scientific-notation

问题 I use this code: long elapsedTime = now - lastTime; delta = ((double) elapsedTime) / 1000000000; System.out.println(elapsedTime); System.out.println(delta); This is my output: 173290 1.7329E-4 This output gives me scientific notation, but I don't know what it is. Can you explain me? And why is double printed in scientific notation? 回答1: The output you're seeing is scientific notation. In Java, double is printed as scientific notation if the magnitude is less than 10^-3 or greater than 10^7 .

问题 I want to set the formatting of the y-axis offset in my plot to non-scientific notation, but I can't find a setting to do this. Other questions and their solutions describe how to either remove the offset altogether, or set the y-ticks to scientific/plain notation; I haven't found an answer for setting the notation of the offset itself. I've already tried using these two options, but I think they're meant for the y-ticks, not the offsets: ax.ticklabel_format(axis='y', style='plain', useOffset

问题 if double d = 1.999e-4 I want my output to be 0.0001999. How can I do it? 回答1: NumberFormat formatter = new DecimalFormat("###.#####"); String f = formatter.format(d); You can explore the sub classes of NumberFormat class to know more details. 回答2: You can do it like this: double d = 1.999e-4; NumberFormat nf = NumberFormat.getInstance(); nf.setMinimumFractionDigits(7); System.out.println(nf.format(d)); Check out the documentation of NumberFormat 's methods to format your double as you see

问题 Writing a data frame with a mix of small integer entries (value less than 1000) and "large" ones (value 1000 or more) into csv file with write_csv() mixes scientific and non-scientific entries. If the first 1000 rows are small values but there is a large value thereafter, read_csv() seems to get confused with this mix and outputs NA for scientific notations: test_write_read <- function(small_value, n_fills, position, large_value) { tib <- tibble(a = rep(small_value, n_fills)) tib$a[position]

问题 Writing a data frame with a mix of small integer entries (value less than 1000) and "large" ones (value 1000 or more) into csv file with write_csv() mixes scientific and non-scientific entries. If the first 1000 rows are small values but there is a large value thereafter, read_csv() seems to get confused with this mix and outputs NA for scientific notations: test_write_read <- function(small_value, n_fills, position, large_value) { tib <- tibble(a = rep(small_value, n_fills)) tib$a[position]

问题 I have a column called accountnumber with values similar to 4.11889000e+11 in a pandas dataframe. I want to suppress the scientific notation and convert the values to 4118890000. I have tried the following method and did not work. df = pd.read_csv(data.csv) pd.options.display.float_format = '{:,.3f}'.format Please recommend. 回答1: I assume the exponential notation for the account numbers must come from the data file. If I create a small csv with the full account numbers, pandas will interpret

问题 This question already has answers here : Closed 8 years ago . Possible Duplicate: Suppress exponential formatting in figure ticks Matlab is outputting my axis markers as 5.777 x10^6 for every tick mark in my figures... is it possible to get matlab to output the actual decimal number rather than scientific notation so the tick marks are actually different values rather than all 5.777? Currently I don't really know where in space these plots are because of a lack of precision on the axis. 回答1:

问题 I've got a database filled up with doubles like the following one: 1.60000000000000000000000000000000000e+01 Does anybody know how to convert a number like that to a double in C++? Is there a "standard" way to do this type of things? Or do I have to roll my own function? Right now I'm doing sth like this: #include <string> #include <sstream> int main() { std::string s("1.60000000000000000000000000000000000e+01"); std::istringstream iss(s); double d; iss >> d; d += 10.303030; std::cout << d <<

问题 Hi I want to get numbers from database, for example, if the number in database is 44.7890000000, I would like to get a string 44.789, the same 0.0010000000 -> 0.001, just keep the numbers and trim the tailing '0'. I use this code: qrySth.Fields[i].AsString - it does its job but I find for very small numbers like 0.0000010000 it becomes 1E-6. Is there a way I could disable the scientific notation for this AsString method? Thanks! 回答1: As an alternative to setting the field's DisplayFormat

问题 We have a StreamBuffer class in which we haven't implemented std::fixed operations and I am trying to prevent number showing up in scientific notations. With my below code some numbers are getting shown in scientific notations. We want to avoid doing any allocations so that's why we implemented StreamBuffer class because of performance reason. Below is the code: T value = 0; template<typename U> void process(U& buf, DataOption holder) const { if (holder == DataOption::TYPES) { switch (type_)