordered in ascending order or as specified by the optional key function as described here pyspark.RDD.takeOrdered. The example shows the following code with one key: >>> sc.parallelize([10, 1, 2, 9, 3, 4, 5, 6, 7], 2).takeOrdered(6, key=lambda x: -x) [10, 9, 7, 6, 5, 4] Is it also possible to define more keys e.g. x,y,z for data that has 3 columns? The keys should be in different order such as x= asc, y= desc, z=asc. That

问题 Based on the following XML, what is the best way to achieve an alphanumeric sort in XSL? Edit : to clarify, the XML below is just a simple sample the real XML would contain much more variant values. <colors> <item> <label>Yellow 100</label> </item> <item> <label>Blue 12</label> </item> <item> <label>Orange 3</label> </item> <item> <label>Yellow 10</label> </item> <item> <label>Orange 26</label> </item> <item> <label>Blue 117</label> </item> </colors> E.g. I want a final outcome in this order:

问题 I'm trying to sort an array that sometimes has Infinity or NaN . When I use a standard JavaScript array.sort() it seems to sort until it reaches a NaN and then I get random results after that. var array =[.02,.2,-.2,Nan,Infinity,20]; Is there a way to still sort this so that the end result is from negative to positive and still have NaN or Infinity at the end. -.2,.02,.2,20,NaN,Infinity 回答1: You can catch NaN and Infinity using JavaScript's built-in utility functions for those cases: let