short

问题 This question already has answers here : How to make quick judgement and assignment without isset()? (4 answers) Closed 5 years ago . is there any shorter way for this in PHP? $b = isset($a) ? $a : 'other'; Like in JS $b = $a || 'other'; This does not realy look like a big thing, but when you have a large list of properties/keys to check, this becomes annoing. Thanks in advance :) 回答1: It is only possible if $a is guaranteed to exist. So in your case it would not be possible, because you seem

问题 I was trying to extract some urls from short ones using PHP but I couldn't, does anyone have an idea how can I do this ? basicaly if you have a short link that redirects to a specific link and you want to get that specific link using php and store in a variable how can you do it ? 来源： https://stackoverflow.com/questions/59346472/i-have-short-urls-stored-in-variables-how-can-i-get-the-full-ones-using-php

问题 I was trying to extract some urls from short ones using PHP but I couldn't, does anyone have an idea how can I do this ? basicaly if you have a short link that redirects to a specific link and you want to get that specific link using php and store in a variable how can you do it ? 来源： https://stackoverflow.com/questions/59346472/i-have-short-urls-stored-in-variables-how-can-i-get-the-full-ones-using-php

问题 this is a code to catch all url in the POST and shorting them then insert each of them in row in mysql ..... but here it is inserting all the url in one row ?? so how can i make it catch the first url then insert it in database then go back for the second one and do the same..??? $urlinput=mysql_real_escape_string($_POST['url']); $pattren="/(http:\/\/)[a-zA-Z0-9]*\.[a-z]*(.*)|(www)\.[a-zA-Z0-9]*\.[com]*(.*)/"; preg_match_all( $pattren, $urlinput, $matches ); foreach($matches[0] as $match) {

问题 From the answers I got from this question, it appears that C++ inherited this requirement for conversion of short into int when performing arithmetic operations from C. May I pick your brains as to why this was introduced in C in the first place? Why not just do these operations as short ? For example ( taken from dyp's suggestion in the comments ): short s = 1, t = 2 ; auto x = s + t ; x will have type of int . 回答1: If we look at the Rationale for International Standard—Programming Languages

问题 I have an app which loads and plays music from cloud storage without problems in normal circumstances, except when it comes to Dropbox short links. These links use a 302 header to redirect to an https link:- 302 Found The resource was found at https://www.dropbox.com/s/jhzh3woy3qxblck/05%20-%20Cinema.ogg; you should be redirected automatically. The structure of this code is a double static method, first [chronologically] to look for a redirect and second to get the data to a file. I'm trying

问题 I need to display two single-line TextViews horizontally. The left TextView (let's name it 1) may have a longer text which may shortened and finished with "...". The right text view (2) has a short text and should never get shortened. I want the 1 to remain aligned to the left end of the parent. The 2 aligned to the right side of 1. There are now 2 conditions that I have to meet a) if the 1 has a short text then the 2 should get aligned to the right of 1 (none of the gets shortened). b) but

问题 I want to use the marquee property for short texts. I wrote this code: <TextView android:id="@+id/MarqueeText" android:layout_width="fill_parent" android:layout_height="wrap_content" android:ellipsize="marquee" android:focusable="true" android:focusableInTouchMode="true" android:freezesText="true" android:marqueeRepeatLimit="marquee_forever" android:paddingLeft="15dip" android:paddingRight="15dip" android:scrollHorizontally="true" android:singleLine="true" android:text="Hello" > and it doesn

问题 I have: int a = 2147483647; short b = (short)a; and I get b = -1 whereas I expect int32 to be converted to int16 ( short ). I expect to see some value and not -1 . Please someone help me with this. 回答1: Your int A is larger than the size of short. When you convert A to short, you get a 1 in the left most bit, which is going to indicate that it is a negative number. Since you're getting -1, I suppose you're getting 1s in all 16 bits, which is going to give you -2^15 + 2^14 + 2^13... + 2^0,

问题 I made a little test to manipulate a short and I came across a compilation problem. The following code compile : short s = 1; s += s; while this one doesn't : short s = 1; s = s + s; //Cannot convert from int to short I've read that shorts are automatically promoted to int , but what's the difference between those two codes ? 回答1: You're right that short are promoted to ints . This occurs during the evaluation of the binary operator + , and it's known as binary numeric promotion . However,