recurrence

问题 I have edited only one event in a recurrence series. While I send a get request with delta token I will get the seriesmaster content, and the edited occurence with type exception My question is how do I patch these kind of events.what is the attribute to add the exception date 回答1: In order to create an exception, you would need to modify (via PATCH) the instance you want to become the exception. If you do: GET /me/events/{event-id-of-master}/instances?startDateTime={start}&endDateTime={end}

问题 I need to Find the solution of the recurrence for n, a power of two if T(n)=3T(n/2)+n for n>1 and T(n)=1 otherwise. using substitution of n=2^m,S(m)=T(2^(m-1)) I can get down to: S(m)=2^m+3*2^(m-1)+3^2*2^(m-2)+⋯+3^(m-1) 2^1+3^m But I have no idea how to simply that. 回答1: These types of recurrences are most easily solved by Master Theorem for analysis of algorithms which is explained as follows: Let a be an integer greater than or equal to 1, b be a real number greater than 1, and c be a

问题 I want to find out the time complexity of the program using recurrence equations. That is .. int f(int x) { if(x<1) return 1; else return f(x-1)+g(x); } int g(int x) { if(x<2) return 1; else return f(x-1)+g(x/2); } I write its recurrence equation and tried to solve it but it keep on getting complex T(n) =T(n-1)+g(n)+c =T(n-2)+g(n-1)+g(n)+c+c =T(n-3)+g(n-2)+g(n-1)+g(n)+c+c+c =T(n-4)+g(n-3)+g(n-2)+g(n-1)+g(n)+c+c+c+c ………………………. …………………….. Kth time ….. =kc+g(n)+g(n-1)+g(n-3)+g(n-4).. .. . … +T(n

问题 I am in a Data Structures and Algorithms class. I am trying to indicate if f(n) is Big Theta of g(n). I will also have to indicate Big O, small o, etc... but I am lost about the way to approach this particular pair. f(n) = log* (log n) g(n) = log( log* n ) From what I have currently learned, if this pair completes this statement Θ(g(n))={f(n):there exists c_1, c_2 > 0 and n_0 <br> such that 0 ≤ c_1 g(n) ≤ f(n) ≤ c_2 g(n) for all n ≥ n_0}. My problem is that I have no idea what log * is and

问题 I am trying to find the big O bound for the following recurrence relation: T(n) = T(n-1) + n^c, where c >= 1 is a constant So I've decided to solve this by using iteration: T(n) = T(n-1) + n^c T(n-1) = T(n-2) + (n-1)^c T(n) = T(n-2) + n^c + (n-1)^c T(n-2) = T(n-3) + (n-2)^c T(n) = T(n-3) + n^c + (n-1)^c + (n-2)^c T(n) = T(n-k) + n^c + (n-1)^c + .... + (n-k+1)^c Suppose k = n-1, then: T(n) = T(1) + n^c + (n-1)^c + (n-n+1+1)^c T(n) = n^c + (n-1)^c + 2^c + 1 I'm not sure if this is correct

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed last year . I am trying to find the time complexity for the recurrence: T(n) = 2T(n 1/2 ) + log n I am pretty close to the solution, however, I have run into a roadblock. I need to solve: n (1/2 k ) = 1 for k to simplify my substitution pattern. I am not looking for answers to the recurrence, just a solution for k . 回答1: When

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed last year . I am trying to find the time complexity for the recurrence: T(n) = 2T(n 1/2 ) + log n I am pretty close to the solution, however, I have run into a roadblock. I need to solve: n (1/2 k ) = 1 for k to simplify my substitution pattern. I am not looking for answers to the recurrence, just a solution for k . 回答1: When

问题 I really need your help, Let's say my demarcation start date is: December 19, 2016 as defined by the variable x How can I write a JavaScript function, such that it will check the present date against x and the present date against what the recurrence date will be (14) days from x as defined by the variable y . var y = recurrence is every 14 days, thereafter from the date (x) with no end date specified (unlimited) Ex. function() { if (present date == x) { alert(true) } if (present date == y) {

问题 formally, say, we have 2 sacks with capacities c1 and c2. There are N items with profits pi and weights wi. As in 0-1 Knapsack problem, we need to fill in c1 and c2 with these items in such a way the overall profit is maximized. Assume pi and wi are positive integers! For the 2 knapsack problem does below recurrence relation hold good? DP[I][J][K] is maximum profit we could achieve from the first i items such that the weight of exactly j was used in knapsack #1 and a weight of exactly k was

问题 I recently stumbled upon a resource where the 2T(n/2) + n/log n type of recurrences were declared unsolvable by MM. I accepted it as a lemma, until today, when another resource proved to be a contradiction (in some sense). As per the resource (link below): Q7 and Q18 in it are the rec. 1 and 2 respectively in the question whereby, the answer to Q7 says it can't be solved by giving the reason 'Polynomial difference b/w f(n) and n^(log a base b)'. On the contrary, answer 18 solves the second