random

Random number: 0 or 1

十年热恋 提交于 2021-02-07 11:15:26
问题 Am I looking too far to see something as simple as pick a number: 0 or 1? Random rand = new Random(); if (rand.NextDouble() == 0) { lnkEvents.CssClass = "selected"; } else { lnkNews.CssClass = "selected"; } 回答1: Random rand = new Random(); if (rand.Next(0, 2) == 0) lnkEvents.CssClass = "selected"; else lnkNews.CssClass = "selected"; Random.Next picks a random integer between the lower bound (inclusive) and the upper bound (exclusive). 回答2: If you want 50/50 probability, I suggest: Random rand

Random number: 0 or 1

假如想象 提交于 2021-02-07 11:15:21
问题 Am I looking too far to see something as simple as pick a number: 0 or 1? Random rand = new Random(); if (rand.NextDouble() == 0) { lnkEvents.CssClass = "selected"; } else { lnkNews.CssClass = "selected"; } 回答1: Random rand = new Random(); if (rand.Next(0, 2) == 0) lnkEvents.CssClass = "selected"; else lnkNews.CssClass = "selected"; Random.Next picks a random integer between the lower bound (inclusive) and the upper bound (exclusive). 回答2: If you want 50/50 probability, I suggest: Random rand

Setting up a Discrete Distribution in C++

大兔子大兔子 提交于 2021-02-07 09:53:42
问题 After hours of struggling with this issue, I cannot find any explanations for my error. I want the computer to pick a random number (weighted) between 0 and 120 (inclusive). I have an array, interval[], which holds the numbers from 0 to 120 (inclusive). I have another array, weights[], which holds the probabilities for choosing the ith element in the array. I want to define a probability distribution function for these data. Here is what I tried. I get an error saying that no instance of

How to set rand() result to values in a certain range including negatives?

别说谁变了你拦得住时间么 提交于 2021-02-07 09:24:55
问题 I am trying to dynamically allocate an array of doubles and set each element to a random value within a range of positive or negative numbers, but I am having difficulty. Right now, I can only figure out how to set numbers 0 - max. Here is what I have so far: double *random_arr(int size, double min, double max) { double *array0 = calloc(size, sizeof(double)); if (array0 == NULL) { exit(1); } for (int i = 0; i < size; i++) array0[i] = (max * rand() / RAND_MAX); return array0; } My best guess:

How to set rand() result to values in a certain range including negatives?

可紊 提交于 2021-02-07 09:23:19
问题 I am trying to dynamically allocate an array of doubles and set each element to a random value within a range of positive or negative numbers, but I am having difficulty. Right now, I can only figure out how to set numbers 0 - max. Here is what I have so far: double *random_arr(int size, double min, double max) { double *array0 = calloc(size, sizeof(double)); if (array0 == NULL) { exit(1); } for (int i = 0; i < size; i++) array0[i] = (max * rand() / RAND_MAX); return array0; } My best guess:

Is std::random_device cryptographic secure?

牧云@^-^@ 提交于 2021-02-07 05:36:14
问题 I see many people talk about security and std::random_device together. For example, here slide 22. According to cppreference, std::random_device : std::random_device is a uniformly-distributed integer random number generator that produces non-deterministic random numbers. It does not talk about security explicitly. Is there any valid reference that explicitly mentions std::random_device is secure for cryptography? 回答1: No, because that's not what std::random_device is designed for; it's

math.random always give 0 result

ぐ巨炮叔叔 提交于 2021-02-05 12:38:47
问题 I am using Ubuntu 14.04.3 LTS and I am studying Java from the book. I tried to follow one example on the book with Ubuntu Terminal and I'm using Sublime Text. Here is the code import java.util.Scanner; public class RepeatAdditionQuiz{ public static void main(String[] args){ int number1 = (int)(Math.random()%10); int number2 = (int)(Math.random()%10); Scanner input = new Scanner(System.in); System.out.print( "What is "+number1+" + "+number2+"?"); int answer = input.nextInt(); while(number1

math.random always give 0 result

ε祈祈猫儿з 提交于 2021-02-05 12:35:13
问题 I am using Ubuntu 14.04.3 LTS and I am studying Java from the book. I tried to follow one example on the book with Ubuntu Terminal and I'm using Sublime Text. Here is the code import java.util.Scanner; public class RepeatAdditionQuiz{ public static void main(String[] args){ int number1 = (int)(Math.random()%10); int number2 = (int)(Math.random()%10); Scanner input = new Scanner(System.in); System.out.print( "What is "+number1+" + "+number2+"?"); int answer = input.nextInt(); while(number1

Scramble each digit of the int a and print out the biggest possible integer

你离开我真会死。 提交于 2021-02-05 12:34:52
问题 I’m stuck here. Do I just keep making new strings and turn them to int or us there a faster better way? public void biggest(int a){ int random; String aS = String.valueOf(a); int ah=9; if (a<10) System.out.println(a); for(int i= 0;i<aS.length();i++){ String firstNum = aS.substring(i,i+1); for (int j = ah; j > Integer.parseInt(firstNum); j--){ System.out.println(ah); } } } ``` 回答1: There's no need to use conversion to String in this case, you can get the digits from the input number by getting

Scramble each digit of the int a and print out the biggest possible integer

给你一囗甜甜゛ 提交于 2021-02-05 12:34:30
问题 I’m stuck here. Do I just keep making new strings and turn them to int or us there a faster better way? public void biggest(int a){ int random; String aS = String.valueOf(a); int ah=9; if (a<10) System.out.println(a); for(int i= 0;i<aS.length();i++){ String firstNum = aS.substring(i,i+1); for (int j = ah; j > Integer.parseInt(firstNum); j--){ System.out.println(ah); } } } ``` 回答1: There's no need to use conversion to String in this case, you can get the digits from the input number by getting