row

问题 I have a UICollectionView and only one section. Is there a way to set the background color of every row? (in my case it would be a gradient from black to white) 回答1: CollectionViews don't really have a concept of a rows because it's designed to have a flexible layout. Your best option is likely to have the background of the cells have your pattern and remove all the padding/margin between the cells. This will be a problem if the last row isn't full, so if the number needs to be flexible you

问题 I have 2D jagged array. And I want to sort it by any rows. I've searched and found code for sorting by columns private static void Sort<T>(T[][] data, int col) { Comparer<T> comparer = Comparer<T>.Default; Array.Sort<T[]>(data, (x,y) => comparer.Compare(x[col],y[col])); } Can I adapt it for sort by any rows ? Any help is appreciated. Sample of my jagged array (Added) using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication3 { class

问题 Like the title says. I am having trouble. for example I have a 2 column (V1,V2) dataframe with lots of rows, around 300,000. I know that max(df$V2) will give me the max value of that second column. Now that I know my max value, how can I get the entire row associated with that value. Thanks! 回答1: You have to write df[which.max(df$V2), ] If more than one row contains the max: i <- max(df$V2) df[which(df$V2 == i), ] 来源： https://stackoverflow.com/questions/36802736/trying-to-find-row-associated

问题 I have the following 2 3D numpy arrays that I want to concatenate. The arrays look like this: a = np.array([[[1,1,1], [2,2,2], [3,3,3]], [["a","a","a"], ["b","b","b"], ["c","c","c"]]]) b = np.array([[[4,4,4], [5,5,5], [6,6,6], [7,7,7], [8,8,8], [9,9,9]], [["d","d","d"], ["e","e","e"], ["f","f","f"], ["g","g","g"], ["h","h","h"], ["i","i","i"]]]) I want to concatenate the two arrays to become one 3D array like: [[['1' '1' '1'] ['2' '2' '2'] ['3' '3' '3'] ['4' '4' '4'] ['5' '5' '5'] ['6' '6' '6

问题 I'm trying to remove rows from my data frame that contain less than 5 words. e.g. mydf <- as.data.frame(read.xlsx("C:\\data.xlsx", 1, header=TRUE) head(mydf) NO ARTICLE 1 34 The New York Times reports a lot of words here. 2 12 Greenwire reports a lot of words. 3 31 Only three words. 4 2 The Financial Times reports a lot of words. 5 9 Greenwire short. 6 13 The New York Times reports a lot of words again. I want to remove rows with 5 or less words. how can i do that? 回答1: Here are two ways:

问题 I´m using a script to export Products from a shop to one .csv file. Now I need to change the header row to make it work for me. I was searching a long time but didn't get it how to make it work. maybe I'm just to silly for that. Lets say my CSV looks like this: Heading1 Heading2 Heading3 value1 value2 value3 Now I need to open that csv file, change just the Headings, close and save it. 回答1: $f = "file.csv"; $new_heading = "World,Mama,Euro"; $new_heading.="\n"; // read into array $arr = file(

问题 I have a table like below: 12/7/2012 A B 100 12/21/2012 A I 20 12/23/2012 A I 25 12/1/2013 A I 20 12/1/2014 A I 20 I want to get the value in column D where column B is "A" and column C is "I". I used a sumproduct to get the value in column D, but I need to go down 1 row from wherever column B is "A" and column C is "I". This is my formula: =SUMPRODUCT(--(B:B="A"),--(C:C="I"),F:F+1). It should return a value of 85, but it returns a value of 4. 回答1: You could use =SUM((B1:B10="A")*(C1:C10="I")

问题 I have a table like below: 12/7/2012 A B 100 12/21/2012 A I 20 12/23/2012 A I 25 12/1/2013 A I 20 12/1/2014 A I 20 I want to get the value in column D where column B is "A" and column C is "I". I used a sumproduct to get the value in column D, but I need to go down 1 row from wherever column B is "A" and column C is "I". This is my formula: =SUMPRODUCT(--(B:B="A"),--(C:C="I"),F:F+1). It should return a value of 85, but it returns a value of 4. 回答1: You could use =SUM((B1:B10="A")*(C1:C10="I")

问题 A completely basic question - and forgive me if it is a duplicate. set.seed(1) df <- data.frame(id=c('a', 'a', 'b', 'b', 'a'), a=sample(1:10, size=5, replace=T), b=sample(1:10, size=5, replace=T), c=sample(1:10, size=5, replace=T)) Then, > df id a b c 1 a 3 9 3 2 a 4 10 2 3 b 6 7 7 4 b 10 7 4 5 a 3 1 8 To return the column name (a, b or c) with the largest value, and if this is in the id variable take the second highest, I use the below function. FUN <- function(r) { top <- names(r[,c('a', 'b

问题 Im so lost. I have table, model and controller named Navbar. Here I create navbar buttons. I made child table called "type_1". So "navbar" id goes to table "type_1" and its column called "navbar_id". $form_data = array( 'tipas' => $tipas, 'p_id' => $p_id, 'name' => $request->title, 'text' => $request->text, 'img' => $name ); navbar::create($form_data); //created parent row Here navbar button is created. How can I create childs empty row with parent (navbar) id? Should I use models or I can do