signedness

I tried the to execute the below program: #include <stdio.h> int main() { signed char a = -5; unsigned char b = -5; int c = -5; unsigned int d = -5; if (a == b) printf("\r\n char is SAME!!!"); else printf("\r\n char is DIFF!!!"); if (c == d) printf("\r\n int is SAME!!!"); else printf("\r\n int is DIFF!!!"); return 0; } For this program, I am getting the output: char is DIFF!!! int is SAME!!! Why are we getting different outputs for both? Should the output be as below ? char is SAME!!! int is SAME!!! A codepad link . This is because of the various implicit type conversion rules in C. There are