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问题 (In relation to this question I posed a few days ago) I have a dictionary whose keys are strings, and whose values are sets of integers, for example: db = {"a":{1,2,3}, "b":{5,6,7}, "c":{2,5,4}, "d":{8,11,10,18}, "e":{0,3,2}} I would like to have a procedure that joins the keys whose values satisfy a certain generic condition given in an external function. The new item will therefore have as a key the union of both keys (the order is not important). The value will be determined by the

问题 I have a list like this: mylist[1:3]=[{'Keywords': 'scrum master', 'result': {'categoryId': '3193', 'categoryName': 'agile coach', 'score': '1.0'}, 'categoryId': '3193'}, {'Keywords': 'principal consultant', 'result': {'categoryId': '2655', 'categoryName': 'principal consultant', 'score': '1.045369052886963'}, 'categoryId': '2655'}, {'Keywords': 'technicalfunctional consultant', 'result': []}] I want to run the following code: categories=set(x['result']['categoryName'] for x in mylist) It

问题 For certain purposes, I need to generate an iterable that lists all the partitions of a list, but with a condition on the subsets lenghts. That is, I want to partition my list in subsets of equal lenght (=3 here), except the last one if the lenght of the list isn't a multiple of 3. i.e. ['a','b','c','d','e'] should give all partitions with 2 subsets of lenght 3 and 2. Namely, if I simply use : [p for p in multiset_partitions(['a','b','c','d','e'],2)] Out: [[['a', 'b', 'c', 'd'], ['e']], [['a'

问题 Since the groups of 6 represent dice, the order of the integers in these groups does not matter. The order of the groups within each set does matter, but to check each one it would be simple to find the permutations of each set, which I can do. Now, I've come up with a way to achieve all this, the problem is efficiency. I want to check each set but so far I've only come up with a way using: for i in itertools.combinations(num, 6): W.append([i]) print(W) print("Done building list of ",len(W),"

问题 I thought it was a coincidence at first so I wrote up a test to try it out and it's true, I ran it 1 million times and every single time the set came back ordered and sorted. This only occurs when you use integers from 0-9 as soon as an integer > 9 is inserted then any integers inserted after will not be sorted. Why is this? Also for floats it kind of sorts it but isn't right all the time, so weird I thought they were completely unordered. Any advice on why 0-9 is sorted every time would be

问题 I have a series of texts that are instances of a custom WebText class. Each text is an object that has a rating (-10 to +10) and a word count (nltk.FreqDist) associated with it: >>trainingTexts = [WebText('train1.txt'), WebText('train2.txt'), WebText('train3.txt'), WebText('train4.txt')] >>trainingTexts[1].rating 10 >>trainingTexts[1].freq_dist <FreqDist: 'the': 60, ',': 49, 'to': 38, 'is': 34,...> How can you now get two lists (or dictionaries) containing every word used exclusively in the

问题 The Scenario Let's suppose we have a set of database tables that represent four key concepts: Entity Types (e.g. account, client, etc.) Entities (e.g. instances of the above Entity Types) Cohorts (a named group) Cohort Members (the Entities that form up the membership of a Cohort) The rules around Cohorts are: A Cohort always has at least one Cohort Member. A Cohorts Members must be unique to that Cohort (i.e. Entity 5 cannot be a member of Cohort 3 twice, though it could be a member of

问题 I'm seeing non-deterministic behavior when trying to select a pseudo-random element from sets, even though the RNG is seeded (example code shown below). Why is this happening, and should I expect other Python data types to show similar behavior? Notes: I've only tested this on Python 2.7, but it's been reproducible on two different Windows computers. Similar Issue: The issue at Python random seed not working with Genetic Programming example code may be similar. Based on my testing, my

问题 This question already has answers here : Is there possibility of sum of ArrayList without looping (13 answers) Closed 1 year ago . How would you find the sum of the elements of a set in Java? Would it be the same with an array? In python, I could do: my_set = {1, 2, 3, 4} print(sum(my_set)) 回答1: Aside from using loops explicitly, for List<Integer> list you can do: int sum = list.stream().mapToInt(Integer::intValue).sum(); If it's an int[] ar then do: int sum = IntStream.of(ar).sum(); This is

问题 This question already has answers here : Is there possibility of sum of ArrayList without looping (13 answers) Closed 1 year ago . How would you find the sum of the elements of a set in Java? Would it be the same with an array? In python, I could do: my_set = {1, 2, 3, 4} print(sum(my_set)) 回答1: Aside from using loops explicitly, for List<Integer> list you can do: int sum = list.stream().mapToInt(Integer::intValue).sum(); If it's an int[] ar then do: int sum = IntStream.of(ar).sum(); This is