repeat

问题 This question already has answers here : List of lists changes reflected across sublists unexpectedly (13 answers) Closed 2 years ago . Why couldn't the first element but the whole column be updated below? >>> x=2*[2*[1]] >>> x [[1, 1], [1, 1]] >>> x[0][0]=2 >>> x [[2, 1], [2, 1]] 回答1: Even tho this is a clear duplicate but use range : >>> x=[[1 for i in range(2)] for x in range(2)] >>> x [[1, 1], [1, 1]] >>> x[0][0]=2 >>> x [[2, 1], [1, 1]] >>> At least still able to do: >>> x=[[1]*2 for x

问题 This question already has answers here : List of lists changes reflected across sublists unexpectedly (13 answers) Closed 2 years ago . Why couldn't the first element but the whole column be updated below? >>> x=2*[2*[1]] >>> x [[1, 1], [1, 1]] >>> x[0][0]=2 >>> x [[2, 1], [2, 1]] 回答1: Even tho this is a clear duplicate but use range : >>> x=[[1 for i in range(2)] for x in range(2)] >>> x [[1, 1], [1, 1]] >>> x[0][0]=2 >>> x [[2, 1], [1, 1]] >>> At least still able to do: >>> x=[[1]*2 for x

问题 I am doing an intro class and they are asking me to repeat a function a certain amount of times, as I said this is an intro so most of the code is written so assume the functions have been defined. I have to repeat the tryConfiguration(floorplan,numLights) the amount of time numTries requests. any help would be awesome :D thank you. def runProgram(): #Allow the user to open a floorplan picture (Assume the user will select a valid PNG floodplan) myPlan = pickAFile() floorplan = makePicture

问题 I have a list with repeating values as shown below: x = [1, 1, 1, 2, 2, 2, 1, 1, 1] This list is generated from a pattern matching regular expression (not shown here). The list is guaranteed to have repeating values (many, many repeats - hundreds, if not thousands), and is never randomly arranged because that's what the regex is matching each time. What I want is to track the list indices at which the entries change from the previous value . So for the above list x , I want to obtain a change

问题 I need to detect the presence of multiple blocks of columnar data given only their headings. Nothing else is known about the data except the heading words, which are different for every set of data. Importantly, it is not known before hand how many words are in each block nor, therefore, how many blocks there are. Equally important, the word list is always relatively short - less than 20. So, given a list or array of heading words such as: Opt Object Type Opt Object Type Opt Object Type what

问题 I am looking for the scala way to give all permutations without repetitions. I know there are some postings on this site already but they seem to have a slightly different problem. I am searching for all permutations with repetitions. For example: combine(List('A','C','G')) Should yield: List(List('A'.'A','A'),List('A'.'A','C'),List('A'.'A','G'),List('A'.'C','A'), List('A'.'C',''C), ... List('G'.'G','G') I am sorry if my problem is already solved but I was not able to find it. Thanks in

问题 I am looking for the scala way to give all permutations without repetitions. I know there are some postings on this site already but they seem to have a slightly different problem. I am searching for all permutations with repetitions. For example: combine(List('A','C','G')) Should yield: List(List('A'.'A','A'),List('A'.'A','C'),List('A'.'A','G'),List('A'.'C','A'), List('A'.'C',''C), ... List('G'.'G','G') I am sorry if my problem is already solved but I was not able to find it. Thanks in

问题 I need to find repeated words on a string, and then count how many times they were repeated. So basically, if the input string is this: String s = "House, House, House, Dog, Dog, Dog, Dog"; I need to create a new string list without repetitions and save somewhere else the amount of repetitions for each word, like such: New String: "House, Dog" New Int Array: [3, 4] Is there a way to do this easily with Java? I've managed to separate the string using s.split() but then how do I count

问题 I'm trying to predictably shuffle javascript arrays the same way each time the webpage is loaded. I can shuffle the arrays randomly, but every time i reload the page it's a different sequence. I'd like it to shuffle the arrays the same way every time the page loads. There are many arrays and they are part of a procedurally generated world. 回答1: Chance.js worked perfectly. Thank you Billy Moon. My Example: <script type="text/javascript" src="assets/js/chance.js"></script> var chance1 = new

问题 This question already has answers here : Remove repeating character (3 answers) Closed 4 years ago . What is the regex pattern to determine if a string solely consists of a single repeating character? e.g. "aaaaaaa" = true "aaabbbb" = false "$$$$$$$" = true This question checks if a string only contains repeating characters (e.g. "aabb") however I need to determine if it is a single repeating character. 回答1: You can try with back reference ^(.)\1{1,}$ DEMO Pattern Explanation: ^ the beginning