sax

NullPointerException in Android RSS app

馋奶兔 提交于 2020-01-15 11:23:10
问题 I'm trying to build an android RSS reader app but I keep getting a Null pointer exception. I'm new to java and can't tell if its the feed url not returning any data or the data not being stored properly. my logcat reads: 08-08 18:44:25.840: E/Trace(621): error opening trace file: No such file or directory (2) 08-08 18:44:25.910: W/ActivityThread(621): Application com.app.fullmetalmanga is waiting for the debugger on port 8100... 08-08 18:44:25.930: I/System.out(621): Sending WAIT chunk 08-08

Better way to parse xml

核能气质少年 提交于 2020-01-12 03:36:12
问题 I've been parsing XML like this for years, and I have to admit when the number of different element becomes larger I find it a bit boring and exhausting to do, here is what I mean, sample dummy XML: <?xml version="1.0"?> <Order> <Date>2003/07/04</Date> <CustomerId>123</CustomerId> <CustomerName>Acme Alpha</CustomerName> <Item> <ItemId> 987</ItemId> <ItemName>Coupler</ItemName> <Quantity>5</Quantity> </Item> <Item> <ItemId>654</ItemId> <ItemName>Connector</ItemName> <Quantity unit="12">3<

XML SAX Parser error: value must not contain the '<' character - pointing to TNS value without '<' character

十年热恋 提交于 2020-01-07 06:15:50
问题 I want to deploy war file into JBOSS6 with the following spring configuration: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.springframework.org/schema/beans" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context" xmlns:jee="http://www.springframework.org/schema/jee" xsi:schemaLocation=" http://www

Not able to retrieve XML tag nested within content of another tag

﹥>﹥吖頭↗ 提交于 2020-01-06 07:10:45
问题 Thanks for reading! Using XML parsing tutorial from here as a reference, I am trying to parse a simple XML RSS feed with the following structure. Everything works fine and all values are parsed except for the following case: I am not able to get the content of the <img> tag. <feed> <title>This is Title</title> <count>10</count> <desc> This is a description for a sample feed <img src="http://someimagelink.com/img.jpg" /> </desc> <link>This is link</link> </feed> This is what the endElement()

running Sax parser

心不动则不痛 提交于 2020-01-06 05:36:12
问题 Am new to using SAX parser .Can anyone tell me how to run it .and what all are required to run it (jdk )..Can i have a sax parser that can parse both android xml and a normal xml 回答1: SAX parsers are implemented by creating a ContentHandler object which implements certain callback functions that correspond to events that happen while parsing an XML document. For example, the startDocument method is called when the parser begins parsing the document, and startElement is called when it

NullPointerException Java SAXParser

淺唱寂寞╮ 提交于 2020-01-05 10:28:57
问题 I am parsing an XML with SAX. I wrote the codes like on tje internet examples that I have seen.I get url and then i parsed this. Here is my codes. public class Urunler implements Serializable { private String title; private String description; public Urunler(String title, String description) { this.title = title; this.description = description; } public Urunler() { } public String getTitle() { return title; } public void setTitle(String title) { this.title = title; } public String

SAX parser and a file from the nework

女生的网名这么多〃 提交于 2020-01-05 08:37:09
问题 Hello fellow developers... just to make sure, I want to ask this question: How does XML SAX parser access the .xml file it is parsing? Does it download the whole file from the given URL? Is there any use in breaking the parsing so that we can save some kilobytes of data? Imagine a large .xml file with ordered items. We need only several items from the top, the other items may already be processed and stored. When I stop the parsing at specific point, will I save some data (surely I will save

SAX parsing through a jar file declares XML document invalid

自古美人都是妖i 提交于 2020-01-05 08:00:50
问题 The picture is self explanatory. When I validate the document using identical process in CMD, the document is declared valid. It is valid when checked manually. The jar file generates this message: Invalid schema_reference.4: Failed to read schema document 'E:/XML and Java/Pro XML Development with Java/schema.xsd', because 1) could not find the document; 2) the document could not be read; 3) the root element of the document is not <xsd:schema>. The question is: WHY? The process of validating

Android: Simple XML SAX Parser - Displays Same Data Over and Over

冷暖自知 提交于 2020-01-05 04:19:05
问题 I've created an XML parser which populates a listView with data obtained from an XML file. The problem is for some reason the listView shows the same data over and over instead of unique data for each listView item. I'm not sure exactly what is causing this issue - any insight is greatly appreciated. Screenshot: XML Data: <response> <cmd>getVideos</cmd> <success>1</success> <NumberOfVideos>4</NumberOfVideos> <Videos> <Video> <VideoName>sample_iPod</VideoName> <VideoDesc/> <VideoUrl> http:/

How do I encode arbitrary data to XML using Java 1.4 and SAX?

半世苍凉 提交于 2020-01-04 05:48:10
问题 We use SAX to parse XML because it does not require the entire XML document to be read into memory in order to parse a single value. I read many articles that insisted SAX can only be used to parse/decode XML and not create it. Is this true? 回答1: No, it isn't true, you can encode XML to any Writer in Java using something similar to: char[] ch; AttributesImpl atts = new AttributesImpl(); Writer writer = new StringWriter(); StreamResult streamResult = new StreamResult(writer);