quantifiers

CUDD: Quantification of ZDDs

回眸只為那壹抹淺笑 提交于 2021-01-23 05:09:03
问题 I'm working with CUDD (https://github.com/ivmai/cudd) to use bdd and zdd functionality for model checking, and am wondering how i can quantify over zdds. For bdds there are the functions bddExistAbstract and bddUnivAbstract (see http://web.mit.edu/sage/export/tmp/y/usr/share/doc/polybori/cudd/cuddAllDet.html#Cudd_bddUnivAbstract). The manual says that the functions universally and existentially abstracts out the given variables from the bdd (in cover form). I dont quite know what they mean

CUDD: Quantification of ZDDs

南笙酒味 提交于 2021-01-23 05:04:26
问题 I'm working with CUDD (https://github.com/ivmai/cudd) to use bdd and zdd functionality for model checking, and am wondering how i can quantify over zdds. For bdds there are the functions bddExistAbstract and bddUnivAbstract (see http://web.mit.edu/sage/export/tmp/y/usr/share/doc/polybori/cudd/cuddAllDet.html#Cudd_bddUnivAbstract). The manual says that the functions universally and existentially abstracts out the given variables from the bdd (in cover form). I dont quite know what they mean

CUDD: Quantification of ZDDs

我怕爱的太早我们不能终老 提交于 2021-01-23 05:04:24
问题 I'm working with CUDD (https://github.com/ivmai/cudd) to use bdd and zdd functionality for model checking, and am wondering how i can quantify over zdds. For bdds there are the functions bddExistAbstract and bddUnivAbstract (see http://web.mit.edu/sage/export/tmp/y/usr/share/doc/polybori/cudd/cuddAllDet.html#Cudd_bddUnivAbstract). The manual says that the functions universally and existentially abstracts out the given variables from the bdd (in cover form). I dont quite know what they mean

Why isn't the “X, at MOST n times” regex quantifier included in Java, in the “X{,n}” syntax? [closed]

我的梦境 提交于 2020-02-26 04:18:07
问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 5 years ago . Java docs tell us you can have this greedy quantifiers: X{n} X, exactly n times X{n,} X, at least n times X{n,m} X, at least n but not more than m times There is no mention of having X, at MOST n times . So I made a little test: boolean atMost = Pattern.matches("X{,3}", "XX")

Why isn't the “X, at MOST n times” regex quantifier included in Java, in the “X{,n}” syntax? [closed]

允我心安 提交于 2020-02-26 04:17:11
问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 5 years ago . Java docs tell us you can have this greedy quantifiers: X{n} X, exactly n times X{n,} X, at least n times X{n,m} X, at least n but not more than m times There is no mention of having X, at MOST n times . So I made a little test: boolean atMost = Pattern.matches("X{,3}", "XX")

Regex expressions in Java, \\s vs. \\s+

﹥>﹥吖頭↗ 提交于 2020-01-28 13:02:43
问题 What's the difference between the following two expressions? x = x.replaceAll("\\s", ""); x = x.replaceAll("\\s+", ""); 回答1: The first one matches a single whitespace, whereas the second one matches one or many whitespaces. They're the so-called regular expression quantifiers, and they perform matches like this (taken from the documentation): Greedy quantifiers X? X, once or not at all X* X, zero or more times X+ X, one or more times X{n} X, exactly n times X{n,} X, at least n times X{n,m} X,

Universal qauntification hypothesis in Coq

[亡魂溺海] 提交于 2020-01-07 04:37:46
问题 I want to change the hypothesis H from the form below mL : Map mR : Map H : forall (k : RecType) (e : String.string), MapsTo k e (filter (is_vis_cookie l) mL) <-> MapsTo k e (filter (is_vis_cookie l) mR) ------------------------------------------------------- Goal to mL : Map mR : Map k : RecType e : String.string H : MapsTo k e (filter (is_vis_cookie l) mL) <-> MapsTo k e (filter (is_vis_cookie l) mR) ------------------------------------------------------- Goal I think, they can both solve

Universal qauntification hypothesis in Coq

南笙酒味 提交于 2020-01-07 04:37:01
问题 I want to change the hypothesis H from the form below mL : Map mR : Map H : forall (k : RecType) (e : String.string), MapsTo k e (filter (is_vis_cookie l) mL) <-> MapsTo k e (filter (is_vis_cookie l) mR) ------------------------------------------------------- Goal to mL : Map mR : Map k : RecType e : String.string H : MapsTo k e (filter (is_vis_cookie l) mL) <-> MapsTo k e (filter (is_vis_cookie l) mR) ------------------------------------------------------- Goal I think, they can both solve

Why is my regex capture group only capturing the last part of the string when it matches multiple parts?

北慕城南 提交于 2020-01-03 18:57:08
问题 What I Tried var test = "asdfdas ABCD EFGH"; var regex = /^\S+( [A-Z]{4})+$/; // Also tried: /^\S+( [A-Z]{4})+$/g // And: /^\S+( [A-Z]{4})+?$/g var matches = test.match(regex); I made a JSFiddle. What I Expect The variable matches should become this array: [ "asdfdas ABCD EFGH", " ABCD", " EFGH" ] What I Get The variable matches is actually this array: [ "asdfdas ABCD EFGH", " EFGH" ] My Thoughts My guess is that there's something I'm missing with the capture group and/or $ logic. Any help