“人造太阳”计划

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I found a weird difference between explicit and automatic trailing return types. In the following code, we define a struct templated on an integer and an iter function, which take one object of this type as argument. The return type depends on the result of calling itself after decrementing the template value. To break the instantiation loop (or so I thought), I provide a specialization which returns a non-dependent type. We have a toy main to instantiate the templates. Here is a bit of code: template struct Int {}; constexpr auto iter(Int)

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: G'Day. I want to iterate over a bunch of JSON objects and turn them into React Elements. The objects look like this "fields" : [ { key : "testname" , "name" : "testname" , "altName" : "" , "visible" : true , "groupVisibility" : "public" , "type" : "text" , "component" : "input" , "label" : "Test Smart Input" , "placeholder" : "Some default Value" , "required" : "required" , "validated" : false , "data" : [] }, { key : "password" , "name" : "password" , "altName" : "" , "visible" : true , "groupVisibility" : "public" , "type" :

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a JNI function that JAVA calls that needs to build and return a HashMap. The key for the map is 'String' and the respective value is 'boolean' or 'Boolean' (either one is fine, as long as it works). With the current code that I have (below), the string is successfully added to the map that is returned and can be accessed in Java. However, when trying to access the value in JAVA, it comes up null. jclass mapclass = env->FindClass("java/util/HashMap"); jmethodID initmeth = env->GetMethodID(mapclass, "<init>", "()V"); jmethodID putmeth =

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am doing the Rust by Example tutorial which has this code snippet: // Vec example let vec1 = vec![1, 2, 3]; let vec2 = vec![4, 5, 6]; // `iter()` for vecs yields `&i32`. Destructure to `i32`. println!("2 in vec1: {}", vec1.iter() .any(|&x| x == 2)); // `into_iter()` for vecs yields `i32`. No destructuring required. println!("2 in vec2: {}", vec2.into_iter().any(| x| x == 2)); // Array example let array1 = [1, 2, 3]; let array2 = [4, 5, 6]; // `iter()` for arrays yields `&i32`. println!("2 in array1: {}", array1.iter() .any(|&x| x == 2)); /

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have an array: const adjacent: [(i8, i8); 8] = [(-1, -1), (-1, 0), (-1, 1), (-1, 0), (1, 0), (1, 1), (1, 0), (1, -1)]; This array represents all adjacent neighbors of a cell within a ROW x COLUMN grid. To iterate over this array to find all neighbors, I do for k in adjacent.into_iter() { let (i, c) = (k.0, k.1); if let Some(a) = grid.get(r+i, j+c) { /* ... */ } } The second line seems like it could be substituted for K, but this causes an error if you write for (i, c) in adjacency.into_iter() { ... error: type mismatch resolving `<core:

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: There are two types of iterators in Java: fail-safe and fail-fast. What does this mean, and is the difference between them? 回答1: What is the difference between them ... "Fail safe" means: it won't fail. Strictly speaking, there is no such thing in Java as a fail-safe iterator. The correct term is "weakly consistent". The javadoc says: "Most concurrent Collection implementations (including most Queues) also differ from the usual java.util conventions in that their Iterators and Spliterators provide weakly consistent rather than fast-fail

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: C:\Projects\Logs\RTC\MNH\Debug C:\Projects\Logs\FF Is there an expression/string that would say go back until you find "Logs" and open it? (assuming you were always below it) The same executable is run out of "Debug", "MNH" or "FF" at different times, the executable always should save it's log files into "Logs". What expression would get there WITHOUT referring to the entire path C:\Projects\Logs? Thanks. 回答1: It sounds like you're asking about a relative path. If the working directory is C:\Projects\Logs\RTC\MNH\Debug\ , the path ..\..\..

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I am studying Alex Marteli's Python in a Nutshell and the book suggests that any object that has a next() method is (or at least can be used as) an iterator . It also suggests that most iterators are built by implicit or explicit calls to a method called iter . After reading this in the book, I felt the urge to try it. I fired up a python 2.7.3 interpreter and did this: >>> x = [ 0 , 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 ] >>> for number in range ( 0 , 10 ): ... print x . next () However the result was this: Traceback ( most recent

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I want to sort numbers in vector which has odd-index (index starts from 0 ). For example, if I enter this numbers; 1 6 5 7 3 2 0 , program must returns this: 1 2 5 6 3 7 0 . My code #include <iostream> #include <vector> using namespace std; int main() { int eded, n, _temp; size_t i; cout << "Nece eded daxil edeceksiniz?" << endl << ">>> "; cin >> n; vector<int> v_eded; v_eded.reserve(n); // n qeder bosh yer ayiriram vektor-da cout << "Ededleri daxil edin:" << endl; for (int i = 0; i < n; i++) { cin >> eded; v_eded.push_back(eded); } for (i =

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have read my materials, which tell that a python iterator must have both __iter__ and __next__ method, but an iterable just needs __iter__ . I check a list and find it has no __next__ method. When using iter() on it, it will become an iterator. This means that iter() will add a __next__ method to a list to convert it to an iterator? If yes, how does this happen? 回答1: No. iter returns an iterator , it does not convert the list into an iterator. It doesn't modify the list at all, and certainly, the list does not get a __next__ method. >>> x