scramble | 易学教程

How to scramble the words in a sentence - Python

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问题 I have created the following code to scramble the letters in a word (except for the first and last letters), but how would one scramble the letters of the words in a sentence; given the input asks for a sentence instead of a word. Thank you for your time! import random def main(): word = input("Please enter a word: ") print(scramble(word)) def scramble(word): char1 = random.randint(1, len(word)-2) char2 = random.randint(1, len(word)-2) while char1 == char2: char2 = random.randint(1, len(word)

How to scramble the words in a sentence - Python

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How can I scramble a word with a factor?

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问题 I would like to scramble a word with a factor. The bigger the factor is, the more scrambled the word will become. For example, the word "paragraphs" with factor of 1.00 would become "paaprahrgs", and it will become "paargarphs" with a factor of 0.50. The distance from the original letter position and the number of scrambled letters should be taken into consideration. This is my code so far, which only scrambles without a factor: def Scramble(s): return ''.join(random.sample(s, len(s))) Any

How can I scramble a word with a factor?

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The best approach to scramble CSS definitions to a human-unreadable state throughout an ASP.NET application

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问题 I'm not sure if it will bring anything beyond saving on traffic through the removal of long-worded names, but I would definitely want to hide my system of namings, declarations and their organization. The thing is that manual Find&Replace is going to take a very long time, and each slight modification could probably require the process to be redone in part or in whole. Has anyone thought of this problem? Maybe write a macros? Will it be intelligent enough to be able to discover names in a CSS

How to randomize letters correctly from an NSString

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问题 I am creating a word scrambler and I am having issues randomizing the letters. When the letters get randomized, it doesn't make sense. For example, the word PARK shows as AAPA. So, as you can tell it won't make sense for the user when it is time to unscramble. Just so you know, I am using a .plist file to hold the words. This is the code I am using to randomize the letters: _words = [NSMutableArray arrayWithCapacity:scramblelength]; for (int i=0;i<scramblelength;i++) { NSString *letter =

garble function contest

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问题 Remember that away message on aim that said how: Aoccdrnig to a rscheearch at Cmabrigde Uinervtisy, it deosn't mttaer in waht oredr the ltteers in a wrod are, the olny iprmoetnt tihng is taht the frist and lsat ltteer be at the rghit pclae. The rset can be a toatl mses and you can sitll raed it wouthit porbelm. Tihs is bcuseae the huamn mnid deos not raed ervey lteter by istlef, but the wrod as a wlohe. Anyway I'm trying to make a function that would do that to an entire page. There are a few

garble function contest

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Remember that away message on aim that said how: Aoccdrnig to a rscheearch at Cmabrigde Uinervtisy, it deosn't mttaer in waht oredr the ltteers in a wrod are, the olny iprmoetnt tihng is taht the frist and lsat ltteer be at the rghit pclae. The rset can be a toatl mses and you can sitll raed it wouthit porbelm. Tihs is bcuseae the huamn mnid deos not raed ervey lteter by istlef, but the wrod as a wlohe. Anyway I'm trying to make a function that would do that to an entire page. There are a few rules for this function. less then 4 characters leave alone. non-alphanumeric characters don't count

Puzzle Solving: Finding All Words Within a Larger Word in PHP

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So I have a database of words between 3 and 20 characters long. I want to code something in PHP that finds all of the smaller words that are contained within a larger word. For example, in the word "inward" there are the words "rain", "win", "rid", etc. At first I thought about adding a field to the Words tables (Words3 through Words20, denoting the number of letters in the words), something like "LetterCount"... for example, "rally" would be represented as 10000000000200000100000010: 1 instances of the letter A, 0 instances of the letter B, ... 2 instances of the letter L, etc. Then, go

Are there any ways to scramble strings in python?

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I'm writing a program and I need to scramble the letters of string s from a list in python. For instance I have a list of string s like: l = ['foo', 'biology', 'sequence'] And I want something like this: l = ['ofo', 'lbyoogil', 'qceeenus'] What is the best way to do it? Thanks for your help! Python has batteries included.. >>> from random import shuffle >>> def shuffle_word(word): ... word = list(word) ... shuffle(word) ... return ''.join(word) A list comprehension is an easy way to create a new list: >>> L = ['foo', 'biology', 'sequence'] >>> [shuffle_word(word) for word in L] ['ofo',