relationship

rest - relation context

情到浓时终转凉″ 提交于 2019-12-05 12:59:25
Say I have two collection resources: /persons /organizations A GET to /persons/id/ returns a specific person. Likewise, a GET to /organizations/id returns a specific organization. A person can be member of one or more organizations. In this relation context, we have data such as the role of the person in the organization, the date on which the person joined the organization, ... Which of the designs make most sense? A membership resource /memberships/id , to which a GET returns the data of the relation context (together with a link to the person and the organization). A /persons/id

ruby on rails - how to make relationship works in route, controller, view ? has_many, belongs_to

…衆ロ難τιáo~ 提交于 2019-12-05 12:14:39
I am struggling to get my relationship in rails to work. I have a User,Gallery,Comment model class Gallery has_many :comments belongs_to :user end class User has_many :comments has_many :galleries end class Comment belongs_to :gallery belongs_to :user end now what should i do in the routes, controller and views to link this all up ? please help me ? its quite confusing finding out the answers. If can, I dont want it to be nested like in the railscast, but i want for each model, eg gallery i can input user, eg comment i can find and input the galleryid and userid. Im totally lost in oblivion

When to use an attribute (property) instead of an association/aggregation/composition when drawing a UML

二次信任 提交于 2019-12-05 10:30:06
Okay so I'm a bit confused as to when I should add an attribute to a class vs drawing an association to a class when trying to show a relationship in a UML diagram. For example let's say I have a DFA class that contains 10 state objects each having a different set of paths to various states in the DFA. Should I draw the composition line from the DFA to the State class or just type all 10 states in the attribute section of the DFA class. Basically I'm trying to figure out if when a Class A contains (or is composed of) one or more Class Bs, should I draw a line (aggregation, composition

unique pair in a “friendship” database

房东的猫 提交于 2019-12-05 08:05:42
I'm posting this question which is somewhat a summary of my other question . I have two databases : 1) db_users. 2) db_friends. I stress that they're stored in separate databases on different servers and therefore no foreign keys can be used. In 'db_friends' I have the table 'tbl_friends' which has the following columns: - id_user - id_friend Now how do I make sure that each pair is unique at this table ('tbl_friends')? I'd like to enfore that at the table level, and not through a query. For example these are invalid rows : 1 - 2 2 - 1 I'd like this to be impossible to add. Additionally - how

Reload association/related collection in NHibernate

℡╲_俬逩灬. 提交于 2019-12-05 07:30:55
问题 If I have Order entity with a list of OrderDetails I can easily eager load the detail along with the order by using NHibernateUtil.Initialize(Order.Details). So obviously the NHibernate have all the information to generate the sql statement. But how do I query the database for just the Details (similar to CreateSourceQuery in Entity Framework) without manually creating a criteria? Is there something like NHibernateUtil.GetList(Order.Details)? Update: Using Darin's answer this what I finally

Laravel Eloquent - firstOrCreate() on a relationship

女生的网名这么多〃 提交于 2019-12-05 07:12:42
When I try the firstOrCreate() on a relationship of another model, it does not work: Client::find($id)->users()->firstOrCreate(array('email' => $email)); This returns an error saying Call to undefined method Illuminate\Database\Query\Builder::firstOrCreate() Running this directly on the model User will work though. This won't work, you have to do it manually/directly using User model because users() should return a collection object This is correct, the users() function does not return a (new, empty or created) User model, it returns a collection object. It's also documented http://laravel.com

Structuring Relationships in Firebase

孤人 提交于 2019-12-05 07:12:35
I've got two items in my Firebase: providers and services , and I'm trying to figure out the best way to structure and build relationships using Firebase's recommended flattened architecture approach. My data looks something like this: { "services" : { "hip_replacement" : { "title" : "Hip Replacement" } }, "providers" : { "the_blue_hospital" : { "title" : "The Blue Hospital" } } } I would like to link these two items together so that if you were to visit the Hip Replacement page, The Blue Hospital would show up underneath it, if you were to visit The Blue Hospital page, Hip Replacement would

What is local and remote side?

旧城冷巷雨未停 提交于 2019-12-05 02:37:37
The questions below are related to database table relationships and the abstractions which SQLAlchemy provides for it. What is the difference between remote and local side? If there is remote_side then why not a local_side ? In the example given here how is parent_id " local " side? remote_side takes in a list so what are the elements of that list supposed to be? And if their are more then one elements then what exactly does that signify? I have read the docs several time but fail to understand the basic concept behind it and how to use it appropriately. (Almost) All I know is that it is

Neo4j Match Node Property OR Relationship Property

人走茶凉 提交于 2019-12-04 19:58:56
I'm trying to write a query that will return nodes that either match a node property or a relationship property. For instance, I want all nodes where the name property is George OR if the relationship property status is "good". I have two queries that will get the nodes for each of these: MATCH (n) where n.name = 'George' return n MATCH (n)-[r]-() where r.status = 'good' return n Is there a singe query I could write to get these combined results? I thought I could use this optional query (below), but I seemed to have misunderstood the optional match clause because I'm only getting nodes from

Rails 3 friendship model : how to ignore a friend request?

早过忘川 提交于 2019-12-04 19:22:04
I have the traditional friendship model: The user model has: has_many :friendships, :dependent => :destroy has_many :friends, :through => :friendships, :dependent => :destroy has_many :inverse_friendships, :class_name => "Friendship", :foreign_key => "friend_id", :dependent => :destroy has_many :inverse_friends, :through => :inverse_friendships, :source => :user, :dependent => :destroy I would like to define the status "friend" only if a friend request has been sent, and accepted by the other user. Everything works fine except that I did not manage to process the "ignore friend request" part.