range

问题 I'm learning Kotlin, but I can't seem to find straight answers to simple questions. I presume that it's so new, no one has had a chance to ask the obvious questions yet. So here it goes. When I want to get the smallest item in a range, I type: range.start But I get the warning, "Could be replaced with unboxed first ". Not sure what unboxed means--can't even guess. But when I use this command: range.first the warning goes away. What's happening here? Should I even be concerned? Why does Kotlin

问题 I'm learning Kotlin, but I can't seem to find straight answers to simple questions. I presume that it's so new, no one has had a chance to ask the obvious questions yet. So here it goes. When I want to get the smallest item in a range, I type: range.start But I get the warning, "Could be replaced with unboxed first ". Not sure what unboxed means--can't even guess. But when I use this command: range.first the warning goes away. What's happening here? Should I even be concerned? Why does Kotlin

问题 Unless I'm mistaken, a range can only include unique numbers. So, a number could be in it or not. I guess only if we want to pass a range as one of many accepted types (dynamic) to some function would it make sense. However, it seems like if it would go over the whole range to count a number it would be very inefficient. I tried to time it compared to " in ", but on my machine it seems they have the same timing. Can that be right? 回答1: Because range() objects conform to the Sequence ABC, and

问题 Unless I'm mistaken, a range can only include unique numbers. So, a number could be in it or not. I guess only if we want to pass a range as one of many accepted types (dynamic) to some function would it make sense. However, it seems like if it would go over the whole range to count a number it would be very inefficient. I tried to time it compared to " in ", but on my machine it seems they have the same timing. Can that be right? 回答1: Because range() objects conform to the Sequence ABC, and

问题 Unless I'm mistaken, a range can only include unique numbers. So, a number could be in it or not. I guess only if we want to pass a range as one of many accepted types (dynamic) to some function would it make sense. However, it seems like if it would go over the whole range to count a number it would be very inefficient. I tried to time it compared to " in ", but on my machine it seems they have the same timing. Can that be right? 回答1: Because range() objects conform to the Sequence ABC, and

问题 Unless I'm mistaken, a range can only include unique numbers. So, a number could be in it or not. I guess only if we want to pass a range as one of many accepted types (dynamic) to some function would it make sense. However, it seems like if it would go over the whole range to count a number it would be very inefficient. I tried to time it compared to " in ", but on my machine it seems they have the same timing. Can that be right? 回答1: Because range() objects conform to the Sequence ABC, and

来源： https://stackoverflow.com/questions/5920839/vector-subscript-out-of-range

来源： https://stackoverflow.com/questions/53321158/why-is-the-swift-compiler-marking-this-as-an-error

来源： https://stackoverflow.com/questions/53321158/why-is-the-swift-compiler-marking-this-as-an-error

来源： https://stackoverflow.com/questions/53321158/why-is-the-swift-compiler-marking-this-as-an-error