reverse

Reverse the order of legend

喜你入骨 提交于 2021-02-17 18:44:39
问题 I use the following code to plot the bar graph. Need to present a legend in reverse order. How can I do it? colorsArr = plt.cm.BuPu(np.linspace(0, 0.5, len(C2))) p = numpy.empty(len(C2), dtype=object) plt.figure(figsize=(11,11)) prevBar = 0 for index in range(len(C2)): plt.bar(ind, C2[index], width, bottom=prevBar, color=colorsArr[index], label=C0[index]) prevBar = prevBar + C2[index] # positions of the x-axis ticks (center of the bars as bar labels) tick_pos = [i+(width/2) for i in ind] plt

Reverse the order of legend

陌路散爱 提交于 2021-02-17 18:43:10
问题 I use the following code to plot the bar graph. Need to present a legend in reverse order. How can I do it? colorsArr = plt.cm.BuPu(np.linspace(0, 0.5, len(C2))) p = numpy.empty(len(C2), dtype=object) plt.figure(figsize=(11,11)) prevBar = 0 for index in range(len(C2)): plt.bar(ind, C2[index], width, bottom=prevBar, color=colorsArr[index], label=C0[index]) prevBar = prevBar + C2[index] # positions of the x-axis ticks (center of the bars as bar labels) tick_pos = [i+(width/2) for i in ind] plt

Reverse the order of legend

纵饮孤独 提交于 2021-02-17 18:43:08
问题 I use the following code to plot the bar graph. Need to present a legend in reverse order. How can I do it? colorsArr = plt.cm.BuPu(np.linspace(0, 0.5, len(C2))) p = numpy.empty(len(C2), dtype=object) plt.figure(figsize=(11,11)) prevBar = 0 for index in range(len(C2)): plt.bar(ind, C2[index], width, bottom=prevBar, color=colorsArr[index], label=C0[index]) prevBar = prevBar + C2[index] # positions of the x-axis ticks (center of the bars as bar labels) tick_pos = [i+(width/2) for i in ind] plt

Keep leading zeros when integer length is unknown

你说的曾经没有我的故事 提交于 2021-02-16 19:22:34
问题 The following program reverses user input. However, for numbers with trailing zeroes, the zeroes are 'ignored' when printing the reversed number. #include<stdio.h> int main(void) { int n, reversedNumber = 0, remainder; printf("Enter an integer: "); scanf("%d", &n); while(n != 0) { remainder = n%10; reversedNumber = reversedNumber*10 + remainder; n /= 10; } printf("Reversed Number = %d\n", reversedNumber); return 0; } Since the integer length of the user input is unknown , how can we print all

Keep leading zeros when integer length is unknown

杀马特。学长 韩版系。学妹 提交于 2021-02-16 19:20:37
问题 The following program reverses user input. However, for numbers with trailing zeroes, the zeroes are 'ignored' when printing the reversed number. #include<stdio.h> int main(void) { int n, reversedNumber = 0, remainder; printf("Enter an integer: "); scanf("%d", &n); while(n != 0) { remainder = n%10; reversedNumber = reversedNumber*10 + remainder; n /= 10; } printf("Reversed Number = %d\n", reversedNumber); return 0; } Since the integer length of the user input is unknown , how can we print all

How to reverse a list of lists in python? [duplicate]

 ̄綄美尐妖づ 提交于 2021-02-16 15:10:44
问题 This question already has answers here : How can I reverse a list in Python? (33 answers) Closed 5 years ago . I was wondering how to reverse a list of lists in python. For example, Original: list = [[1,2,3],[4,5,6],[7,8,9]] Output: new_list = [[7,8,9],[4,5,6],[1,2,3]] Right now, I am trying this: new_list = reversed(list) However, this doesn't seem to work. 回答1: In [24]: L = [[1,2,3],[4,5,6],[7,8,9]] In [25]: L[::-1] Out[25]: [[7, 8, 9], [4, 5, 6], [1, 2, 3]] 来源: https://stackoverflow.com

How to reverse a list of lists in python? [duplicate]

纵然是瞬间 提交于 2021-02-16 15:08:52
问题 This question already has answers here : How can I reverse a list in Python? (33 answers) Closed 5 years ago . I was wondering how to reverse a list of lists in python. For example, Original: list = [[1,2,3],[4,5,6],[7,8,9]] Output: new_list = [[7,8,9],[4,5,6],[1,2,3]] Right now, I am trying this: new_list = reversed(list) However, this doesn't seem to work. 回答1: In [24]: L = [[1,2,3],[4,5,6],[7,8,9]] In [25]: L[::-1] Out[25]: [[7, 8, 9], [4, 5, 6], [1, 2, 3]] 来源: https://stackoverflow.com

How to reverse a list of lists in python? [duplicate]

喜夏-厌秋 提交于 2021-02-16 15:06:33
问题 This question already has answers here : How can I reverse a list in Python? (33 answers) Closed 5 years ago . I was wondering how to reverse a list of lists in python. For example, Original: list = [[1,2,3],[4,5,6],[7,8,9]] Output: new_list = [[7,8,9],[4,5,6],[1,2,3]] Right now, I am trying this: new_list = reversed(list) However, this doesn't seem to work. 回答1: In [24]: L = [[1,2,3],[4,5,6],[7,8,9]] In [25]: L[::-1] Out[25]: [[7, 8, 9], [4, 5, 6], [1, 2, 3]] 来源: https://stackoverflow.com

Reversing words within a string

青春壹個敷衍的年華 提交于 2021-02-11 15:33:07
问题 I am to reverse the words within a string. I feel like I'm headed in the right direction. But I keep getting wonky output and cant help but think it has to do with my strncat() function. Do any of you see any issues with out I've decided to handle it. I'm open to suggestion on other ways to do it. int main() { int ch, ss=0, s=0; char x[3]; char *word, string1[100], string2[100], temp[100]; x[0]='y'; while(x[0]=='y'||x[0]=='Y') { printf("Enter a String: "); fgets(string1, 100, stdin); if

reversing words in a string in c

可紊 提交于 2021-02-11 13:34:25
问题 I have homework assignment: to write a function that reverse a string, and then write a function that reverses words in a string, using the first function. So if the input is: "have a nice day", the output will be: "day nice a have". I cannot understand why my code isn't working - I keep getting segmentation fault. The first function (reverse) works just fine. The problem is with the second one. I really need your help... Thank you in advance. #include <stdio.h> #include <string.h> #include