random

问题 I'm pretty sure that this will never be an issue. However, I'm still curious, exactly how many iterations can any given seed generate a random number before its scope is fully exhausted and it wraps back around to generating the same numbers again? As an example: Suppose you have an array consisting of eight integer indices; during a given iteration the random.Next would fill each indice with a value of 0-31. And the test is attempting to see how long it would take to generate a perfect array

问题 I have a function that im trying to produce random numbers between 18 and 5 int randomAge() { int random; std::random_device rd; static std::default_random_engine generator(rd()); //produce a static random engine std::normal_distribution<double> distribution(18, 52); //random age between 18 and 52 random = distribution(generator); return random; } However I am recieving negative numbers and even numbers that are higher than 52. How can I fix this so it produces numbers between 18 and 52? 回答1:

问题 I have a function that im trying to produce random numbers between 18 and 5 int randomAge() { int random; std::random_device rd; static std::default_random_engine generator(rd()); //produce a static random engine std::normal_distribution<double> distribution(18, 52); //random age between 18 and 52 random = distribution(generator); return random; } However I am recieving negative numbers and even numbers that are higher than 52. How can I fix this so it produces numbers between 18 and 52? 回答1:

问题 I am trying to generate 12 characters alphanumeric string in julia with the following snippets: a) an = randstring(rand(Bool) ? ('A':'Z') : ('0':'9'), 12) b) an = "" for i in [1:12] an *= randstring(rand(Bool) ? ('A':'Z') : ('0':'9')) end but both gives either complete 12 digits or 12 alphabets but not of their combination. please guide me in generating combination of 12 alphanumeric string. 回答1: If you don't mind using both upper and lower case letters, you can simply call randstring(12) :

问题 I am trying to generate 12 characters alphanumeric string in julia with the following snippets: a) an = randstring(rand(Bool) ? ('A':'Z') : ('0':'9'), 12) b) an = "" for i in [1:12] an *= randstring(rand(Bool) ? ('A':'Z') : ('0':'9')) end but both gives either complete 12 digits or 12 alphabets but not of their combination. please guide me in generating combination of 12 alphanumeric string. 回答1: If you don't mind using both upper and lower case letters, you can simply call randstring(12) :

问题 I am trying to generate 12 characters alphanumeric string in julia with the following snippets: a) an = randstring(rand(Bool) ? ('A':'Z') : ('0':'9'), 12) b) an = "" for i in [1:12] an *= randstring(rand(Bool) ? ('A':'Z') : ('0':'9')) end but both gives either complete 12 digits or 12 alphabets but not of their combination. please guide me in generating combination of 12 alphanumeric string. 回答1: If you don't mind using both upper and lower case letters, you can simply call randstring(12) :

问题 Looking to create a randomly generated alphabet for a substitution cipher. My idea was something like this. char randomChar = (char) (97 + r.nextInt(25)); However this will cause repetition of letters. Going through the char array and seeing if the letter is already present seems inefficient also. edit: I was too vague in my request and see this now. Here is the full question I am trying to solve. The alphabet must also contain the space button character e.g ' '. Write a Java program which

问题 Looking to create a randomly generated alphabet for a substitution cipher. My idea was something like this. char randomChar = (char) (97 + r.nextInt(25)); However this will cause repetition of letters. Going through the char array and seeing if the letter is already present seems inefficient also. edit: I was too vague in my request and see this now. Here is the full question I am trying to solve. The alphabet must also contain the space button character e.g ' '. Write a Java program which

问题 Looking to create a randomly generated alphabet for a substitution cipher. My idea was something like this. char randomChar = (char) (97 + r.nextInt(25)); However this will cause repetition of letters. Going through the char array and seeing if the letter is already present seems inefficient also. edit: I was too vague in my request and see this now. Here is the full question I am trying to solve. The alphabet must also contain the space button character e.g ' '. Write a Java program which

问题 I'm coding an arithmetic game where the user is asked a series of addition questions. I want to however randomly assign an operator for each question so that the question could be either: Question 1: num1 + num2 = or Question 2: num1 - num2 = I have been using the Math.random() method to randomise num1 and num2 the last thing I am struggling on is randomly generating '+' and '-'. Is it something to do with the ASCII values of these two characters and then I can randomly pick between them?