set

问题 My application references a database object that acts as a catalog. It's a catalog of items that can be crafted if the user has the necessary components. Here is a small sample of the catalog: const itemCatalog = { "bramble_vest" : { "components" : [ "Chain Vest", "Chain Vest" ], "name" : "Bramble Vest" }, "guardian_angel" : { "components" : [ "B.F. Sword", "Chain Vest" ], "name" : "Guardian Angel" }, "hextech_gunblade" : { "components" : [ "B.F. Sword", "Needlessly Large Rod" ], "name" :

问题 I have an array of components: let components = ["a", "b", "c"]; It is possible to combine those components to make products; i.e., "a" + "b" = "ab" . I have a catalog of possible products: let catalog = ["ab", "ac", "bc"]; Using something like lodash, we can create an array of possible products. Output array would look like ["ab", "ac", "bc"] . But the problem is that not all of those products could be built because once the component for one is used, it is no longer available for use in

问题 I have an array of components: let components = ["a", "b", "c"]; It is possible to combine those components to make products; i.e., "a" + "b" = "ab" . I have a catalog of possible products: let catalog = ["ab", "ac", "bc"]; Using something like lodash, we can create an array of possible products. Output array would look like ["ab", "ac", "bc"] . But the problem is that not all of those products could be built because once the component for one is used, it is no longer available for use in

问题 We have Vector for List, and Hashtable for Map. Similarly do we have any class which has thread safe methods for Set? 回答1: One option: (java8) Set<String> set = ConcurrentHashMap.newKeySet(); which is similar to HashSet, but also safe to use concurrently. 回答2: There are ways to get thread safe sets. some e.g. CopyOnWriteArraySet Collections.synchronizedSet(Set set) etc Check this for more details - Different types of thread-safe Sets in Java 回答3: Vector and Hashtable are relics from before

问题 In a script.sh, source a.sh source b.sh CMD1 CMD2 CMD3 how can I replace the source *.sh with their content (without executing the commands)? I would like to see what the bash interpreter executes after sourcing the files and expanding all variables. I know I can use set -n -v or run bash -n -v script.sh 2>output.sh , but that would not replace the source commands (and even less if a.sh or b.sh contain variables). I thought of using a subshell, but that still doesn't expand the source lines.

问题 In a script.sh, source a.sh source b.sh CMD1 CMD2 CMD3 how can I replace the source *.sh with their content (without executing the commands)? I would like to see what the bash interpreter executes after sourcing the files and expanding all variables. I know I can use set -n -v or run bash -n -v script.sh 2>output.sh , but that would not replace the source commands (and even less if a.sh or b.sh contain variables). I thought of using a subshell, but that still doesn't expand the source lines.

问题 Is it specified that you can delete any element in an instance of Set while iterating using for..of and that you won't iterate more than once on an element you won't miss any other element that was in the set at the start of the iteration other than the ones you remove ? 回答1: Yes , it is perfectly fine to add elements and remove elements to a set while iterating it. This use case was considered and is supported in JavaScript 2015 (ES6). It will leave it in a consistent state. Note this also

问题 Is it specified that you can delete any element in an instance of Set while iterating using for..of and that you won't iterate more than once on an element you won't miss any other element that was in the set at the start of the iteration other than the ones you remove ? 回答1: Yes , it is perfectly fine to add elements and remove elements to a set while iterating it. This use case was considered and is supported in JavaScript 2015 (ES6). It will leave it in a consistent state. Note this also

问题 Is it specified that you can delete any element in an instance of Set while iterating using for..of and that you won't iterate more than once on an element you won't miss any other element that was in the set at the start of the iteration other than the ones you remove ? 回答1: Yes , it is perfectly fine to add elements and remove elements to a set while iterating it. This use case was considered and is supported in JavaScript 2015 (ES6). It will leave it in a consistent state. Note this also

来源： https://stackoverflow.com/questions/64491039/how-to-process-object-with-map-for-csv-output