sorteddictionary

There are many, many threads on ways to get the "first" item from a Dictionary , and various answers as to why such a thing is not really a good idea because there's no internal ordering. But mine's a SortedDictionary , so those arguments don't apply. Yet I cannot find a way to get the Nth item from a SortedDictionary any easier than a Dictionary . Here is my SD: FRs As SortedDictionary(Of DateTime, ScheduleItem) I see a few hints that I should be able to do: If FRs.Count = 1 Then FirstFR = FRs.Keys(0) But that is not valid in my code - it says it has no defaults and cannot be indexed. .First

I made a class that uses a SortedDictionary to store and manipulate data. The class works great except when it is implemented in a multi-threaded environment. Now, I would like to make the class thread safe by writing a wrapper class for the internal SortedDictionary class. I would like to use the Reader-Writer Locks to implement this but for now, I'm having problems just writing the wrapper class itself. Specifically, I'm not sure how to implement the Enumerator for the dictionary. Here is my complete code for the class as it stands now. public class ConcurrentSortedDictionary<TKey, TValue> :

I am having difficulties to use my custom IComparer for my SortedDictionary<>. The goal is to put email addresses in a specific format (firstnam.lastname@domain.com) as the key, and sort by last name. When I do something like this: public class Program { public static void Main(string[] args) { SortedDictionary<string, string> list = new SortedDictionary<string, string>(new SortEmailComparer()); list.Add("a.johansson@domain.com", "value1"); list.Add("b.johansson@domain.com", "value2"); foreach (KeyValuePair<string, string> kvp in list) { Console.WriteLine(kvp.Key); } Console.ReadLine(); } }

I want to convert a dict into sorted dict in python data = pandas.read_csv('D:\myfile.csv') for colname, dtype in data.dtypes.to_dict().iteritems(): if dtype == 'object': print colname count = data[colname].value_counts() d = dict((str(k), int(v)) for k, v in count.iteritems()) f = dict(sorted(d.iteritems(), key=lambda item: item[1], reverse = True)[:5]) print f m ={} m["count"]= int(sum(count)) m["Top 5"]= f print m k = json.dumps(m) print k f = {'Gears of war 3': 6, 'Batman': 5, 'gears of war 3': 4, 'Rocksmith': 5, 'Madden': 3} My desired Output is : f = {'Gears of war 3': 6, 'Batman': 5,

I have dictionary containing key value pairs. SortedDictionary<int,int> dictionary=new SortedDictionary<int,int>(); dictionary.Add(1,33); dictionary.Add(2,20); dictionary.Add(4,35); I want to get previous key value pair from a known key value. In the above case, if I have key 4, then how can I get <2,20> ? It's hard to implement this efficiently with a SortedDictionary<TKey, TValue> since it is implemented as a binary search tree that does not expose predecessors or successors. You could of course just enumerate each KeyValuePair until you find the "known" key. With a little bit of LINQ, this

Is there a built-in sorted dictionary implementation in Python 2.6, or are hashtables the only kind? Clarifications: I'm asking about sorted dictionarys, not ordered dictionaries! James Hurford I think the answer here is no. There is a Treemap but it isn't in the python standard library. http://pypi.python.org/pypi/treemap/ I think to those who don't like my answer, may think it's wrong due to a recent update. Please note this is for Python 2.6, not 2.7 or Python 3 Please add the correct answer if you still think it's wrong, or unhelpful, or at least give a reason why you think it's a bad