set

问题 I have list of list that looks like this my_list = [[1, 2, 3, 4], [4, 5, 6, 7], [9, 10, 11, 12]] and I would like to find what's the best way to split the list into two groups so that the individual elements in each group are not overlapping. For instance, in the example above the two groups would be group1 = [[1, 2, 3, 4], [4, 5, 6, 7]] group2 = [[9, 10, 11, 12]] and this is because 9, 10, 11, 12 never appear in any of the items of group1 . 回答1: Similarly to Combine lists with common

问题 To create all possible combinations of two sets of parameters and perform an action on them, you can do: setOf(foo, bar, baz).forEach { a -> setOf(0, 1).forEach { b -> /* use a and b */ } } However, if you have (potentially many) more parameters, this quickly turns into a pyramid of doom: setOf(foo, bar, baz).forEach { a -> setOf(0, 1).forEach { b -> setOf(true, false, null).forEach { c -> setOf("Hello,", "World!").forEach { d -> /* use a, b, c and d */ } } } } You could write this similarly

问题 How does it work? (seq #{3 1 22 44}) And why the order will be like (1 3 44 22) 回答1: Because the set data structure is, by definition, unordered: http://en.wikipedia.org/wiki/Set_(data_structure) To be more precise, Clojure's built-in set (which #{blah blah blah} gives you) is a hash set -- that is, a set backed by a hash table (http://en.wikipedia.org/wiki/Hash_tables). It provides you with the following guarantees: Uniqueness of every element (no duplicates allowed). O(1) performance

问题 I've just been doing some random stuff in Python 3.5. And with 15 minutes of spare time, I came up with this: a = {"a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"} len_a = len(a) list = list(range(0, len_a)) message = "" wordlist = [ch for ch in message] len_wl = len(wordlist) for x in list: print (a[x]) But that satisfying feel of random success did not run over me. Instead, the feeling of failure did: Traceback

问题 I've just been doing some random stuff in Python 3.5. And with 15 minutes of spare time, I came up with this: a = {"a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"} len_a = len(a) list = list(range(0, len_a)) message = "" wordlist = [ch for ch in message] len_wl = len(wordlist) for x in list: print (a[x]) But that satisfying feel of random success did not run over me. Instead, the feeling of failure did: Traceback

问题 Generally, I've been searching for a while and could not find a serious answer. The problem is that I've a QString variable containing certain url, e.g. "C:/Users/Me/Desktop/image.png". How to open it and display the image in my application window? I know the problem might seem trivial, however I can't find a working solution. 回答1: Load the image by using QPixmap and then show it with QLabel : QString url = R"(C:/Users/Me/Desktop/image.png)"; QPixmap img(url); QLabel *label = new QLabel(this)

问题 I'm trying to read some information from a file with ObjectInputStream method. For some reason, the file does not contain the information after the command executed. No error appears. This is my code : public boolean findUser(String user_id) throws Exception { try (ObjectInputStream objectInputStream = new ObjectInputStream(new FileInputStream(fILENAME))){ //System.out.println("Adsfasdf"); System.out.println(objectInputStream); Set<MarkoliaUser> users = (Set<MarkoliaUser>) objectInputStream

问题 Is there a way to copy a TreeSet ? That is, is it possible to go Set <Item> itemList; Set <Item> tempList; tempList = itemList; or do you have to physically iterate through the sets and copy them one by one? 回答1: Another way to do this is to use the copy constructor: Collection<E> oldSet = ... TreeSet<E> newSet = new TreeSet<E>(oldSet); Or create an empty set and add the elements: Collection<E> oldSet = ... TreeSet<E> newSet = new TreeSet<E>(); newSet.addAll(oldSet); Unlike clone these allow

问题 I have some sets of combinations and I want to find out the intersection function between say two of them. Then I want to represent the intersected results in ZDD. I am thinking about using the CUDD package to do this. An example: All the 4-bit strings having hamming distance >= 2 with 1100 = { 0001, 0010, 0011,0101, 0110, 0111, 1001, 1010, 1011 } All the 4-bit strings having hamming distance >= 2 with 0000 = { 0011, 0101, 0110, 1001, 1010, 0111, 1011, 1101, 1110 } Intersected elements of the

问题 I have some sets of combinations and I want to find out the intersection function between say two of them. Then I want to represent the intersected results in ZDD. I am thinking about using the CUDD package to do this. An example: All the 4-bit strings having hamming distance >= 2 with 1100 = { 0001, 0010, 0011,0101, 0110, 0111, 1001, 1010, 1011 } All the 4-bit strings having hamming distance >= 2 with 0000 = { 0011, 0101, 0110, 1001, 1010, 0111, 1011, 1101, 1110 } Intersected elements of the