sorteddictionary

First item in a SortedDictionary?

情到浓时终转凉″ 提交于 2019-12-20 03:30:06
问题 There are many, many threads on ways to get the "first" item from a Dictionary , and various answers as to why such a thing is not really a good idea because there's no internal ordering. But mine's a SortedDictionary , so those arguments don't apply. Yet I cannot find a way to get the Nth item from a SortedDictionary any easier than a Dictionary . Here is my SD: FRs As SortedDictionary(Of DateTime, ScheduleItem) I see a few hints that I should be able to do: If FRs.Count = 1 Then FirstFR =

How to use custom IComparer for SortedDictionary?

一笑奈何 提交于 2019-12-19 05:23:14
问题 I am having difficulties to use my custom IComparer for my SortedDictionary<>. The goal is to put email addresses in a specific format (firstnam.lastname@domain.com) as the key, and sort by last name. When I do something like this: public class Program { public static void Main(string[] args) { SortedDictionary<string, string> list = new SortedDictionary<string, string>(new SortEmailComparer()); list.Add("a.johansson@domain.com", "value1"); list.Add("b.johansson@domain.com", "value2");

Get last element in a SortedDictionary

泄露秘密 提交于 2019-12-18 15:19:23
问题 I see this question. How can I get the last element in a SortedDictionary in .Net 3.5. 回答1: You can use LINQ: var lastItem = sortedDict.Values.Last(); You can also get the last key: var lastkey = sortedDict.Keys.Last(); You can even get the last key-value pair: var lastKeyValuePair = sortedDict.Last(); This will give you a KeyValuePair<TKey, TValue> with Key and Value properties. Note that this will throw an exception if the dictionary is empty; if you don't want that, call LastOrDefault .

Get last element in a SortedDictionary

╄→гoц情女王★ 提交于 2019-12-18 15:18:21
问题 I see this question. How can I get the last element in a SortedDictionary in .Net 3.5. 回答1: You can use LINQ: var lastItem = sortedDict.Values.Last(); You can also get the last key: var lastkey = sortedDict.Keys.Last(); You can even get the last key-value pair: var lastKeyValuePair = sortedDict.Last(); This will give you a KeyValuePair<TKey, TValue> with Key and Value properties. Note that this will throw an exception if the dictionary is empty; if you don't want that, call LastOrDefault .

Python 2.6 TreeMap/SortedDictionary?

只愿长相守 提交于 2019-12-18 04:32:57
问题 Is there a built-in sorted dictionary implementation in Python 2.6, or are hashtables the only kind? Clarifications: I'm asking about sorted dictionarys, not ordered dictionaries! 回答1: I think the answer here is no. There is a Treemap but it isn't in the python standard library. http://pypi.python.org/pypi/treemap/ I think to those who don't like my answer, may think it's wrong due to a recent update. Please note this is for Python 2.6, not 2.7 or Python 3 Please add the correct answer if you

Is SortedDictionary a red-black tree?

*爱你&永不变心* 提交于 2019-12-18 04:01:07
问题 I saw several quotes about this on the Internet but no official documentation? Can anyone tell me where I can get information about this? 回答1: This isn’t supposed to be documented since it’s an implementation detail . For instance, there is more than one implementation of SortedDictionary : there’s Microsoft’s and there’s the Mono implementation. And the Mono implementation does, in fact, use a red-black tree in its current version (2.10.9). So does the current .NET version (you can find that

What is Ruby (1.8.7) analog to SortedDictionary in C#/.NET?

余生长醉 提交于 2019-12-08 08:45:26
问题 I need to hold values in sorted hash in ruby (1.8.7). What data structed will fit the best? 回答1: There is nothing in the core library or the standard library now, that will fit your bill. There is , however, a feature request to add a Red/Black-Tree implementation to Ruby 1.9.3/2.0. If you are able to force your users to only ever use XRuby or JRuby, you could just use one of the implementations of Java's java.util.SortedMap<K, V> such as java.util.TreeMap<K, V>. If you are able to force your

What is Ruby (1.8.7) analog to SortedDictionary in C#/.NET?

≯℡__Kan透↙ 提交于 2019-12-08 06:27:25
I need to hold values in sorted hash in ruby (1.8.7). What data structed will fit the best? There is nothing in the core library or the standard library now, that will fit your bill. There is , however, a feature request to add a Red/Black-Tree implementation to Ruby 1.9.3/2.0. If you are able to force your users to only ever use XRuby or JRuby , you could just use one of the implementations of Java's java.util.SortedMap<K, V> such as java.util.TreeMap<K, V> . If you are able to force your users to only ever use Ruby.NET or IronRuby , you could just use .NET's System.Collections.Generic

SortedList vs. SortedDictionary vs. Sort()

ぃ、小莉子 提交于 2019-12-02 23:54:55
This is a continuation of questions like this one . Are there any guidelines for tweaking the performance? I don't mean gains in big-O, just saving some linear time. For example, how much does pre-sorting save on either SortedList or SortedDictionary ? Say I have a person-class with 3 properties to sort on, one of them is age in years. Should I bucket the objects on age first? Should I first sort on one property, then use the resulting list/dictionary to sort on two properties and so on? Any other optimizations that spring to mind? Well, it's an easy win on SortedList. Inserting an item

How to find point between two keys in sorted dictionary

醉酒当歌 提交于 2019-12-02 04:06:34
问题 I have a sorted dictionary that contains measured data points as key/value pairs. To determine the value for a non-measured data point I want to extrapolate the value between two known keys using a linear interpolation of their corresponding values. I understand how to calculate the non-measured data point once I have the two key/value pairs it lies between. What I don't know is how to find out which keys it lies between. Is there a more elegant way than a "for" loop (I'm thinking function