recursion

Usage of std::swap() inside move assignment should cause endless recursion (and causes), but it is an example from Stroustrup's book

徘徊边缘 提交于 2020-07-14 07:09:08
问题 I'm trying to get the deep knowledge about how should I write my copy and move constructors and assignment operators. In Bjarne Stroustrup's "The C++ Programming Language - 2013" I see the following example of move constructor and move assignment: template<class T, class A> vector_base<T,A>::vector_base(vector_base&& a) : alloc{a.alloc}, elem{a.elem}, space{a.space}, last{a.space} { a.elem = a.space = a.last = nullptr; // no longer owns any memory } template<class T, class A> vector_base<T,A>

Usage of std::swap() inside move assignment should cause endless recursion (and causes), but it is an example from Stroustrup's book

妖精的绣舞 提交于 2020-07-14 07:09:00
问题 I'm trying to get the deep knowledge about how should I write my copy and move constructors and assignment operators. In Bjarne Stroustrup's "The C++ Programming Language - 2013" I see the following example of move constructor and move assignment: template<class T, class A> vector_base<T,A>::vector_base(vector_base&& a) : alloc{a.alloc}, elem{a.elem}, space{a.space}, last{a.space} { a.elem = a.space = a.last = nullptr; // no longer owns any memory } template<class T, class A> vector_base<T,A>

Python Array Rotation

别等时光非礼了梦想. 提交于 2020-07-14 01:19:47
问题 So I am implementing a block swap algorithm in python. The algorithm I am following is this: Initialize A = arr[0..d-1] and B = arr[d..n-1] 1) Do following until size of A is equal to size of B a) If A is shorter, divide B into Bl and Br such that Br is of same length as A. Swap A and Br to change ABlBr into BrBlA. Now A is at its final place, so recur on pieces of B. b) If A is longer, divide A into Al and Ar such that Al is of same length as B Swap Al and B to change AlArB into BArAl. Now B

Python Array Rotation

独自空忆成欢 提交于 2020-07-14 01:15:08
问题 So I am implementing a block swap algorithm in python. The algorithm I am following is this: Initialize A = arr[0..d-1] and B = arr[d..n-1] 1) Do following until size of A is equal to size of B a) If A is shorter, divide B into Bl and Br such that Br is of same length as A. Swap A and Br to change ABlBr into BrBlA. Now A is at its final place, so recur on pieces of B. b) If A is longer, divide A into Al and Ar such that Al is of same length as B Swap Al and B to change AlArB into BArAl. Now B

Python - Pull random numbers from a list. Populate a new list with a specified length and sum

ⅰ亾dé卋堺 提交于 2020-07-10 09:24:25
问题 I am trying to create a function where: The output list is generated from random numbers from the input list The output list is a specified length and adds to a specified sum ex. I specify that I want a list that is 4 in length and adds up to 10. random numbers are pulled from the input list until the criteria is satisfied. I feel like I am approaching this problem all wrong trying to use recursion. Any help will be greatly appreciated!!! EDIT: for more context on this problem.... Its going

Python - Pull random numbers from a list. Populate a new list with a specified length and sum

↘锁芯ラ 提交于 2020-07-10 09:20:22
问题 I am trying to create a function where: The output list is generated from random numbers from the input list The output list is a specified length and adds to a specified sum ex. I specify that I want a list that is 4 in length and adds up to 10. random numbers are pulled from the input list until the criteria is satisfied. I feel like I am approaching this problem all wrong trying to use recursion. Any help will be greatly appreciated!!! EDIT: for more context on this problem.... Its going

Iterative Solution to End-Overlapping Indices

◇◆丶佛笑我妖孽 提交于 2020-07-09 11:50:33
问题 The bounty expires in 5 days . Answers to this question are eligible for a +50 reputation bounty. Luke Poeppel is looking for an answer from a reputable source . I have a list that holds tuples that represent ranges of numbers. My goal is to return all (see the note below; really looking for the longest) possible subsets of this collection that overlap only by the second value in each tuple or not at all. The function I have been using is a recursive solution to this problem. def get_all_end

How do I return from a recursive generator function in JavaScript?

a 夏天 提交于 2020-07-06 11:54:29
问题 I'm playing around with a recursive generator function that returns values asynchronously. I'm using a coroutine wrapper function to call it. Code and JSBin below: http://jsbin.com/nuyovay/edit?js,console let log = console.log.bind(console); let err = console.error.bind(console); function coroutine(generatorFn){ return function co() { let generator = generatorFn.apply(this, arguments); function handle(result) { console.log(result); if (result.done) { return Promise.resolve(result.value); }

Tree Structure from Adjacency List

好久不见. 提交于 2020-07-04 06:28:05
问题 I am trying to generate a hierarchical tree object from a flat array with parent IDs. // `parent` represents an ID and not the nesting level. var flat = [ { id: 1, name: "Business", parent: 0 }, { id: 2, name: "Management", parent: 1 }, { id: 3, name: "Leadership", parent: 2 }, { id: 4, name: "Finance", parent: 1 }, { id: 5, name: "Fiction", parent: 0 }, { id: 6, name: "Accounting", parent: 1 }, { id: 7, name: "Project Management", parent: 2 } ]; The final tree object should look as follows:

data.table | faster row-wise recursive update within group

你。 提交于 2020-07-04 05:42:43
问题 I have to do the following recursive row-by-row operation to obtain z : myfun = function (xb, a, b) { z = NULL for (t in 1:length(xb)) { if (t >= 2) { a[t] = b[t-1] + xb[t] } z[t] = rnorm(1, mean = a[t]) b[t] = a[t] + z[t] } return(z) } set.seed(1) n_smpl = 1e6 ni = 5 id = rep(1:n_smpl, each = ni) smpl = data.table(id) smpl[, time := 1:.N, by = id] a_init = 1; b_init = 1 smpl[, ':=' (a = a_init, b = b_init)] smpl[, xb := (1:.N)*id, by = id] smpl[, z := myfun(xb, a, b), by = id] I would like